我正在用 PHP 构建一个 REST Web 服务客户端,目前我正在使用 curl 向服务发出请求。
如何使用 curl 发出经过身份验证的(http 基本)请求?我必须自己添加标题吗?
你要这个:
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
Zend 有一个 REST 客户端和 zend_http_client,我确信 PEAR 有某种包装器。但它很容易自己做。
所以整个请求可能看起来像这样:
$ch = curl_init($host);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/xml', $additionalHeaders));
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $payloadName);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$return = curl_exec($ch);
curl_close($ch);
CURLOPT_USERPWD
基本上发送带有 http 标头的 user:password
字符串的 base64,如下所示:
Authorization: Basic dXNlcjpwYXNzd29yZA==
因此,除了 CURLOPT_USERPWD
之外,您还可以将 HTTP-Request
标头选项与其他标头一起使用,如下所示:
$headers = array(
'Content-Type:application/json',
'Authorization: Basic '. base64_encode("user:password") // <---
);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
CURLOPT_USERPWD
的方法对我有用。
直接使用 CURL 的最简单和原生的方式。
这对我有用:
<?php
$login = 'login';
$password = 'password';
$url = 'http://your.url';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_USERPWD, "$login:$password");
$result = curl_exec($ch);
curl_close($ch);
echo($result);
您只需要指定 CURLOPT_HTTPAUTH 和 CURLOPT_USERPWD 选项:
$curlHandler = curl_init();
$userName = 'postman';
$password = 'password';
curl_setopt_array($curlHandler, [
CURLOPT_URL => 'https://postman-echo.com/basic-auth',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPAUTH => CURLAUTH_BASIC,
CURLOPT_USERPWD => $userName . ':' . $password,
]);
$response = curl_exec($curlHandler);
curl_close($curlHandler);
或指定标题:
$curlSecondHandler = curl_init();
curl_setopt_array($curlSecondHandler, [
CURLOPT_URL => 'https://postman-echo.com/basic-auth',
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => [
'Authorization: Basic ' . base64_encode($userName . ':' . $password)
],
]);
$response = curl_exec($curlSecondHandler);
curl_close($curlSecondHandler);
贪吃例子:
use GuzzleHttp\Client;
use GuzzleHttp\RequestOptions;
$userName = 'postman';
$password = 'password';
$httpClient = new Client();
$response = $httpClient->get(
'https://postman-echo.com/basic-auth',
[
RequestOptions::AUTH => [$userName, $password]
]
);
print_r($response->getBody()->getContents());
请参阅https://github.com/andriichuk/php-curl-cookbook#basic-auth
基本方法的其他方法是:
$curl = curl_init();
$public_key = "public_key";
$private_key = "private_key";
curl_setopt_array($curl, array(
CURLOPT_URL => "https://url.endpoint.co/login",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 0,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_HTTPHEADER => array(
"Content-Type: application/json",
"Authorization: Basic ".base64_encode($public_key.":".$private_key)
),
));
$response = curl_exec($curl);
curl_close($curl);
echo $response;
与 SOAP 不同,REST 不是标准化协议,因此拥有“REST 客户端”有点困难。但是,由于大多数 RESTful 服务使用 HTTP 作为其底层协议,因此您应该能够使用任何 HTTP 库。除了 cURL,PHP 还通过 PEAR 提供了这些:
取代
他们如何进行 HTTP 基本身份验证的示例
// This will set credentials for basic auth
$request = new HTTP_Request2('http://user:password@www.example.com/secret/');
还支持 Digest Auth
// This will set credentials for Digest auth
$request->setAuth('user', 'password', HTTP_Request2::AUTH_DIGEST);
如果授权类型是 Basic auth 并且发布的数据是 json 那么这样做
<?php
$data = array("username" => "test"); // data u want to post
$data_string = json_encode($data);
$api_key = "your_api_key";
$password = "xxxxxx";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://xxxxxxxxxxxxxxxxxxxxxxx");
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 20);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERPWD, $api_key.':'.$password);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Accept: application/json',
'Content-Type: application/json')
);
if(curl_exec($ch) === false)
{
echo 'Curl error: ' . curl_error($ch);
}
$errors = curl_error($ch);
$result = curl_exec($ch);
$returnCode = (int)curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
echo $returnCode;
var_dump($errors);
print_r(json_decode($result, true));
对于那些不想使用 curl 的人:
//url
$url = 'some_url';
//Credentials
$client_id = "";
$client_pass= "";
//HTTP options
$opts = array('http' =>
array(
'method' => 'POST',
'header' => array ('Content-type: application/json', 'Authorization: Basic '.base64_encode("$client_id:$client_pass")),
'content' => "some_content"
)
);
//Do request
$context = stream_context_create($opts);
$json = file_get_contents($url, false, $context);
$result = json_decode($json, true);
if(json_last_error() != JSON_ERROR_NONE){
return null;
}
print_r($result);
雅虎有一个使用 PHP 调用他们的 REST 服务的教程:
Make Yahoo! Web Service REST Calls with PHP
我自己没有使用过它,但雅虎就是雅虎,至少应该保证一定程度的质量。不过,它们似乎没有涵盖 PUT 和 DELETE 请求。
此外,User Contributed Notes to curl_exec() 和其他包含很多有用的信息。
Michael Dowling 非常积极地维护的 Guzzle 是一个不错的方法。除了优雅的界面、异步调用和 PSR 合规性之外,它还使 REST 调用的身份验证标头变得非常简单:
// Create a client with a base URL
$client = new GuzzleHttp\Client(['base_url' => 'http://myservices.io']);
// Send a request to http://myservices.io/status with basic authentication
$response = $client->get('/status', ['auth' => ['username', 'password']]);
请参阅the docs。