How can I pad an integer with zeros on the left?

Use java.lang.String.format(String,Object...) like this:

String.format("%05d", yournumber);

for zero-padding with a length of 5. For hexadecimal output replace the d with an x as in "%05x".

The full formatting options are documented as part of java.util.Formatter.

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Let's say you want to print 11 as 011

You could use a formatter: "%03d".

https://i.stack.imgur.com/u4vid.png

You can use this formatter like this:

int a = 11;
String with3digits = String.format("%03d", a);
System.out.println(with3digits);

Alternatively, some java methods directly support these formatters:

System.out.printf("%03d", a);

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If you for any reason use pre 1.5 Java then may try with Apache Commons Lang method

org.apache.commons.lang.StringUtils.leftPad(String str, int size, '0')

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Found this example... Will test...

import java.text.DecimalFormat;
class TestingAndQualityAssuranceDepartment
{
    public static void main(String [] args)
    {
        int x=1;
        DecimalFormat df = new DecimalFormat("00");
        System.out.println(df.format(x));
    }
}

Tested this and:

String.format("%05d",number);

Both work, for my purposes I think String.Format is better and more succinct.

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Try this one:

import java.text.DecimalFormat; 

DecimalFormat df = new DecimalFormat("0000");

String c = df.format(9);   // Output: 0009

String a = df.format(99);  // Output: 0099

String b = df.format(999); // Output: 0999

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If performance is important in your case you could do it yourself with less overhead compared to the String.format function:

/**
 * @param in The integer value
 * @param fill The number of digits to fill
 * @return The given value left padded with the given number of digits
 */
public static String lPadZero(int in, int fill){

    boolean negative = false;
    int value, len = 0;

    if(in >= 0){
        value = in;
    } else {
        negative = true;
        value = - in;
        in = - in;
        len ++;
    }

    if(value == 0){
        len = 1;
    } else{         
        for(; value != 0; len ++){
            value /= 10;
        }
    }

    StringBuilder sb = new StringBuilder();

    if(negative){
        sb.append('-');
    }

    for(int i = fill; i > len; i--){
        sb.append('0');
    }

    sb.append(in);

    return sb.toString();       
}

Performance

public static void main(String[] args) {
    Random rdm;
    long start; 

    // Using own function
    rdm = new Random(0);
    start = System.nanoTime();

    for(int i = 10000000; i != 0; i--){
        lPadZero(rdm.nextInt(20000) - 10000, 4);
    }
    System.out.println("Own function: " + ((System.nanoTime() - start) / 1000000) + "ms");

    // Using String.format
    rdm = new Random(0);        
    start = System.nanoTime();

    for(int i = 10000000; i != 0; i--){
        String.format("%04d", rdm.nextInt(20000) - 10000);
    }
    System.out.println("String.format: " + ((System.nanoTime() - start) / 1000000) + "ms");
}

Result

Own function: 1697ms

String.format: 38134ms

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You can use Google Guava:

Maven:

<dependency>
     <artifactId>guava</artifactId>
     <groupId>com.google.guava</groupId>
     <version>14.0.1</version>
</dependency>

Sample code:

String paddedString1 = Strings.padStart("7", 3, '0'); //"007"
String paddedString2 = Strings.padStart("2020", 3, '0'); //"2020"

Note:

Guava is very useful library, it also provides lots of features which related to Collections, Caches, Functional idioms, Concurrency, Strings, Primitives, Ranges, IO, Hashing, EventBus, etc

Ref: GuavaExplained

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Here is how you can format your string without using DecimalFormat.

String.format("%02d", 9)

09

String.format("%03d", 19)

019

String.format("%04d", 119)

0119

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Although many of the above approaches are good, but sometimes we need to format integers as well as floats. We can use this, particularly when we need to pad particular number of zeroes on left as well as right of decimal numbers.

import java.text.NumberFormat;  
public class NumberFormatMain {  

public static void main(String[] args) {  
    int intNumber = 25;  
    float floatNumber = 25.546f;  
    NumberFormat format=NumberFormat.getInstance();  
    format.setMaximumIntegerDigits(6);  
    format.setMaximumFractionDigits(6);  
    format.setMinimumFractionDigits(6);  
    format.setMinimumIntegerDigits(6);  

    System.out.println("Formatted Integer : "+format.format(intNumber).replace(",",""));  
    System.out.println("Formatted Float   : "+format.format(floatNumber).replace(",",""));  
 }    
}  

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int x = 1;
System.out.format("%05d",x);

if you want to print the formatted text directly onto the screen.

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You need to use a Formatter, following code uses NumberFormat

    int inputNo = 1;
    NumberFormat nf = NumberFormat.getInstance();
    nf.setMaximumIntegerDigits(4);
    nf.setMinimumIntegerDigits(4);
    nf.setGroupingUsed(false);

    System.out.println("Formatted Integer : " + nf.format(inputNo));

Output: 0001

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Use the class DecimalFormat, like so:

NumberFormat formatter = new DecimalFormat("0000"); //i use 4 Zero but you can also another number
System.out.println("OUTPUT : "+formatter.format(811)); 

OUTPUT : 0000811

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You can add leading 0 to your string like this. Define a string that will be the maximum length of the string that you want. In my case i need a string that will be only 9 char long.

String d = "602939";
d = "000000000".substring(0, (9-d.length())) + d;
System.out.println(d);

Output : 000602939

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Check my code that will work for integer and String.

Assume our first number is 2. And we want to add zeros to that so the the length of final string will be 4. For that you can use following code

    int number=2;
    int requiredLengthAfterPadding=4;
    String resultString=Integer.toString(number);
    int inputStringLengh=resultString.length();
    int diff=requiredLengthAfterPadding-inputStringLengh;
    if(inputStringLengh<requiredLengthAfterPadding)
    {
        resultString=new String(new char[diff]).replace("\0", "0")+number;
    }        
    System.out.println(resultString);

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Use this simple extension function

fun Int.padZero(): String {
    return if (this < 10) {
        "0$this"
    } else {
        this.toString()
    }
}

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For Kotlin

fun Calendar.getFullDate(): String {
    val mYear = "${this.get(Calendar.YEAR)}-"
    val mMonth = if (this.get(Calendar.MONTH) + 1 < 10) {
        "0${this.get(Calendar.MONTH) + 1}-"
    } else {
        "${this.get(Calendar.MONTH)+ 1}-"
    }
    val mDate = if (this.get(Calendar.DAY_OF_MONTH)  < 10) {
        "0${this.get(Calendar.DAY_OF_MONTH)}"
    } else {
        "${this.get(Calendar.DAY_OF_MONTH)}"
    }
    return mYear + mMonth + mDate
}

and use it as

val date: String = calendar.getFullDate()

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Here is another way to pad an integer with zeros on the left. You can increase the number of zeros as per your convenience. Have added a check to return the same value as is in case of negative number or a value greater than or equals to zeros configured. You can further modify as per your requirement.

/**
 * 
 * @author Dinesh.Lomte
 *
 */
public class AddLeadingZerosToNum {
    
    /**
     * 
     * @param args
     */
    public static void main(String[] args) {
        
        System.out.println(getLeadingZerosToNum(0));
        System.out.println(getLeadingZerosToNum(7));
        System.out.println(getLeadingZerosToNum(13));
        System.out.println(getLeadingZerosToNum(713));
        System.out.println(getLeadingZerosToNum(7013));
        System.out.println(getLeadingZerosToNum(9999));
    }
    /**
     * 
     * @param num
     * @return
     */
    private static String getLeadingZerosToNum(int num) {
        // Initializing the string of zeros with required size
        String zeros = new String("0000");
        // Validating if num value is less then zero or if the length of number 
        // is greater then zeros configured to return the num value as is
        if (num < 0 || String.valueOf(num).length() >= zeros.length()) {
            return String.valueOf(num);
        }
        // Returning zeros in case if value is zero.
        if (num == 0) {
            return zeros;
        }
        return new StringBuilder(zeros.substring(0, zeros.length() - 
                String.valueOf(num).length())).append(
                        String.valueOf(num)).toString();
    }
}

Input

0

7

13

713

7013

9999

Output

0000

0007

0013

7013

9999

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No packages needed:

String paddedString = i < 100 ? i < 10 ? "00" + i : "0" + i : "" + i;

This will pad the string to three characters, and it is easy to add a part more for four or five. I know this is not the perfect solution in any way (especially if you want a large padded string), but I like it.

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