Round double in two decimal places in C#?

This works:

inputValue = Math.Round(inputValue, 2);

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Math.Round(inputValue, 2, MidpointRounding.AwayFromZero)

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Another easy way is to use ToString with a parameter. Example:

float d = 54.9700F;    
string s = d.ToString("N2");
Console.WriteLine(s);

Result:

54.97

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You should use

inputvalue=Math.Round(inputValue, 2, MidpointRounding.AwayFromZero)

Math.Round

Math.Round rounds a double-precision floating-point value to a specified number of fractional digits.

MidpointRounding

Specifies how mathematical rounding methods should process a number that is midway between two numbers.

Basically the function above will take your inputvalue and round it to 2 (or whichever number you specify) decimal places. With MidpointRounding.AwayFromZero when a number is halfway between two others, it is rounded toward the nearest number that is away from zero. There is also another option you can use that rounds towards the nearest even number.

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Use Math.Round

value = Math.Round(48.485, 2);

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you can try one from below.there are many way for this.

1. 
 value=Math.Round(123.4567, 2, MidpointRounding.AwayFromZero) //"123.46"
2.
 inputvalue=Math.Round(123.4567, 2)  //"123.46"
3. 
 String.Format("{0:0.00}", 123.4567);      // "123.46"
4. 
string.Format("{0:F2}", 123.456789);     //123.46
string.Format("{0:F3}", 123.456789);     //123.457
string.Format("{0:F4}", 123.456789);     //123.4568

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Use an interpolated string, this generates a rounded up string:

var strlen = 6;
$"{48.485:F2}"

Output

"48.49"

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I think all these answers are missing the question. The problem was to "Round UP", not just "Round". It is my understanding that Round Up means that ANY fractional value about a whole digit rounds up to the next WHOLE digit. ie: 48.0000000 = 48 but 25.00001 = 26. Is this not the definition of rounding up? (or have my past 60 years in accounting been misplaced?

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