Given a path such as "mydir/myfile.txt"
, how do I find the file's absolute path in Python? E.g. on Windows, I might end up with:
"C:/example/cwd/mydir/myfile.txt"
>>> import os
>>> os.path.abspath("mydir/myfile.txt")
'C:/example/cwd/mydir/myfile.txt'
Also works if it is already an absolute path:
>>> import os
>>> os.path.abspath("C:/example/cwd/mydir/myfile.txt")
'C:/example/cwd/mydir/myfile.txt'
You could use the new Python 3.4 library pathlib
. (You can also get it for Python 2.6 or 2.7 using pip install pathlib
.) The authors wrote: "The aim of this library is to provide a simple hierarchy of classes to handle filesystem paths and the common operations users do over them."
To get an absolute path in Windows:
>>> from pathlib import Path
>>> p = Path("pythonw.exe").resolve()
>>> p
WindowsPath('C:/Python27/pythonw.exe')
>>> str(p)
'C:\\Python27\\pythonw.exe'
Or on UNIX:
>>> from pathlib import Path
>>> p = Path("python3.4").resolve()
>>> p
PosixPath('/opt/python3/bin/python3.4')
>>> str(p)
'/opt/python3/bin/python3.4'
Docs are here: https://docs.python.org/3/library/pathlib.html
os.path.abspath()
gave me an error: AttributeError: 'NoneType' object has no attribute 'startswith'
, using Path().resolve()
does not with the same relative filepath. (Linux and Python3.4)
resolve()
returns full path to you only if it is able to resolve()
file. But, os.path.abspath
returns full path to you anyway even the file does not exists. However, in linux, it always return absolute path
Path(__file__)
alone (without the resolve method) is used in a module being imported along with a package, gives the absolute path instead of the relative path?
resolve()
will follow symlinks. If you don't want this, use absolute()
instead, which will leave not resolve symlinks.
import os
os.path.abspath(os.path.expanduser(os.path.expandvars(PathNameString)))
Note that expanduser
is necessary (on Unix) in case the given expression for the file (or directory) name and location may contain a leading ~/
(the tilde refers to the user's home directory), and expandvars
takes care of any other environment variables (like $HOME
).
Install a third-party path module (found on PyPI
), it wraps all the os.path
functions and other related functions into methods on an object that can be used wherever strings are used:
>>> from path import path
>>> path('mydir/myfile.txt').abspath()
'C:\\example\\cwd\\mydir\\myfile.txt'
pathlib
. See my answer in this thread.
from path import Path
then Path('mydir/myfile.txt').abspath()
path
module. The linked module uses a class named path
.
Update for Python 3.4+ pathlib
that actually answers the question:
from pathlib import Path
relative = Path("mydir/myfile.txt")
absolute = relative.absolute() # absolute is a Path object
If you only need a temporary string, keep in mind that you can use Path
objects with all the relevant functions in os.path
, including of course abspath
:
from os.path import abspath
absolute = abspath(relative) # absolute is a str object
Today you can also use the unipath
package which was based on path.py
: http://sluggo.scrapping.cc/python/unipath/
>>> from unipath import Path
>>> absolute_path = Path('mydir/myfile.txt').absolute()
Path('C:\\example\\cwd\\mydir\\myfile.txt')
>>> str(absolute_path)
C:\\example\\cwd\\mydir\\myfile.txt
>>>
I would recommend using this package as it offers a clean interface to common os.path utilities.
This always gets the right filename of the current script, even when it is called from within another script. It is especially useful when using subprocess
.
import sys,os
filename = sys.argv[0]
from there, you can get the script's full path with:
>>> os.path.abspath(filename)
'/foo/bar/script.py'
It also makes easier to navigate folders by just appending /..
as many times as you want to go 'up' in the directories' hierarchy.
To get the cwd:
>>> os.path.abspath(filename+"/..")
'/foo/bar'
For the parent path:
>>> os.path.abspath(filename+"/../..")
'/foo'
By combining "/.."
with other filenames, you can access any file in the system.
You can use this to get absolute path of a specific file.
from pathlib import Path
fpath = Path('myfile.txt').absolute()
print(fpath)
if you are on a mac
import os
upload_folder = os.path.abspath("static/img/users")
this will give you a full path:
print(upload_folder)
will show the following path:
>>>/Users/myUsername/PycharmProjects/OBS/static/img/user
Given a path such as mydir/myfile.txt, how do I find the file's absolute path relative to the current working directory in Python?
I would do it like this,
import os.path
os.path.join( os.getcwd(), 'mydir/myfile.txt' )
That returns '/home/ecarroll/mydir/myfile.txt'
In case someone is using python and linux and looking for full path to file:
>>> path=os.popen("readlink -f file").read()
>>> print path
abs/path/to/file
Success story sharing
normpath()
as follows:normpath(join(os.getcwd(), path))
. So ifmydir/myfile.txt
do not underos.getcwd()
, the absolute path is not the real path.mydir/myfile.txt
implicitly refers to a path inside the current working directory as is therefore equivalent to./mydir/myfile.txt
. That might not be the path you intended to input, but it seems like the correct interpretation of the path as far as I can tell. Could you elaborate?abspath
function and a real file. You could give any pathname- non-existent files and directory heirarchies are fine- and abspath will simply resolve the bits of the path (including the parent directory "..
" element) and return a string. This is just a string computed from the current directory; any correlation to an actual file is accidental, it seems. Tryos.path.abspath("/wow/junk/../blha/hooey")
. It works.os.path.exists
. To the contrary, systems like PowerShell that insist on the path existing with the standard path resolution function are a pain to use.relpath
: "the filesystem is not accessed to confirm the existence or nature ofpath
". If the argument here is obvious, why be explicit forrelpath
?