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Get line number while using grep

I am using grep recursive to search files for a string, and all the matched files and the lines containing that string are print on the terminal. But is it possible to get the line numbers of those lines too??

ex: presently what I get is /var/www/file.php: $options = "this.target", but what I am trying to get is /var/www/file.php: 1142 $options = "this.target";, well where 1142 would be the line number containing that string.

Syntax I am using to grep recursively is sudo grep -r 'pattern' '/var/www/file.php'

One more question is, how do we get results for not equal to a pattern. Like all the files but not the ones having a certain string?

The -v flag will show lines that do not match ( grep -v myText MyFile.txt )

D
Dominykas Mostauskis
grep -n SEARCHTERM file1 file2 ...

I had another quick question, how do we get results for not equal to a pattern. Like all the files but not the ones having a certain string?
that would be command line switch -v. If you run 'grep --help' it will display all options
You don't need -r if you specify multiple files. You only need -r if you specify directories.
@JeanPaul - I see same result for both -nr and -n -r. What version of grep are you using ? $ grep -n -r name * | wc -l 1984 $ grep -nr name * | wc -l 1984 $ grep -V grep (BSD grep) 2.5.1-FreeBSD
Code only answer, no explanation. :S
c
carlito

Line numbers are printed with grep -n:

grep -n pattern file.txt

To get only the line number (without the matching line), one may use cut:

grep -n pattern file.txt | cut -d : -f 1

Lines not containing a pattern are printed with grep -v:

grep -v pattern file.txt

And last matching line number: grep -n pattern file.txt | cut -d : -f 1 | tail -1 (you can save this to a variable and use it to e.g tail file from it)
And to remove the number/colon at the beginning of each string you can use something like: grep -n pattern file.txt | sed 's/^[0-9][0-9]*://'
q
quotesBro

If you want only the line number do this:

grep -n Pattern file.ext | gawk '{print $1}' FS=":"

Example:

$ grep -n 9780545460262 EXT20130410.txt | gawk '{print $1}' FS=":" 
48793
52285
54023

awk -F: '{print $1}' also works & you don't need -r in grep when used on files (only directories can be searched recursively)
How to separate awk '{print $1}' FS=":" results and save them in a variable for future manipulations?
f
fedorqui
grep -A20 -B20 pattern file.txt

Search pattern and show 20 lines after and before pattern


This is not at all what was asked for.
Also, -C20 is a shorter version if that's what was wanted
Lets face it tough - it's an excelent answer for many of us, who google in here while sifting through log files :)
@JonathonReinhart That may not have been exactly what the OP asked for, but I found it quite useful, and I would encourage folks who answer this type of question to continue adding that sort of tidbit.
g
gorkem

grep -nr "search string" directory

This gives you the line with the line number.


F
Fouad Djebbar

In order to display the results with the line numbers, you might try this

grep -nr "word to search for" /path/to/file/file 

The result should be something like this:

linenumber: other data "word to search for" other data

P
Porsche9II

When working with vim you can place

function grepn() {
    grep -n $@ /dev/null | awk -F $':' '{t = $1; $1 = $2; $2 = t; print; }' OFS=$':' | sed 's/^/vim +/' | sed '/:/s// /' | sed '/:/s// : /'
}

in your .bashrc and then

grepn SEARCHTERM file1 file2 ...

results in

vim +123 file1 : xxxxxxSEARCHTERMxxxxxxxxxx
vim +234 file2 : xxxxxxSEARCHTERMxxxxxxxxxx

Now, you can open vim on the correspondending line (for example line 123) by simply copying vim +123 file1 to your shell.