I have a bunch of elements with a class name red
, but I can't seem to select the first element with the class="red"
using the following CSS rule:
.home .red:first-child { border: 1px solid red; }
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What is wrong in this selector and how do I correct it to target the first child with class red
?
This is one of the most well-known examples of authors misunderstanding how :first-child
works. Introduced in CSS2, the :first-child
pseudo-class represents the very first child of its parent. That's it. There's a very common misconception that it picks up whichever child element is the first to match the conditions specified by the rest of the compound selector. Due to the way selectors work (see here for an explanation), that is simply not true.
Selectors level 3 introduces a :first-of-type
pseudo-class, which represents the first element among siblings of its element type. This answer explains, with illustrations, the difference between :first-child
and :first-of-type
. However, as with :first-child
, it does not look at any other conditions or attributes. In HTML, the element type is represented by the tag name. In the question, that type is p
.
Unfortunately, there is no similar :first-of-class
pseudo-class for matching the first child element of a given class. At the time this answer was first posted, the newly published FPWD of Selectors level 4 introduced an :nth-match()
pseudo-class, designed around existing selector mechanics as I mentioned in the first paragraph by adding a selector-list argument, through which you can supply the rest of the compound selector to get the desired filtering behavior. In recent years this functionality was subsumed into :nth-child()
itself, with the selector list appearing as an optional second argument, to simplify things as well as averting the false impression that :nth-match()
matched across the entire document (see the final note below).
While we await cross-browser support (seriously, it's been nearly 10 years, and there has only been a single implementation for the last 5 of those years), one workaround that Lea Verou and I developed independently (she did it first!) is to first apply your desired styles to all your elements with that class:
/*
* Select all .red children of .home, including the first one,
* and give them a border.
*/
.home > .red {
border: 1px solid red;
}
... then "undo" the styles for elements with the class that come after the first one, using the general sibling combinator ~
in an overriding rule:
/*
* Select all but the first .red child of .home,
* and remove the border from the previous rule.
*/
.home > .red ~ .red {
border: none;
}
Now only the first element with class="red"
will have a border.
Here's an illustration of how the rules are applied:
.home > .red { border: 1px solid red; } .home > .red ~ .red { border: none; }
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No rules are applied; no border is rendered. This element does not have the class red, so it's skipped. Only the first rule is applied; a red border is rendered. This element has the class red, but it's not preceded by any elements with the class red in its parent. Thus the second rule is not applied, only the first, and the element keeps its border. Both rules are applied; no border is rendered. This element has the class red. It is also preceded by at least one other element with the class red. Thus both rules are applied, and the second border declaration overrides the first, thereby "undoing" it, so to speak.
As a bonus, although it was introduced in Selectors 3, the general sibling combinator is actually pretty well-supported by IE7 and newer, unlike :first-of-type
and :nth-of-type()
which are only supported by IE9 onward. If you need good browser support, you're in luck.
In fact, the fact that the sibling combinator is the only important component in this technique, and it has such amazing browser support, makes this technique very versatile — you can adapt it for filtering elements by other things, besides class selectors:
You can use this to work around :first-of-type in IE7 and IE8, by simply supplying a type selector instead of a class selector (again, more on its incorrect usage in the question in a later section): article > p { /* Apply styles to article > p:first-of-type, which may or may not be :first-child */ } article > p ~ p { /* Undo the above styles for every subsequent article > p */ }
You can filter by attribute selectors or any other simple selectors instead of classes.
You can also combine this overriding technique with pseudo-elements even though pseudo-elements technically aren't simple selectors.
Note that in order for this to work, you will need to know in advance what the default styles will be for your other sibling elements so you can override the first rule. Additionally, since this involves overriding rules in CSS, you can't achieve the same thing with a single selector for use with the Selectors API, or Selenium's CSS locators.
On a final note, keep in mind that this answer assumes that the question is looking for any number of first child elements having a given class. There is neither a pseudo-class nor even a generic CSS solution for the nth match of a complex selector across the entire document — whether a solution exists depends heavily on the document structure. jQuery provides :eq()
, :first
, :last
and more for this purpose, but note again that they function very differently from :nth-child()
et al. Using the Selectors API, you can either use document.querySelector()
to obtain the very first match:
var first = document.querySelector('.home > .red');
Or use document.querySelectorAll()
with an indexer to pick any specific match:
var redElements = document.querySelectorAll('.home > .red');
var first = redElements[0];
var second = redElements[1];
// etc
Although the .red:nth-of-type(1)
solution in the original accepted answer by Philip Daubmeier works (which was originally written by Martyn but deleted since), it does not behave the way you'd expect it to.
For example, if you only wanted to select the p
here:
<p class="red"></p>
<div class="red"></div>
... then you can't use .red:first-of-type
(equivalent to .red:nth-of-type(1)
), because each element is the first (and only) one of its type (p
and div
respectively), so both will be matched by the selector.
When the first element of a certain class is also the first of its type, the pseudo-class will work, but this happens only by coincidence. This behavior is demonstrated in Philip's answer. The moment you stick in an element of the same type before this element, the selector will fail. Taking the markup from the question:
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
Applying a rule with .red:first-of-type
will work, but once you add another p
without the class:
<div class="home">
<span>blah</span>
<p>dummy</p>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
... the selector will immediately fail, because the first .red
element is now the second p
element.
The :first-child
selector is intended, like the name says, to select the first child of a parent tag. So this example will work (Just tried it here):
<body>
<p class="red">first</p>
<div class="red">second</div>
</body>
This won't work, though, if you've nested your tags under different parent tags, or if your tags of class red
aren't the first tags under the parent.
Notice also that this doesn't only apply to the first such tag in the whole document, but every time a new parent is wrapped around it, like:
<div>
<p class="red">first</p>
<div class="red">second</div>
</div>
<div>
<p class="red">third</p>
<div class="red">fourth</div>
</div>
first
and third
will be red then.
For your case, you can use the :nth-of-type
selector:
.red:nth-of-type(1) { border:5px solid red; }
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Credits to Martyn, who deleted his answer containing this approach. More infos for example here. Be aware that this is a CSS 3 selector, therefore not all browsers will recognize it (e.g. IE8 or older).
.red:nth-of-type(1)
will select any element which (a) is the first child of its element type, and (b) has the class "red". So if, in the example, the the first <p> did not have class "red", it would not be selected. Alternatively if the <span> and the first <p> both had class "red", they'd both be selected. jsfiddle.net/fvAxn
:nth-of-type()
is not a good solution to this. I have provided an alternative answer that should be more reliable and, as a bonus, works in IE7+, unlike :nth-of-type()
.
:first-of-type
is equivalent to :nth-of-type(1)
, so of course it works, too. It can also fail, too, in the same way for the same reason stated in my answer.
:nth-of-type
means "element/tag" when it says "type". So it only considers the element, not things like classes.
The correct answer is:
.red:first-child, :not(.red) + .red { border:5px solid red }
Part I: If element is first to its parent and has class "red", it shall get border. Part II: If ".red" element is not first to its parent, but is immediately following an element without class ".red", it shall also deserve the honor of said border.
Philip Daubmeier's answer, while accepted, is not correct - see attached fiddle. BoltClock's answer would work, but unnecessarily defines and overwrites styles (particularly an issue where it otherwise would inherit a different border - you don't want to declare other to border:none)
EDIT: In the event that you have "red" following non-red several times, each "first" red will get the border. To prevent that, one would need to use BoltClock's answer. See fiddle
.red
follows a :not(.red)
doesn't always make it the first .red
among its siblings. And if the border needs to be inherited, it's simply a matter of declaring border: inherit
instead of border: none
in the override rule.
you could use first-of-type
or nth-of-type(1)
.red { color: green; } /* .red:nth-of-type(1) */ .red:first-of-type { color: red; }
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<p></p>
between the span
and your first p
element with red
class. Look at this JSFiddle.
The above answers are too complex.
.class:first-of-type { }
This will select the first-type of class. MDN Source
Note: Tested with Chrome 91 and Firefox 89, June 2021.
<span>
, and a few have the class highlight
. The .highlight:first-of-type
selector will select the first instance of the "type" with the selected class, in this example the first <span>
, and not the first instance of the class highlight
. Only if that first instance of span also has the class highlight will the style be implemented. (codepen.io/andrewRmillar/pen/poJKJdJ)
I am surprised no one mentioned the cleanest solution:
.red:not(.red ~ .red) { border: 1px solid red; }
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.red
that is not a ".red
preceded with a .red
". Only the first one is in this example. But it won't work if another class is inserted in between. Note: .red:not(.red ~ *)
should work too ("a red
that is not "anything
preceded with a .red
")
Since the other answers cover what's wrong with it, I'll try the other half, how to fix it. Unfortunately, I don't know that you have a CSS only solution here, at least not that I can think of. There are some other options though....
Assign a first class to the element when you generate it, like this:
CSS: .first.red { border:5px solid red; } This CSS only matches elements with both first and red classes. Alternatively, do the same in JavaScript, for example here's what jQuery you would use to do this, using the same CSS as above: $(".red:first").addClass("first");:first-of-class
, I would also suggest to add an extra class to the first element. Seems the easiest solution for now.
To match your selector, the element must have a class name of red
and must be the first child of its parent.
<div>
<span class="red"></span> <!-- MATCH -->
</div>
<div>
<span>Blah</span>
<p class="red"></p> <!-- NO MATCH -->
</div>
<div>
<span>Blah</span>
<div><p class="red"></p></div> <!-- MATCH -->
</div>
I got this one in my project.
div > .b ~ .b:not(:first-child) { background: none; } div > .b { background: red; }
The first paragraph.
The second paragraph.
The third paragraph.
The fourth paragraph.
According to your updated problem
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
how about
.home span + .red{
border:1px solid red;
}
This will select class home, then the element span and finally all .red elements that are placed immediately after span elements.
Reference: http://www.w3schools.com/cssref/css_selectors.asp
I am using below CSS to have a background image for the list ul li
#footer .module:nth-of-type(1)>.menu>li:nth-of-type(1){ background-position: center; background-image: url(http://monagentvoyagessuperprix.j3.voyagesendirect.com/images/stories/images_monagentvoyagessuperprix/layout/icon-home.png); background-repeat: no-repeat; }
For some reason none of the above answers seemed to be addressing the case of the real first and only first child of the parent.
#element_id > .class_name:first-child
All the above answers will fail if you want to apply the style to only the first class child within this code.
<aside id="element_id">
Content
<div class="class_name">First content that need to be styled</div>
<div class="class_name">
Second content that don't need to be styled
<div>
<div>
<div class="class_name">deep content - no style</div>
<div class="class_name">deep content - no style</div>
<div>
<div class="class_name">deep content - no style</div>
</div>
</div>
</div>
</div>
</aside>
You can change your code to something like this to get it work
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
This does the job for you
.home span + .red{
border:3px solid green;
}
Here is a CSS reference from SnoopCode about that.
You could use nth-of-type(1) but be sure that site doesn't need to support IE7 etc, if this is the case use jQuery to add body class then find element via IE7 body class then the element name, then add in the nth-child styling to it.
All in All, after reading this all page and other ones and a lot of documentation. Here's the summary:
For first/last child: Safe to use now (Supported by all modern browsers)
:nth-child() Also safe to use now (Supported by all modern browsers). But be careful it even counts siblings! So, the following won't work properly:
/* This should select the first 2 element with class display_class * but it will NOT WORK Because the nth-child count even siblings * including the first div skip_class */ .display_class:nth-child(-n+2){ background-color:green; }
Currently, there is a selector :nth-child(-n+2 of .foo) that supports selection by class but not supported by modern browsers so not useful.
So, that leaves us with Javascript solution (we'll fix the example above):
// Here we'll go through the elements with the targeted class // and add our classmodifer to only the first 2 elements! [...document.querySelectorAll('.display_class')].forEach((element,index) => { if (index < 2) element.classList.add('display_class--green'); }); .display_class--green { background-color:green; }
The following code will definitely work well everywhere. it is simple and short.
<div class="home">
<span>blah</span>
<p class="blue"> first-blue </p>
<p class="blue"> second-blue </p>
<p class="blue"> third-blue </p>
<p class="red"> first-red </p>
<p class="red"> second-red </p>
<p class="red"> third-red </p>
<p class="red"> fourth-red </p>
<p class="pink"> first-pink </p>
<p class="pink"> second-pink </p>
<p class="red"> new-first-red </p>
<p class="red"> new-second-red </p>
</div>
we can select the first-red
with:
.home .red:not(.home .red ~ .red) {
background-color: blue;
}
if you want to select new-first-red
too you should use +
instead of ~
.
Try This Simple and Effective
.home > span + .red{
border:1px solid red;
}
I believe that using relative selector +
for selecting elements placed immediately after, works here the best (as few suggested before).
It is also possible for this case to use this selector
.home p:first-of-type
but this is element selector not the class one.
Here you have nice list of CSS selectors: https://kolosek.com/css-selectors/
Could you try something like this:
.red:first-of-type {
border: 5px solid red;
}
you also can use this for last element (if you need it):
.red:last-of-type {
border: 5px solid red;
}
just use
.home > .red ~ .red{
border: 1px solid red;
}
it will work.
use this
or this will work
explain how and why it will work.
Try this solution:
.home p:first-of-type { border:5px solid red; width:100%; display:block; }
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I think a lot of people have explained already. your code is selecting only first child of the first instance. If you want to select all the first children of red class, you need to use
.home > .red:first-child {
/* put your styling here */
}
Success story sharing
:last-of-class
? Select the last element of a class.article > p ~ article > p
doesn't work/produce the same effect asarticle > p ~ p
.> p
implies that the secondp
is a child of the samearticle
by way of the sibling combinator, so replacing that secondp
witharticle
works similarly, and the following> p
traverses one additional level down from that point. I have a couple of other answers that explain it in much greater detail: stackoverflow.com/a/3851754 stackoverflow.com/a/8135729