If I have this schema...
person = {
name : String,
favoriteFoods : Array
}
... where the favoriteFoods
array is populated with strings. How can I find all persons that have "sushi" as their favorite food using mongoose?
I was hoping for something along the lines of:
PersonModel.find({ favoriteFoods : { $contains : "sushi" }, function(...) {...});
(I know that there is no $contains
in mongodb, just explaining what I was expecting to find before knowing the solution)
As favouriteFoods
is a simple array of strings, you can just query that field directly:
PersonModel.find({ favouriteFoods: "sushi" }, ...); // favouriteFoods contains "sushi"
But I'd also recommend making the string array explicit in your schema:
person = {
name : String,
favouriteFoods : [String]
}
The relevant documentation can be found here: https://docs.mongodb.com/manual/tutorial/query-arrays/
There is no $contains
operator in mongodb.
You can use the answer from JohnnyHK as that works. The closest analogy to contains that mongo has is $in
, using this your query would look like:
PersonModel.find({ favouriteFoods: { "$in" : ["sushi"]} }, ...);
$in
is used when you have multiple query values and the document needs to match one of them. For the reverse (which is what this question is about), JohnnyHK's answer is correct. I was going to downvote but I guess this answer may be helpful to other people who end up on this page.
PersonModel.find({favouriteFoods: {"$in": ["sushi", "hotdog"]}})
I feel like $all
would be more appropriate in this situation. If you are looking for person that is into sushi you do :
PersonModel.find({ favoriteFood : { $all : ["sushi"] }, ...})
As you might want to filter more your search, like so :
PersonModel.find({ favoriteFood : { $all : ["sushi", "bananas"] }, ...})
$in
is like OR and $all
like AND. Check this : https://docs.mongodb.com/manual/reference/operator/query/all/
In case that the array contains objects for example if favouriteFoods
is an array of objects of the following:
{
name: 'Sushi',
type: 'Japanese'
}
you can use the following query:
PersonModel.find({"favouriteFoods.name": "Sushi"});
In case you need to find documents which contain NULL elements inside an array of sub-documents, I've found this query which works pretty well:
db.collection.find({"keyWithArray":{$elemMatch:{"$in":[null], "$exists":true}}})
This query is taken from this post: MongoDb query array with null values
It was a great find and it works much better than my own initial and wrong version (which turned out to work fine only for arrays with one element):
.find({
'MyArrayOfSubDocuments': { $not: { $size: 0 } },
'MyArrayOfSubDocuments._id': { $exists: false }
})
Incase of lookup_food_array is array.
match_stage["favoriteFoods"] = {'$elemMatch': {'$in': lookup_food_array}}
Incase of lookup_food_array is string.
match_stage["favoriteFoods"] = {'$elemMatch': lookup_food_string}
Though agree with find() is most effective in your usecase. Still there is $match of aggregation framework, to ease the query of a big number of entries and generate a low number of results that hold value to you especially for grouping and creating new files.
PersonModel.aggregate([ { "$match": { $and : [{ 'favouriteFoods' : { $exists: true, $in: [ 'sushi']}}, ........ ] } }, { $project : {"_id": 0, "name" : 1} } ]);
There are some ways to achieve this. First one is by $elemMatch
operator:
const docs = await Documents.find({category: { $elemMatch: {$eq: 'yourCategory'} }});
// you may need to convert 'yourCategory' to ObjectId
Second one is by $in
or $all
operators:
const docs = await Documents.find({category: { $in: [yourCategory] }});
or
const docs = await Documents.find({category: { $all: [yourCategory] }});
// you can give more categories with these two approaches
//and again you may need to convert yourCategory to ObjectId
$in
is like OR and $all
like AND. For further details check this link : https://docs.mongodb.com/manual/reference/operator/query/all/
Third one is by aggregate()
function:
const docs = await Documents.aggregate([
{ $unwind: '$category' },
{ $match: { 'category': mongoose.Types.ObjectId(yourCategory) } }
]};
with aggregate() you get only one category id in your category array.
I get this code snippets from my projects where I had to find docs with specific category/categories, so you can easily customize it according to your needs.
For Loopback3 all the examples given did not work for me, or as fast as using REST API anyway. But it helped me to figure out the exact answer I needed.
{"where":{"arrayAttribute":{ "all" :[String]}}}
With populate & $in this code will be useful.
ServiceCategory.find().populate({
path: "services",
match: { zipCodes: {$in: "10400"}},
populate: [
{
path: "offers",
},
],
});
In case You are searching in an Array of objects, you can use $elemMatch
. For example:
PersonModel.find({ favoriteFoods : { $elemMatch: { name: "sushi" }});
If you'd want to use something like a "contains" operator through javascript, you can always use a Regular expression for that...
eg. Say you want to retrieve a customer having "Bartolomew" as name
async function getBartolomew() {
const custStartWith_Bart = await Customers.find({name: /^Bart/ }); // Starts with Bart
const custEndWith_lomew = await Customers.find({name: /lomew$/ }); // Ends with lomew
const custContains_rtol = await Customers.find({name: /.*rtol.*/ }); // Contains rtol
console.log(custStartWith_Bart);
console.log(custEndWith_lomew);
console.log(custContains_rtol);
}
I know this topic is old, but for future people who could wonder the same question, another incredibly inefficient solution could be to do:
PersonModel.find({$where : 'this.favouriteFoods.indexOf("sushi") != -1'});
This avoids all optimisations by MongoDB so do not use in production code.
Success story sharing
favouriteFoods
is:favouriteFoods:[{type:Schema.Types.ObjectId, ref:'Food'}]
PersonModel.find({ favouriteFoods.text: "sushi" }, ...); person = { name : String, favouriteFoods : [{text:String}] }
db.person.find( { favouriteFoods: { $all: ["sushi", "sashimi"] } } )
will return all person loving both "sushi" and "sashimi" someone pointed it a few answers below