What is the easiest/shortest way to convert a Java 8 Stream
into an array?
The easiest method is to use the toArray(IntFunction<A[]> generator)
method with an array constructor reference. This is suggested in the API documentation for the method.
String[] stringArray = stringStream.toArray(String[]::new);
What it does is find a method that takes in an integer (the size) as argument, and returns a String[]
, which is exactly what (one of the overloads of) new String[]
does.
You could also write your own IntFunction
:
Stream<String> stringStream = ...;
String[] stringArray = stringStream.toArray(size -> new String[size]);
The purpose of the IntFunction<A[]> generator
is to convert an integer, the size of the array, to a new array.
Example code:
Stream<String> stringStream = Stream.of("a", "b", "c");
String[] stringArray = stringStream.toArray(size -> new String[size]);
Arrays.stream(stringArray).forEach(System.out::println);
Prints:
a
b
c
If you want to get an array of ints, with values from 1 to 10, from a Stream<Integer>
, there is IntStream
at your disposal.
Here we create a Stream
with a Stream.of
method and convert a Stream<Integer>
to an IntStream
using a mapToInt
. Then we can call IntStream
's toArray
method.
Stream<Integer> stream = Stream.of(1,2,3,4,5,6,7,8,9,10);
//or use this to create our stream
//Stream<Integer> stream = IntStream.rangeClosed(1, 10).boxed();
int[] array = stream.mapToInt(x -> x).toArray();
Here is the same thing, without the Stream<Integer>
, using only the IntStream
:
int[]array2 = IntStream.rangeClosed(1, 10).toArray();
You can convert a java 8 stream to an array using this simple code block:
String[] myNewArray3 = myNewStream.toArray(String[]::new);
But let's explain things more, first, let's Create a list of string filled with three values:
String[] stringList = {"Bachiri","Taoufiq","Abderrahman"};
Create a stream from the given Array :
Stream<String> stringStream = Arrays.stream(stringList);
we can now perform some operations on this stream Ex:
Stream<String> myNewStream = stringStream.map(s -> s.toUpperCase());
and finally convert it to a java 8 Array using these methods:
1-Classic method (Functional interface)
IntFunction<String[]> intFunction = new IntFunction<String[]>() {
@Override
public String[] apply(int value) {
return new String[value];
}
};
String[] myNewArray = myNewStream.toArray(intFunction);
2 -Lambda expression
String[] myNewArray2 = myNewStream.toArray(value -> new String[value]);
3- Method reference
String[] myNewArray3 = myNewStream.toArray(String[]::new);
Method reference Explanation:
It's another way of writing a lambda expression that it's strictly equivalent to the other.
Convert text to string array where separating each value by comma, and trim every field, for example:
String[] stringArray = Arrays.stream(line.split(",")).map(String::trim).toArray(String[]::new);
import java.util.List;
import java.util.stream.Stream;
class Main {
public static void main(String[] args) {
// Create a stream of strings from list of strings
Stream<String> myStreamOfStrings = List.of("lala", "foo", "bar").stream();
// Convert stream to array by using toArray method
String[] myArrayOfStrings = myStreamOfStrings.toArray(String[]::new);
// Print results
for (String string : myArrayOfStrings) {
System.out.println(string);
}
}
}
Try it out online: https://repl.it/@SmaMa/Stream-to-array
You can create a custom collector that convert a stream to array.
public static <T> Collector<T, ?, T[]> toArray( IntFunction<T[]> converter )
{
return Collectors.collectingAndThen(
Collectors.toList(),
list ->list.toArray( converter.apply( list.size() ) ) );
}
and a quick use
List<String> input = Arrays.asList( ..... );
String[] result = input.stream().
.collect( CustomCollectors.**toArray**( String[]::new ) );
Collectors.groupingBy
so that I could map some attribute to arrays of objects per attribute value. This answer gives me exactly that. Also @DidierL.
list -> list.toArray(converter)
due to addition of Collection.toArray(IntFunction)
Using the toArray(IntFunction<A[]> generator)
method is indeed a very elegant and safe way to convert (or more correctly, collect) a Stream into an array of the same type of the Stream.
However, if the returned array's type is not important, simply using the toArray()
method is both easier and shorter. For example:
Stream<Object> args = Stream.of(BigDecimal.ONE, "Two", 3);
System.out.printf("%s, %s, %s!", args.toArray());
Stream<Integer> stream = Stream.of(1, 2, 3, 4, 5, 6);
int[] arr= stream.mapToInt(x->x.intValue()).toArray();
Stream<Integer> stream = Stream.of(1, 2, 3, 4, 5, 6);
Integer[] integers = stream.toArray(it->new Integer[it]);
you can use the collector like this
Stream<String> io = Stream.of("foo" , "lan" , "mql");
io.collect(Collectors.toCollection(ArrayList<String>::new));
Success story sharing
toArray(sz -> new String[sz])
so I'm not sure that one can really say what the solution should or must be.sz -> new String[sz]
makes a new function where as the constructor reference does not. It depends how much you value Garbage Collection Churn I guess.private
method, which cannot cause churn, and both versions need to create a new object. A reference creates an object that points directly at the target method; a lambda creates an object that points at the generatedprivate
one. A reference to a constructor should still perform better for lack of indirection and easier VM optimization, but churning has nothing to do with it.