What I'm trying to achieve is to create one module that contains multiple functions in it.
module.js:
module.exports = function(firstParam) { console.log("You did it"); },
module.exports = function(secondParam) { console.log("Yes you did it"); },
// This may contain more functions
main.js:
var foo = require('module.js')(firstParam);
var bar = require('module.js')(secondParam);
The problem I have is that the firstParam
is an object type and the secondParam
is a URL string, but when I have that it always complains that the type is wrong.
How can I declare multiple module.exports in this case?
require
methods, or a combination of require
methods and other functions, then the answer is here.
You can do something like:
module.exports = {
method: function() {},
otherMethod: function() {},
};
Or just:
exports.method = function() {};
exports.otherMethod = function() {};
Then in the calling script:
const myModule = require('./myModule.js');
const method = myModule.method;
const otherMethod = myModule.otherMethod;
// OR:
const {method, otherMethod} = require('./myModule.js');
To export multiple functions you can just list them like this:
module.exports = {
function1,
function2,
function3
}
And then to access them in another file:
var myFunctions = require("./lib/file.js")
And then you can call each function by calling:
myFunctions.function1
myFunctions.function2
myFunctions.function3
const { function1, function2, function3 } = require("./lib/file.js")
which allows you to call them directly (e.g. function1
instead of myFunctions.function1
)
in addition to @mash answer I recommend you to always do the following:
const method = () => {
// your method logic
}
const otherMethod = () => {
// your method logic
}
module.exports = {
method,
otherMethod,
// anotherMethod
};
Note here:
You can call method from otherMethod and you will need this a lot
You can quickly hide a method as private when you need
This is easier for most IDE's to understand and autocomplete your code ;)
You can also use the same technique for import: const {otherMethod} = require('./myModule.js');
const {otherMethod} = require('./myModule.js');
this. what do you call this approach of import methods from a {}?
require(./myModule.js)
in the right side of the assignment you are actually importing the whole module as a single object then when you do const {otherMethod}
in the left side of the assignment you are doing something called "Destructuring Assignment" you can read more about it in MDN here: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…
module.js:
const foo = function(<params>) { ... }
const bar = function(<params>) { ... }
//export modules
module.exports = {
foo,
bar
}
main.js:
// import modules
var { foo, bar } = require('module');
// pass your parameters
var f1 = foo(<params>);
var f2 = bar(<params>);
This is just for my reference as what I was trying to achieve can be accomplished by this.
In the module.js
We can do something like this
module.exports = function ( firstArg, secondArg ) {
function firstFunction ( ) { ... }
function secondFunction ( ) { ... }
function thirdFunction ( ) { ... }
return { firstFunction: firstFunction, secondFunction: secondFunction,
thirdFunction: thirdFunction };
}
In the main.js
var name = require('module')(firstArg, secondArg);
If the files are written using ES6 export, you can write:
module.exports = {
...require('./foo'),
...require('./bar'),
};
One way that you can do it is creating a new object in the module instead of replacing it.
for example:
var testone = function () {
console.log('test one');
};
var testTwo = function () {
console.log('test two');
};
module.exports.testOne = testOne;
module.exports.testTwo = testTwo;
and to call
var test = require('path_to_file').testOne:
testOne();
You can write a function that manually delegates between the other functions:
module.exports = function(arg) {
if(arg instanceof String) {
return doStringThing.apply(this, arguments);
}else{
return doObjectThing.apply(this, arguments);
}
};
There are multiple ways to do this, one way is mentioned below. Just assume you have .js file like this.
let add = function (a, b) {
console.log(a + b);
};
let sub = function (a, b) {
console.log(a - b);
};
You can export these functions using the following code snippet,
module.exports.add = add;
module.exports.sub = sub;
And you can use the exported functions using this code snippet,
var add = require('./counter').add;
var sub = require('./counter').sub;
add(1,2);
sub(1,2);
I know this is a late reply, but hope this helps!
use this
(function()
{
var exports = module.exports = {};
exports.yourMethod = function (success)
{
}
exports.yourMethod2 = function (success)
{
}
})();
also you can export it like this
const func1 = function (){some code here}
const func2 = function (){some code here}
exports.func1 = func1;
exports.func2 = func2;
or for anonymous functions like this
const func1 = ()=>{some code here}
const func2 = ()=>{some code here}
exports.func1 = func1;
exports.func2 = func2;
Two types module import and export.
type 1 (module.js):
// module like a webpack config
const development = {
// ...
};
const production = {
// ...
};
// export multi
module.exports = [development, production];
// export single
// module.exports = development;
type 1 (main.js):
// import module like a webpack config
const { development, production } = require("./path/to/module");
type 2 (module.js):
// module function no param
const module1 = () => {
// ...
};
// module function with param
const module2 = (param1, param2) => {
// ...
};
// export module
module.exports = {
module1,
module2
}
type 2 (main.js):
// import module function
const { module1, module2 } = require("./path/to/module");
How to use import module?
const importModule = {
...development,
// ...production,
// ...module1,
...module2("param1", "param2"),
};
Inside your node module you can export various functions such as:
module.exports.eat = eat; function eat() { ....... return *something*; }; module.exports.sleep = sleep; function sleep() { ....... return *something*; };
Note that you are not calling the functions while exporting them. Then while requiring the modules you can require as:-
const task = require(__dirname + "/task.js"); //task is the name of the file let eat = task.eat(); let sleep = task.sleep();
module1.js:
var myFunctions = {
myfunc1:function(){
},
myfunc2:function(){
},
myfunc3:function(){
},
}
module.exports=myFunctions;
main.js
var myModule = require('./module1');
myModule.myfunc1(); //calling myfunc1 from module
myModule.myfunc2(); //calling myfunc2 from module
myModule.myfunc3(); //calling myfunc3 from module
If you declare a class in module file instead of the simple object
File: UserModule.js
//User Module
class User {
constructor(){
//enter code here
}
create(params){
//enter code here
}
}
class UserInfo {
constructor(){
//enter code here
}
getUser(userId){
//enter code here
return user;
}
}
// export multi
module.exports = [User, UserInfo];
Main File: index.js
// import module like
const { User, UserInfo } = require("./path/to/UserModule");
User.create(params);
UserInfo.getUser(userId);
You can use this approach too
module.exports.func1 = ...
module.exports.func2 = ...
or
exports.func1 = ...
exports.func2 = ...
Adding here for someone to help:
this code block will help adding multiple plugins into cypress index.js Plugins -> cypress-ntlm-auth and cypress env file selection
const ntlmAuth = require('cypress-ntlm-auth/dist/plugin');
const fs = require('fs-extra');
const path = require('path');
const getConfigurationByFile = async (config) => {
const file = config.env.configFile || 'dev';
const pathToConfigFile = path.resolve(
'../Cypress/cypress/',
'config',
`${file}.json`
);
console.log('pathToConfigFile' + pathToConfigFile);
return fs.readJson(pathToConfigFile);
};
module.exports = async (on, config) => {
config = await getConfigurationByFile(config);
await ntlmAuth.initNtlmAuth(config);
return config;
};
Use the export keyword
module.js
export {method1, method2}
And import them in main.js
import {method1, method2) from "./module"
module.exports = (function () {
'use strict';
var foo = function () {
return {
public_method: function () {}
};
};
var bar = function () {
return {
public_method: function () {}
};
};
return {
module_a: foo,
module_b: bar
};
}());
Success story sharing
module.method
anywhere here...onlyexports.method
, which is just a reference tomodule.exports.method
, so behaves the same way. The only difference is we did not definemodule.exports
, so it defaults to{}
, unless I'm mistaken.var otherMethod = require('module.js')(otherMethod);
? I.e., would that line require theotherMethod
function just as if it were the only function on the page and the export had been:module.exports = secondMethod;
?var otherMethod = require('module.js').otherMethod
.