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When should you use a class vs a struct in C++?

In what scenarios is it better to use a struct vs a class in C++?

This isn't only applicable to C++, but to any language that provides both structs and classes.
I still disagree - I approach this question semantically. Maybe there are some technical differences, but semantically, they are not. Structs are really useful for creating value types, classes are not.
I believe that there is no serious reason for using structs in C++. To me structs are another redundant "feature" of C++ that exists only for compatibility with C, like typedefs. These would not exist if C++ was not initially treated as an extension to C, and was designed from scratch, such as Java. In general, I find that many of the weirdest things about C++ have to do with C compatibility.
Struct - For POD (plain old data) and all member accessibility is public. Class - When you need better encapsulation and need member functions to work with the class's state.
This is true only by convention. There is no difference, apart from default encapsulation.

e
einpoklum

The differences between a class and a struct in C++ is:

struct members and base classes/structs are public by default.

class members and base classes/struts are private by default.

Both classes and structs can have a mixture of public, protected and private members, can use inheritance and can have member functions.

I would recommend you:

use struct for plain-old-data structures without any class-like features;

use class when you make use of features such as private or protected members, non-default constructors and operators, etc.


A struct with no modifiers or methods is called a POD struct, which exists as a backwards compatible interface with C libraries as it is (supposedly) guaranteed to be laid out as though it were a C struct. Apart from this one exception though, the only difference is as stated.
@workmad3: The name is misleading, but 9/4 (C++03) says: "A POD-struct is an aggregate class that has no non-static data members of type non-POD-struct, non-POD-union (or array of such types) or reference, and has no user-defined copy assignment operator and no user-defined destructor." There is no restriction on using the "struct" class-key and no restriction on using "public" (see 8.5.1/1 for aggregate requirements). This is not a difference between "struct" and "class".
Your use of "aggregate" could be misunderstood, given the standard's definition. :)
According to Stroustrup's "Principles and Practice" book: "structs should primarily be used where the members can take any value" (i.e. where no meaningful class invariant can be defined)
Of course you may use classes when interfacing with C. There is no difference between classes and structs. Structs are classes; only default access is flipped from private to public.
C
Community

As everyone else notes there are really only two actual language differences:

struct defaults to public access and class defaults to private access.

When inheriting, struct defaults to public inheritance and class defaults to private inheritance. (Ironically, as with so many things in C++, the default is backwards: public inheritance is by far the more common choice, but people rarely declare structs just to save on typing the "public" keyword.

But the real difference in practice is between a class/struct that declares a constructor/destructor and one that doesn't. There are certain guarantees to a "plain-old-data" POD type, that no longer apply once you take over the class's construction. To keep this distinction clear, many people deliberately only use structs for POD types, and, if they are going to add any methods at all, use classes. The difference between the two fragments below is otherwise meaningless:

class X
{
  public:

  // ...
};

struct X
{
  // ...
};

(Incidentally, here's a thread with some good explanations about what "POD type" actually means: What are POD types in C++?)


Nice example regarding the inheritance differences: here.
Whether you use struct or class has no bearing on whether your object is POD or whether you should define a copy constructor / destructor. Member functions also have no bearing on something being POD. As I re-read what you wrote, I see you aren't suggesting otherwise, but the current wording is confusing
@DavidStone Basically, POD structs are supposed to be guaranteed to be backwards-compatible with C code, and thus are basically supposed to just be designed as C-style structs.
@juanchopanza how so? Are there any other differences you're aware of?
@rdelfin I think I must have misread the paragraph, because the question is about differences between struct and class and when it comes to object layout there aren't any. The POD thing also change a bit since C++11. The bullet points are correct though. it is just about the defaults when you use either keyword to define a class.
L
Lightness Races in Orbit

There are lots of misconceptions in the existing answers.

Both class and struct declare a class.

Yes, you may have to rearrange your access modifying keywords inside the class definition, depending on which keyword you used to declare the class.

But, beyond syntax, the only reason to choose one over the other is convention/style/preference.

Some people like to stick with the struct keyword for classes without member functions, because the resulting definition "looks like" a simple structure from C.

Similarly, some people like to use the class keyword for classes with member functions and private data, because it says "class" on it and therefore looks like examples from their favourite book on object-oriented programming.

The reality is that this completely up to you and your team, and it'll make literally no difference whatsoever to your program.

The following two classes are absolutely equivalent in every way except their name:

struct Foo
{
   int x;
};

class Bar
{
public:
   int x;
};

You can even switch keywords when redeclaring:

class Foo;
struct Bar;

(although this breaks Visual Studio builds due to non-conformance, so that compiler will emit a warning when you do this.)

and the following expressions both evaluate to true:

std::is_class<Foo>::value
std::is_class<Bar>::value

Do note, though, that you can't switch the keywords when redefining; this is only because (per the one-definition rule) duplicate class definitions across translation units must "consist of the same sequence of tokens". This means you can't even exchange const int member; with int const member;, and has nothing to do with the semantics of class or struct.


This was very informative, and honestly my favorite answer. Everyone else is treating them as separate entities, when underneath the hood, they are the same. I wonder if a struct definition in the Arduino environment is considered a cpp class, seeing as it's compiled using g++.
@Ben Of course it is. The Arduino compiler compiles C++; that's the end of it.
So if I'm understanding this right: As long as your visibility modifiers are explicit, not omitted, it doesn't matter. You could write a huge C++ application using nothing but structs; or you could go through and change every case of struct to class. As long as you're not using default visibility, the applications would be precisely the same.
I'm not convinced that one translation unit of a C++ program can have the complete declaration class foo { public: ... }; and another can have struct foo { ... }; which would have to hold true according to the "absolutely equivalent" claim. It comes to reason that the incomplete declarations struct foo; and class foo; are interchangeable. These do not specify the class body, and so they speak nothing to the access layout.
@Kaz: You're right - if the definitions were for literally the same type, they must be lexically identical for the behaviour to be well-defined. The struct-key and class-key are otherwise logically exchangeable though (where the semantics are not affected), and Foo and Bar are still equivalent/identical types. I did make sure to say "when redeclaring" and give an example. Come to think of it, I'll clarify this in the answer to make sure I'm not misleading people into UB
F
Ferruccio

The only time I use a struct instead of a class is when declaring a functor right before using it in a function call and want to minimize syntax for the sake of clarity. e.g.:

struct Compare { bool operator() { ... } };
std::sort(collection.begin(), collection.end(), Compare()); 

Now that it is several years later and C++11 is supported by all the major compilers, Lambdas make this even more concise.
C
Community

From the C++ FAQ Lite:

The members and base classes of a struct are public by default, while in class, they default to private. Note: you should make your base classes explicitly public, private, or protected, rather than relying on the defaults. struct and class are otherwise functionally equivalent. OK, enough of that squeaky clean techno talk. Emotionally, most developers make a strong distinction between a class and a struct. A struct simply feels like an open pile of bits with very little in the way of encapsulation or functionality. A class feels like a living and responsible member of society with intelligent services, a strong encapsulation barrier, and a well defined interface. Since that's the connotation most people already have, you should probably use the struct keyword if you have a class that has very few methods and has public data (such things do exist in well designed systems!), but otherwise you should probably use the class keyword.


I don't understand why they are stating that struct and class are functionally the same, but saying to prefer the one over the other in certain cases without any reasoning..
The reason is convention. The compiler doesn't care which one you use, but another developer looking at your code will have an easier time understanding what you meant.
@deetz: The entire third paragraph is reasoning.
Wow, coming from 'old school' I had no idea that a struct could have methods and even inheritance. I've always used struct for when using just data only with no methods and it's usually when dealing with API code that needs the struct. Can structs support multiple inheritance also?
s
start2learn

One place where a struct has been helpful for me is when I have a system that's receiving fixed format messages (over say, a serial port) from another system. You can cast the stream of bytes into a struct that defines your fields, and then easily access the fields.

typedef struct
{
    int messageId;
    int messageCounter;
    int messageData;
} tMessageType;

void processMessage(unsigned char *rawMessage)
{
    tMessageType *messageFields = (tMessageType *)rawMessage;
    printf("MessageId is %d\n", messageFields->messageId);
}

Obviously, this is the same thing you would do in C, but I find that the overhead of having to decode the message into a class is usually not worth it.


The same can be achieved in C.
Or you could just implement operator >> on a class instead of writing the processMessage function, which would make your C++ look more like proper C++ and less like C.
Besides the fact that it's not portable between different systems, this violates aliasing rules, so it's not guaranteed to work even within a single architecture.
@underscore_d Quite portable for the lifetime of a project or codebase for an embedded system, and an ADC won't change its register set for 30 years. It does the job, its single cycle, and easily testable, and can be handed to kernel drivers, void* system calls, and passed between C and C++,I say win-win?
@jacwah Huh, good point. Aliasing won't be a problem here because one of the pointers is a char type, which are exempt from aliasing. However, there is still a problem, albeit a different one: Casting a char* to a different type, if there was not really any object of the latter type already initialised at that address, is UB as it violates lifetime rules. Afaik, even if the destination type is trivially constructible, just having allocated memory is not sufficient for C++ to formally allow treating that memory as that type.
A
Adisak

You can use "struct" in C++ if you are writing a library whose internals are C++ but the API can be called by either C or C++ code. You simply make a single header that contains structs and global API functions that you expose to both C and C++ code as this:

// C access Header to a C++ library
#ifdef __cpp
extern "C" {
#endif

// Put your C struct's here
struct foo
{
    ...
};
// NOTE: the typedef is used because C does not automatically generate
// a typedef with the same name as a struct like C++.
typedef struct foo foo;

// Put your C API functions here
void bar(foo *fun);

#ifdef __cpp
}
#endif

Then you can write a function bar() in a C++ file using C++ code and make it callable from C and the two worlds can share data through the declared struct's. There are other caveats of course when mixing C and C++ but this is a simplified example.


Best fitting answer. C-compatibility is really the most important reason. all other stuff like default access is esoteric.
o
ogoid

As every one says, the only real difference is the default access. But I particularly use struct when I don't want any sort of encapsulation with a simple data class, even if I implement some helper methods. For instance, when I need something like this:

struct myvec {
    int x;
    int y;
    int z;

    int length() {return x+y+z;}
};

+1 for giving an example of a struct with some member functions which do not feel like you've "taken away the structness".
A
Andy

For C++, there really isn't much of a difference between structs and classes. The main functional difference is that members of a struct are public by default, while they are private by default in classes. Otherwise, as far as the language is concerned, they are equivalent.

That said, I tend to use structs in C++ like I do in C#, similar to what Brian has said. Structs are simple data containers, while classes are used for objects that need to act on the data in addition to just holding on to it.


A
Alan Hinchcliffe

To answer my own question (shamelessly), As already mentioned, access privileges are the only difference between them in C++.

I tend to use a struct for data-storage only. I'll allow it to get a few helper functions if it makes working with the data easier. However as soon as the data requires flow control (i.e. getters/setters that maintain or protect an internal state) or starts acquring any major functionality (basically more object-like), it will get 'upgraded' to a class to better communicate intent.


D
Deduplicator

Structs (PODs, more generally) are handy when you're providing a C-compatible interface with a C++ implementation, since they're portable across language borders and linker formats.

If that's not a concern to you, then I suppose the use of the "struct" instead of "class" is a good communicator of intent (as @ZeroSignal said above). Structs also have more predictable copying semantics, so they're useful for data you intend to write to external media or send across the wire.

Structs are also handy for various metaprogramming tasks, like traits templates that just expose a bunch of dependent typedefs:

template <typename T> struct type_traits {
  typedef T type;
  typedef T::iterator_type iterator_type;
  ...
};

...But that's really just taking advantage of struct's default protection level being public...


That is not the correct usage of POD. A struct (or class) can be POD struct if (and only if) it contains ONLY POD members.
"predictable copying semantics": The symantics are the same as for class (and have the same problems (shallow copy)).
This post would have you believe (hopefully by accident) that all structs are PODs. This is not at all true. I hope that people are not mislead by this.
p
pasbi

As others have pointed out

both are equivalent apart from default visibility

there may be reasons to be forced to use the one or the other for whatever reason

There's a clear recommendation about when to use which from Stroustrup/Sutter:

Use class if the class has an invariant; use struct if the data members can vary independently

However, keep in mind that it is not wise to forward declare sth. as a class (class X;) and define it as struct (struct X { ... }). It may work on some linkers (e.g., g++) and may fail on others (e.g., MSVC), so you will find yourself in developer hell.


Can you describe these linker problems?
@LightnessRacesinOrbit I can't, unfortunately. I'm not even able to craft an example. The trivial class Foo; struct Foo { void bar() {} }; int main() { Foo().bar(); } not only compiles and runs with MSVC 2017, it even produces a clear warning that Foo was declared as struct but defined as class. But I also remember clearly that it cost our team half a day to find that stupid bug. I'm not sure what MSVC version we've used back then.
The linker shouldn't even know about whether you used class or struct on a forward declaration, and the two are freely interchangeable per the standard (though it is known that VS warns; I always assumed that was just to avoid apparent programmer mistakes). Something doesn't smell right here. Are you sure it wasn't an ODR violation bug?
I don't remember exactly. The problem did not occur in an application directly, but in a library which was used in a gtest. I just know that the linker produced incomprehensible errors (LNK???). Once I replaced the struct-forwards to class-forwards, the problems went away. As of today, I find it strange, too. I'd be glad if you could shed some light on it.
V
Vorac

An advantage of struct over class is that it save one line of code, if adhering to "first public members, then private". In this light, I find the keyword class useless.

Here is another reason for using only struct and never class. Some code style guidelines for C++ suggest using small letters for function macros, the rationale being that when the macro is converted to an inline function, the name shouldn't need to be changed. Same here. You have your nice C-style struct and one day, you find out you need to add a constructor, or some convenience method. Do you change it to a class? Everywhere?

Distinguishing between structs and classes is just too much hassle getting into the way of doing what we should be doing - programming. Like so many of C++'s problems it arises out of the strong desire for backwards compatibility.


Why would you need to change it to a class? Did you think that a class defined with the struct keyword can't have member functions or a constructor?
@LightnessRacesinOrbit because of 1. consistency and 2. some static analysers complain about the violation of 1.
That doesn't follow. What other "consistencies" do you adhere to? Every class with a member called joe() must be defined with class keyword? Every class with at least 4 int members must be defined with struct keyword?
@LightnessRacesinOrbit I am referring to the idiom "POD aggregates are defined with struct, aggregates with methods are defined with class". Too much hassle.
e
enigmatic

They are pretty much the same thing. Thanks to the magic of C++, a struct can hold functions, use inheritance, created using "new" and so on just like a class

The only functional difference is that a class begins with private access rights, while a struct begins with public. This is the maintain backwards compatibility with C.

In practice, I've always used structs as data holders and classes as objects.


R
Richard Chambers

Both struct and class are the same under the hood though with different defaults as to visibility, struct default is public and class default is private. You can change either one to be the other with the appropriate use of private and public. They both allow inheritance, methods, constructors, destructors, and all the rest of the goodies of an object oriented language.

However one huge difference between the two is that struct as a keyword is supported in C whereas class is not. This means that one can use a struct in an include file that can be #include into either C++ or C so long as the struct is a plain C style struct and everything else in the include file is compatible with C, i.e. no C++ specific keywords such as private, public, no methods, no inheritance, etc. etc. etc.

A C style struct can be used with other interfaces which support using C style struct to carry data back and forth over the interface.

A C style struct is a kind of template (not a C++ template but rather a pattern or stencil) that describes the layout of a memory area. Over the years interfaces usable from C and with C plug-ins (here's looking at you Java and Python and Visual Basic) have been created some of which work with C style struct.


This answer contradicts itself: They are the "same under the hood" yet there is "one huge difference". Huh? If the C++ implementation treats the struct specially to preserve compatibility as described, then they are not necessarily the same "under the hood". The rest of the description is clear and compatible with other answers and comments, but if there is a difference, then just explain that directly without having to backtrack from the opening declaration. At least provide a proper context to the first sentence like "If either type is used completely within a C++ context, then..."
The "same under the hood", the hood being C++ internals; "huge difference" above the hood, outside of C++ proper.
Here's looking at the phrase I never anticipated hearing outside of Casablanca.
@tejasvi88 Two phrases, one from Casablanca and one from The King and I. Lol.
s
sehe

Class.

Class members are private by default.

class test_one {
    int main_one();
};

Is equivalent to

class test_one {
  private:
    int main_one();
};

So if you try

int two = one.main_one();

We will get an error: main_one is private because its not accessible. We can solve it by initializing it by specifying its a public ie

class test_one {
  public:
    int main_one();
};

Struct.

A struct is a class where members are public by default.

struct test_one {
    int main_one;
};

Means main_one is private ie

class test_one {
  public:
    int main_one;
};

I use structs for data structures where the members can take any value, it's easier that way.


J
Javier

they're the same thing with different defaults (private by default for class, and public by default for struct), so in theory they're totally interchangeable.

so, if I just want to package some info to move around, I use a struct, even if i put a few methods there (but not many). If it's a mostly-opaque thing, where the main use would be via methods, and not directly to the data members, i use a full class.


a
anio

Structs by default have public access and classes by default have private access.

Personally I use structs for Data Transfer Objects or as Value Objects. When used as such I declare all members as const to prevent modification by other code.


T
Tony Delroy

Just to address this from a C++20 Standardese perspective (working from N4860)...

A class is a type. The keywords "class" and "struct" (and "union") are - in the C++ grammar - class-keys, and the only functional significance of the choice of class or struct is:

The class-key determines whether ... access is public or private by default (11.9).

Data member default accessibility

That the class keyword results in private-by-default members, and `struct keyword results in public-by-default members, is documented by the examples in 11.9.1:

class X { int a; // X::a is private by default: class used

...vs...

struct S { int a; // S::a is public by default: struct used

Base class default accessibility

1.9 also says:

In the absence of an access-specifier for a base class, public is assumed when the derived class is defined with the class-key struct and private is assumed when the class is defined with the class-key class.

Circumstances where consistent use of struct or class is required...

There's a requirement:

In a redeclaration, partial specialization, explicit specialization or explicit instantiation of a class template, the class-key shall agree in kind with the original class template declaration (9.2.8.3).

...in any elaborated-type-specifier, the enum keyword shall be used to refer to an enumeration (9.7.1), the union class-key shall be used to refer to a union (11.5), and either the class or struct class-key shall be used to refer to a non-union class (11.1).

The following example (of when consistency is not required) is provided:

struct S { } s; class S* p = &s; // OK

Still, some compilers may warn about this.

Interestingly, while the types you create with struct, class and union are all termed "classes", we have...

A standard-layout struct is a standard layout class defined with the class-key struct or the class-key class.

...so in Standardese, when there's talk of a standard-layout struct it's using "struct" to imply "not a union"s.

I'm curious if there are similar use of "struct" in other terminology, but it's too big a job to do an exhaustive search of the Standard. Comments about that welcome.


I thought there was some difference regarding the "typedef name space", where, for compatibility with C, you can write typedef struct A A and use either struct A or plain A to declare/define variables, etc., but it seems that's not the case. It seems you can use both struct or class in that way.
u
user13947194

After years of programming in C++, my main language, I come to the dead conclusion that this is another one of C++ dumb feature.

There is no real difference between the two, and no reason why I should spend extra time deciding whether I should define my entity as a struct or a class.

To answer this question, feel free to always define your entity as a struct. Members will be public by default which is the norm. But even more importantly, inheritance will be public by default. Protected inheritance, and even worse, private inheritance, are the exceptions.

I have never had a case where private inheritance was the right thing to do. Yes I tried to invent problems to use private inheritance but it didn't work. And Java, the role model of Object Oriented programming defaults to public inheritance if you don't use the accessor keywords. And by the way, Java doesn't allow accessor keywords on inherited classes, they can only be publicly inherited. So you can see, the cpp team really fell down here.

Another frustrating thing about this, is that if you define as a class and declare as a struct you get compilation warning. As though this is something that impacted the performance or accuracy of your program. One answer also noted that MSVC may propogate a compiler error instead.

Those persons that use classes when it is raining and structs when it is shining are doing so based on what they have been taught. It's not something they discovered to be true. Java does not have a pair of names for classes, and only have the class keyword. If you want a data structure, simply make all your members public and don't add functions. This works in Java and I don't see any problem. What's the problem? You need 4 or 5 characters of BOM code to determine how to interpret the context of a class entity.


It is indeed unfortunate that the correct keyword to declare a class in C++ is struct.
M
Maciek

Technically both are the same in C++ - for instance it's possible for a struct to have overloaded operators etc.

However :

I use structs when I wish to pass information of multiple types simultaneously I use classes when the I'm dealing with a "functional" object.

Hope it helps.

#include <string>
#include <map>
using namespace std;

struct student
{
    int age;
    string name;
    map<string, int> grades
};

class ClassRoom
{
    typedef map<string, student> student_map;
  public :
    student getStudentByName(string name) const 
    { student_map::const_iterator m_it = students.find(name); return m_it->second; }
  private :
    student_map students;
};

For instance, I'm returning a struct student in the get...() methods over here - enjoy.


K
Khaled Alshaya

When would you choose to use struct and when to use class in C++?

I use struct when I define functors and POD. Otherwise I use class.

// '()' is public by default!
struct mycompare : public std::binary_function<int, int, bool>
{
    bool operator()(int first, int second)
    { return first < second; }
};

class mycompare : public std::binary_function<int, int, bool>
{
public:
    bool operator()(int first, int second)
    { return first < second; }
};

This answer is showing signs of age :) std::binary_function<> is not just deprecated, c++17 even removes it.
Not a surprise really since it was written in the time of C++03, a language defined 15 years ago.
i
ivan.ukr

I use structs when I need to create POD type or functor.


H
Helping Bean

All class members are private by default and all struct members are public by default. Class has default private bases and Struct has default public bases. Struct in case of C cannot have member functions where as in case of C++ we can have member functions being added to the struct. Other than these differences, I don't find anything surprising about them.


h
harik

I use struct only when I need to hold some data without any member functions associated to it (to operate on the member data) and to access the data variables directly.

Eg: Reading/Writing data from files and socket streams etc. Passing function arguments in a structure where the function arguments are too many and function syntax looks too lengthy.

Technically there is no big difference between class and struture except default accessibility. More over it depends on programming style how you use it.


G
GaiusSensei

Want to improve this post? Provide detailed answers to this question, including citations and an explanation of why your answer is correct. Answers without enough detail may be edited or deleted.

I thought that Structs was intended as a Data Structure (like a multi-data type array of information) and classes was inteded for Code Packaging (like collections of subroutines & functions)..

:(


B
Baltimark

I never use "struct" in C++.

I can't ever imagine a scenario where you would use a struct when you want private members, unless you're willfully trying to be confusing.

It seems that using structs is more of a syntactic indication of how the data will be used, but I'd rather just make a class and try to make that explicit in the name of the class, or through comments.

E.g.

class PublicInputData {
    //data members
 };

According to me, a "syntactic indication of how data will be used" is a perfectly good reason to use a struct, especially if the alternative is to use a comment or a name in the classname.
Wouldn't declaring a struct already be pretty explicit that the members of the class will be, by default, public?