In what scenarios is it better to use a struct
vs a class
in C++?
The differences between a class
and a struct
in C++ is:
struct members and base classes/structs are public by default.
class members and base classes/struts are private by default.
Both classes and structs can have a mixture of public
, protected
and private
members, can use inheritance and can have member functions.
I would recommend you:
use struct for plain-old-data structures without any class-like features;
use class when you make use of features such as private or protected members, non-default constructors and operators, etc.
As everyone else notes there are really only two actual language differences:
struct defaults to public access and class defaults to private access.
When inheriting, struct defaults to public inheritance and class defaults to private inheritance. (Ironically, as with so many things in C++, the default is backwards: public inheritance is by far the more common choice, but people rarely declare structs just to save on typing the "public" keyword.
But the real difference in practice is between a class
/struct
that declares a constructor/destructor and one that doesn't. There are certain guarantees to a "plain-old-data" POD type, that no longer apply once you take over the class's construction. To keep this distinction clear, many people deliberately only use struct
s for POD types, and, if they are going to add any methods at all, use class
es. The difference between the two fragments below is otherwise meaningless:
class X
{
public:
// ...
};
struct X
{
// ...
};
(Incidentally, here's a thread with some good explanations about what "POD type" actually means: What are POD types in C++?)
struct
or class
has no bearing on whether your object is POD or whether you should define a copy constructor / destructor. Member functions also have no bearing on something being POD. As I re-read what you wrote, I see you aren't suggesting otherwise, but the current wording is confusing
struct
and class
and when it comes to object layout there aren't any. The POD thing also change a bit since C++11. The bullet points are correct though. it is just about the defaults when you use either keyword to define a class.
There are lots of misconceptions in the existing answers.
Both class
and struct
declare a class.
Yes, you may have to rearrange your access modifying keywords inside the class definition, depending on which keyword you used to declare the class.
But, beyond syntax, the only reason to choose one over the other is convention/style/preference.
Some people like to stick with the struct
keyword for classes without member functions, because the resulting definition "looks like" a simple structure from C.
Similarly, some people like to use the class
keyword for classes with member functions and private
data, because it says "class" on it and therefore looks like examples from their favourite book on object-oriented programming.
The reality is that this completely up to you and your team, and it'll make literally no difference whatsoever to your program.
The following two classes are absolutely equivalent in every way except their name:
struct Foo
{
int x;
};
class Bar
{
public:
int x;
};
You can even switch keywords when redeclaring:
class Foo;
struct Bar;
(although this breaks Visual Studio builds due to non-conformance, so that compiler will emit a warning when you do this.)
and the following expressions both evaluate to true:
std::is_class<Foo>::value
std::is_class<Bar>::value
Do note, though, that you can't switch the keywords when redefining; this is only because (per the one-definition rule) duplicate class definitions across translation units must "consist of the same sequence of tokens". This means you can't even exchange const int member;
with int const member;
, and has nothing to do with the semantics of class
or struct
.
class foo { public: ... };
and another can have struct foo { ... };
which would have to hold true according to the "absolutely equivalent" claim. It comes to reason that the incomplete declarations struct foo;
and class foo;
are interchangeable. These do not specify the class body, and so they speak nothing to the access layout.
Foo
and Bar
are still equivalent/identical types. I did make sure to say "when redeclaring" and give an example. Come to think of it, I'll clarify this in the answer to make sure I'm not misleading people into UB
The only time I use a struct instead of a class is when declaring a functor right before using it in a function call and want to minimize syntax for the sake of clarity. e.g.:
struct Compare { bool operator() { ... } };
std::sort(collection.begin(), collection.end(), Compare());
From the C++ FAQ Lite:
The members and base classes of a struct are public by default, while in class, they default to private. Note: you should make your base classes explicitly public, private, or protected, rather than relying on the defaults. struct and class are otherwise functionally equivalent. OK, enough of that squeaky clean techno talk. Emotionally, most developers make a strong distinction between a class and a struct. A struct simply feels like an open pile of bits with very little in the way of encapsulation or functionality. A class feels like a living and responsible member of society with intelligent services, a strong encapsulation barrier, and a well defined interface. Since that's the connotation most people already have, you should probably use the struct keyword if you have a class that has very few methods and has public data (such things do exist in well designed systems!), but otherwise you should probably use the class keyword.
One place where a struct has been helpful for me is when I have a system that's receiving fixed format messages (over say, a serial port) from another system. You can cast the stream of bytes into a struct that defines your fields, and then easily access the fields.
typedef struct
{
int messageId;
int messageCounter;
int messageData;
} tMessageType;
void processMessage(unsigned char *rawMessage)
{
tMessageType *messageFields = (tMessageType *)rawMessage;
printf("MessageId is %d\n", messageFields->messageId);
}
Obviously, this is the same thing you would do in C, but I find that the overhead of having to decode the message into a class is usually not worth it.
operator >>
on a class instead of writing the processMessage
function, which would make your C++ look more like proper C++ and less like C.
void*
system calls, and passed between C and C++,I say win-win?
char
type, which are exempt from aliasing. However, there is still a problem, albeit a different one: Casting a char*
to a different type, if there was not really any object of the latter type already initialised at that address, is UB as it violates lifetime rules. Afaik, even if the destination type is trivially constructible, just having allocated memory is not sufficient for C++ to formally allow treating that memory as that type.
You can use "struct" in C++ if you are writing a library whose internals are C++ but the API can be called by either C or C++ code. You simply make a single header that contains structs and global API functions that you expose to both C and C++ code as this:
// C access Header to a C++ library
#ifdef __cpp
extern "C" {
#endif
// Put your C struct's here
struct foo
{
...
};
// NOTE: the typedef is used because C does not automatically generate
// a typedef with the same name as a struct like C++.
typedef struct foo foo;
// Put your C API functions here
void bar(foo *fun);
#ifdef __cpp
}
#endif
Then you can write a function bar() in a C++ file using C++ code and make it callable from C and the two worlds can share data through the declared struct's. There are other caveats of course when mixing C and C++ but this is a simplified example.
As every one says, the only real difference is the default access. But I particularly use struct when I don't want any sort of encapsulation with a simple data class, even if I implement some helper methods. For instance, when I need something like this:
struct myvec {
int x;
int y;
int z;
int length() {return x+y+z;}
};
For C++, there really isn't much of a difference between structs and classes. The main functional difference is that members of a struct are public by default, while they are private by default in classes. Otherwise, as far as the language is concerned, they are equivalent.
That said, I tend to use structs in C++ like I do in C#, similar to what Brian has said. Structs are simple data containers, while classes are used for objects that need to act on the data in addition to just holding on to it.
To answer my own question (shamelessly), As already mentioned, access privileges are the only difference between them in C++.
I tend to use a struct for data-storage only. I'll allow it to get a few helper functions if it makes working with the data easier. However as soon as the data requires flow control (i.e. getters/setters that maintain or protect an internal state) or starts acquring any major functionality (basically more object-like), it will get 'upgraded' to a class to better communicate intent.
Structs (PODs, more generally) are handy when you're providing a C-compatible interface with a C++ implementation, since they're portable across language borders and linker formats.
If that's not a concern to you, then I suppose the use of the "struct" instead of "class" is a good communicator of intent (as @ZeroSignal said above). Structs also have more predictable copying semantics, so they're useful for data you intend to write to external media or send across the wire.
Structs are also handy for various metaprogramming tasks, like traits templates that just expose a bunch of dependent typedefs:
template <typename T> struct type_traits {
typedef T type;
typedef T::iterator_type iterator_type;
...
};
...But that's really just taking advantage of struct's default protection level being public...
As others have pointed out
both are equivalent apart from default visibility
there may be reasons to be forced to use the one or the other for whatever reason
There's a clear recommendation about when to use which from Stroustrup/Sutter:
Use class if the class has an invariant; use struct if the data members can vary independently
However, keep in mind that it is not wise to forward declare sth. as a class (class X;
) and define it as struct (struct X { ... }
). It may work on some linkers (e.g., g++) and may fail on others (e.g., MSVC), so you will find yourself in developer hell.
class Foo; struct Foo { void bar() {} }; int main() { Foo().bar(); }
not only compiles and runs with MSVC 2017, it even produces a clear warning that Foo
was declared as struct
but defined as class
. But I also remember clearly that it cost our team half a day to find that stupid bug. I'm not sure what MSVC version we've used back then.
class
or struct
on a forward declaration, and the two are freely interchangeable per the standard (though it is known that VS warns; I always assumed that was just to avoid apparent programmer mistakes). Something doesn't smell right here. Are you sure it wasn't an ODR violation bug?
struct
-forwards to class
-forwards, the problems went away. As of today, I find it strange, too. I'd be glad if you could shed some light on it.
An advantage of struct
over class
is that it save one line of code, if adhering to "first public members, then private". In this light, I find the keyword class
useless.
Here is another reason for using only struct
and never class
. Some code style guidelines for C++ suggest using small letters for function macros, the rationale being that when the macro is converted to an inline function, the name shouldn't need to be changed. Same here. You have your nice C-style struct and one day, you find out you need to add a constructor, or some convenience method. Do you change it to a class
? Everywhere?
Distinguishing between struct
s and class
es is just too much hassle getting into the way of doing what we should be doing - programming. Like so many of C++'s problems it arises out of the strong desire for backwards compatibility.
class
? Did you think that a class defined with the struct
keyword can't have member functions or a constructor?
joe()
must be defined with class
keyword? Every class with at least 4 int
members must be defined with struct
keyword?
struct
, aggregates with methods are defined with class
". Too much hassle.
They are pretty much the same thing. Thanks to the magic of C++, a struct can hold functions, use inheritance, created using "new" and so on just like a class
The only functional difference is that a class begins with private access rights, while a struct begins with public. This is the maintain backwards compatibility with C.
In practice, I've always used structs as data holders and classes as objects.
Both struct
and class
are the same under the hood though with different defaults as to visibility, struct
default is public and class
default is private. You can change either one to be the other with the appropriate use of private
and public
. They both allow inheritance, methods, constructors, destructors, and all the rest of the goodies of an object oriented language.
However one huge difference between the two is that struct
as a keyword is supported in C whereas class
is not. This means that one can use a struct
in an include file that can be #include
into either C++ or C so long as the struct
is a plain C style struct
and everything else in the include file is compatible with C, i.e. no C++ specific keywords such as private
, public
, no methods, no inheritance, etc. etc. etc.
A C style struct
can be used with other interfaces which support using C style struct
to carry data back and forth over the interface.
A C style struct
is a kind of template (not a C++ template but rather a pattern or stencil) that describes the layout of a memory area. Over the years interfaces usable from C and with C plug-ins (here's looking at you Java and Python and Visual Basic) have been created some of which work with C style struct
.
Class.
Class members are private by default.
class test_one {
int main_one();
};
Is equivalent to
class test_one {
private:
int main_one();
};
So if you try
int two = one.main_one();
We will get an error: main_one is private
because its not accessible. We can solve it by initializing it by specifying its a public ie
class test_one {
public:
int main_one();
};
Struct.
A struct is a class where members are public by default.
struct test_one {
int main_one;
};
Means main_one
is private ie
class test_one {
public:
int main_one;
};
I use structs for data structures where the members can take any value, it's easier that way.
they're the same thing with different defaults (private by default for class
, and public by default for struct
), so in theory they're totally interchangeable.
so, if I just want to package some info to move around, I use a struct, even if i put a few methods there (but not many). If it's a mostly-opaque thing, where the main use would be via methods, and not directly to the data members, i use a full class.
Structs by default have public access and classes by default have private access.
Personally I use structs for Data Transfer Objects or as Value Objects. When used as such I declare all members as const to prevent modification by other code.
Just to address this from a C++20 Standardese perspective (working from N4860)...
A class is a type. The keywords "class
" and "struct
" (and "union
") are - in the C++ grammar - class-keys, and the only functional significance of the choice of class
or struct
is:
The class-key determines whether ... access is public or private by default (11.9).
Data member default accessibility
That the class
keyword results in private-by-default members, and `struct keyword results in public-by-default members, is documented by the examples in 11.9.1:
class X { int a; // X::a is private by default: class used
...vs...
struct S { int a; // S::a is public by default: struct used
Base class default accessibility
1.9 also says:
In the absence of an access-specifier for a base class, public is assumed when the derived class is defined with the class-key struct and private is assumed when the class is defined with the class-key class.
Circumstances where consistent use of struct or class is required...
There's a requirement:
In a redeclaration, partial specialization, explicit specialization or explicit instantiation of a class template, the class-key shall agree in kind with the original class template declaration (9.2.8.3).
...in any elaborated-type-specifier, the enum keyword shall be used to refer to an enumeration (9.7.1), the union class-key shall be used to refer to a union (11.5), and either the class or struct class-key shall be used to refer to a non-union class (11.1).
The following example (of when consistency is not required) is provided:
struct S { } s; class S* p = &s; // OK
Still, some compilers may warn about this.
Interestingly, while the types you create with struct
, class
and union
are all termed "classes", we have...
A standard-layout struct is a standard layout class defined with the class-key struct or the class-key class.
...so in Standardese, when there's talk of a standard-layout struct it's using "struct" to imply "not a union"s.
I'm curious if there are similar use of "struct" in other terminology, but it's too big a job to do an exhaustive search of the Standard. Comments about that welcome.
typedef struct A A
and use either struct A
or plain A
to declare/define variables, etc., but it seems that's not the case. It seems you can use both struct
or class
in that way.
After years of programming in C++, my main language, I come to the dead conclusion that this is another one of C++ dumb feature.
There is no real difference between the two, and no reason why I should spend extra time deciding whether I should define my entity as a struct or a class.
To answer this question, feel free to always define your entity as a struct. Members will be public by default which is the norm. But even more importantly, inheritance will be public by default. Protected inheritance, and even worse, private inheritance, are the exceptions.
I have never had a case where private inheritance was the right thing to do. Yes I tried to invent problems to use private inheritance but it didn't work. And Java, the role model of Object Oriented programming defaults to public inheritance if you don't use the accessor keywords. And by the way, Java doesn't allow accessor keywords on inherited classes, they can only be publicly inherited. So you can see, the cpp team really fell down here.
Another frustrating thing about this, is that if you define as a class and declare as a struct you get compilation warning. As though this is something that impacted the performance or accuracy of your program. One answer also noted that MSVC may propogate a compiler error instead.
Those persons that use classes when it is raining and structs when it is shining are doing so based on what they have been taught. It's not something they discovered to be true. Java does not have a pair of names for classes, and only have the class keyword. If you want a data structure, simply make all your members public and don't add functions. This works in Java and I don't see any problem. What's the problem? You need 4 or 5 characters of BOM code to determine how to interpret the context of a class entity.
struct
.
Technically both are the same in C++ - for instance it's possible for a struct to have overloaded operators etc.
However :
I use structs when I wish to pass information of multiple types simultaneously I use classes when the I'm dealing with a "functional" object.
Hope it helps.
#include <string>
#include <map>
using namespace std;
struct student
{
int age;
string name;
map<string, int> grades
};
class ClassRoom
{
typedef map<string, student> student_map;
public :
student getStudentByName(string name) const
{ student_map::const_iterator m_it = students.find(name); return m_it->second; }
private :
student_map students;
};
For instance, I'm returning a struct student in the get...() methods over here - enjoy.
When would you choose to use struct and when to use class in C++?
I use struct
when I define functors
and POD
. Otherwise I use class
.
// '()' is public by default!
struct mycompare : public std::binary_function<int, int, bool>
{
bool operator()(int first, int second)
{ return first < second; }
};
class mycompare : public std::binary_function<int, int, bool>
{
public:
bool operator()(int first, int second)
{ return first < second; }
};
std::binary_function<>
is not just deprecated, c++17 even removes it.
I use structs when I need to create POD type or functor.
All class members are private by default and all struct members are public by default. Class has default private bases and Struct has default public bases. Struct in case of C cannot have member functions where as in case of C++ we can have member functions being added to the struct. Other than these differences, I don't find anything surprising about them.
I use struct only when I need to hold some data without any member functions associated to it (to operate on the member data) and to access the data variables directly.
Eg: Reading/Writing data from files and socket streams etc. Passing function arguments in a structure where the function arguments are too many and function syntax looks too lengthy.
Technically there is no big difference between class and struture except default accessibility. More over it depends on programming style how you use it.
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I thought that Structs was intended as a Data Structure (like a multi-data type array of information) and classes was inteded for Code Packaging (like collections of subroutines & functions)..
:(
I never use "struct" in C++.
I can't ever imagine a scenario where you would use a struct when you want private members, unless you're willfully trying to be confusing.
It seems that using structs is more of a syntactic indication of how the data will be used, but I'd rather just make a class and try to make that explicit in the name of the class, or through comments.
E.g.
class PublicInputData {
//data members
};
struct
already be pretty explicit that the members of the class will be, by default, public?
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