I'm trying to use matplotlib
to read in an RGB image and convert it to grayscale.
In matlab I use this:
img = rgb2gray(imread('image.png'));
In the matplotlib tutorial they don't cover it. They just read in the image
import matplotlib.image as mpimg
img = mpimg.imread('image.png')
and then they slice the array, but that's not the same thing as converting RGB to grayscale from what I understand.
lum_img = img[:,:,0]
I find it hard to believe that numpy or matplotlib doesn't have a built-in function to convert from rgb to gray. Isn't this a common operation in image processing?
I wrote a very simple function that works with the image imported using imread
in 5 minutes. It's horribly inefficient, but that's why I was hoping for a professional implementation built-in.
Sebastian has improved my function, but I'm still hoping to find the built-in one.
matlab's (NTSC/PAL) implementation:
import numpy as np
def rgb2gray(rgb):
r, g, b = rgb[:,:,0], rgb[:,:,1], rgb[:,:,2]
gray = 0.2989 * r + 0.5870 * g + 0.1140 * b
return gray
gray = np.mean(rgb, -1)
. Maybe rgb[...,:3]
there if it is actually rgba.
gray = np.mean(rgb, -1)
works fine. thanks. Is there any reason not to use this? Why would I use the solutions in the answers below instead?
np.mean(rgb, -1)
.
0.2989 * R + 0.5870 * G + 0.1140 * B
I'm assuming that it's the standard way of doing it.
How about doing it with Pillow:
from PIL import Image
img = Image.open('image.png').convert('L')
img.save('greyscale.png')
If an alpha (transparency) channel is present in the input image and should be preserved, use mode LA
:
img = Image.open('image.png').convert('LA')
Using matplotlib and the formula
Y' = 0.2989 R + 0.5870 G + 0.1140 B
you could do:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.image as mpimg
def rgb2gray(rgb):
return np.dot(rgb[...,:3], [0.2989, 0.5870, 0.1140])
img = mpimg.imread('image.png')
gray = rgb2gray(img)
plt.imshow(gray, cmap=plt.get_cmap('gray'), vmin=0, vmax=1)
plt.show()
You can also use scikit-image, which provides some functions to convert an image in ndarray
, like rgb2gray
.
from skimage import color
from skimage import io
img = color.rgb2gray(io.imread('image.png'))
Notes: The weights used in this conversion are calibrated for contemporary CRT phosphors: Y = 0.2125 R + 0.7154 G + 0.0721 B
Alternatively, you can read image in grayscale by:
from skimage import io
img = io.imread('image.png', as_gray=True)
cmap
as gray' then only the image is shown as gray in
pyplot.imshow()` ? Any thoughts ? Where am I wrong?
Three of the suggested methods were tested for speed with 1000 RGBA PNG images (224 x 256 pixels) running with Python 3.5 on Ubuntu 16.04 LTS (Xeon E5 2670 with SSD).
Average run times
pil :
1.037 seconds
scipy:
1.040 seconds
sk :
2.120 seconds
PIL and SciPy gave identical numpy
arrays (ranging from 0 to 255). SkImage gives arrays from 0 to 1. In addition the colors are converted slightly different, see the example from the CUB-200 dataset.
https://i.stack.imgur.com/ZLd5vm.png
https://i.stack.imgur.com/eQ4KIm.png
https://i.stack.imgur.com/DTjVSm.png
https://i.stack.imgur.com/43cy1m.png
https://i.stack.imgur.com/f5fy9m.png
Code
Performance run_times = dict(sk=list(), pil=list(), scipy=list()) for t in range(100): start_time = time.time() for i in range(1000): z = random.choice(filenames_png) img = skimage.color.rgb2gray(skimage.io.imread(z)) run_times['sk'].append(time.time() - start_time) start_time = time.time() for i in range(1000): z = random.choice(filenames_png) img = np.array(Image.open(z).convert('L')) run_times['pil'].append(time.time() - start_time) start_time = time.time() for i in range(1000): z = random.choice(filenames_png) img = scipy.ndimage.imread(z, mode='L') run_times['scipy'].append(time.time() - start_time) for k, v in run_times.items(): print('{:5}: {:0.3f} seconds'.format(k, sum(v) / len(v))) Output z = 'Cardinal_0007_3025810472.jpg' img1 = skimage.color.rgb2gray(skimage.io.imread(z)) * 255 IPython.display.display(PIL.Image.fromarray(img1).convert('RGB')) img2 = np.array(Image.open(z).convert('L')) IPython.display.display(PIL.Image.fromarray(img2)) img3 = scipy.ndimage.imread(z, mode='L') IPython.display.display(PIL.Image.fromarray(img3)) Comparison img_diff = np.ndarray(shape=img1.shape, dtype='float32') img_diff.fill(128) img_diff += (img1 - img3) img_diff -= img_diff.min() img_diff *= (255/img_diff.max()) IPython.display.display(PIL.Image.fromarray(img_diff).convert('RGB')) Imports import skimage.color import skimage.io import random import time from PIL import Image import numpy as np import scipy.ndimage import IPython.display Versions skimage.version 0.13.0 scipy.version 0.19.1 np.version 1.13.1
You can always read the image file as grayscale right from the beginning using imread
from OpenCV:
img = cv2.imread('messi5.jpg', 0)
Furthermore, in case you want to read the image as RGB, do some processing and then convert to Gray Scale you could use cvtcolor
from OpenCV:
gray_image = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
0
flag is cv2.CV_LOAD_IMAGE_GRAYSCALE
.
The fastest and current way is to use Pillow, installed via pip install Pillow
.
The code is then:
from PIL import Image
img = Image.open('input_file.jpg').convert('L')
img.save('output_file.jpg')
convert
returns a converted copy of the image
The tutorial is cheating because it is starting with a greyscale image encoded in RGB, so they are just slicing a single color channel and treating it as greyscale. The basic steps you need to do are to transform from the RGB colorspace to a colorspace that encodes with something approximating the luma/chroma model, such as YUV/YIQ or HSL/HSV, then slice off the luma-like channel and use that as your greyscale image. matplotlib
does not appear to provide a mechanism to convert to YUV/YIQ, but it does let you convert to HSV.
Try using matplotlib.colors.rgb_to_hsv(img)
then slicing the last value (V) from the array for your grayscale. It's not quite the same as a luma value, but it means you can do it all in matplotlib
.
Background:
http://matplotlib.sourceforge.net/api/colors_api.html
http://en.wikipedia.org/wiki/HSL_and_HSV
Alternatively, you could use PIL or the builtin colorsys.rgb_to_yiq()
to convert to a colorspace with a true luma value. You could also go all in and roll your own luma-only converter, though that's probably overkill.
Using this formula
Y' = 0.299 R + 0.587 G + 0.114 B
We can do
import imageio
import numpy as np
import matplotlib.pyplot as plt
pic = imageio.imread('(image)')
gray = lambda rgb : np.dot(rgb[... , :3] , [0.299 , 0.587, 0.114])
gray = gray(pic)
plt.imshow(gray, cmap = plt.get_cmap(name = 'gray'))
However, the GIMP converting color to grayscale image software has three algorithms to do the task.
you could do:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.image as mpimg
def rgb_to_gray(img):
grayImage = np.zeros(img.shape)
R = np.array(img[:, :, 0])
G = np.array(img[:, :, 1])
B = np.array(img[:, :, 2])
R = (R *.299)
G = (G *.587)
B = (B *.114)
Avg = (R+G+B)
grayImage = img.copy()
for i in range(3):
grayImage[:,:,i] = Avg
return grayImage
image = mpimg.imread("your_image.png")
grayImage = rgb_to_gray(image)
plt.imshow(grayImage)
plt.show()
If you're using NumPy/SciPy already you may as well use:
scipy.ndimage.imread(file_name, mode='L')
scipy.ndimage.imread()
and scipy.misc.imread()
are formally deprecated in SciPy 1.0.0 and will be permanently removed in SciPy 1.2.0. While SciPy's documentation recommends imageio.imread()
as a suitable replacement, this function's API is bare bones to the point of absurdity. It provides no support for grayscale conversion and thus remains unsuitable for many applications – including ours. </sigh>
Use img.Convert(), supports “L”, “RGB” and “CMYK.” mode
import numpy as np
from PIL import Image
img = Image.open("IMG/center_2018_02_03_00_34_32_784.jpg")
img.convert('L')
print np.array(img)
Output:
[[135 123 134 ..., 30 3 14]
[137 130 137 ..., 9 20 13]
[170 177 183 ..., 14 10 250]
...,
[112 99 91 ..., 90 88 80]
[ 95 103 111 ..., 102 85 103]
[112 96 86 ..., 182 148 114]]
img = img.convert('L')
?
I came to this question via Google, searching for a way to convert an already loaded image to grayscale.
Here is a way to do it with SciPy:
import scipy.misc
import scipy.ndimage
# Load an example image
# Use scipy.ndimage.imread(file_name, mode='L') if you have your own
img = scipy.misc.face()
# Convert the image
R = img[:, :, 0]
G = img[:, :, 1]
B = img[:, :, 2]
img_gray = R * 299. / 1000 + G * 587. / 1000 + B * 114. / 1000
# Show the image
scipy.misc.imshow(img_gray)
img_gray = numpy.average(img, weights=[0.299, 0.587, 0.114], axis=2)
numpy.average
is a bit faster but not practically different. Your solution is clear and has relevant information about R,G,B, so I would keep it. My comment was more of an additional option, not a replacement.
scipy.ndimage.imread()
and scipy.misc.imread()
are formally deprecated in SciPy 1.0.0 and will be permanently removed in SciPy 1.2.0. You probably just want to use Pillow's builtin grayscale conversion support (ala unutbu's answer), instead.
With OpenCV its simple:
import cv2
im = cv2.imread("flower.jpg")
# To Grayscale
im = cv2.cvtColor(im, cv2.COLOR_BGR2GRAY)
cv2.imwrite("grayscale.jpg", im)
# To Black & White
im = cv2.threshold(im, 127, 255, cv2.THRESH_BINARY)[1]
cv2.imwrite("black-white.jpg", im)
https://i.stack.imgur.com/J4eEv.png
When the values in a pixel across all 3 color channels (RGB) are same then that pixel will always be in grayscale format.
One of a simple & intuitive method to convert a RGB image to Grayscale is by taking the mean of all color channels in each pixel and assigning the value back to that pixel.
import numpy as np
from PIL import Image
img=np.array(Image.open('sample.jpg')) #Input - Color image
gray_img=img.copy()
for clr in range(img.shape[2]):
gray_img[:,:,clr]=img.mean(axis=2) #Take mean of all 3 color channels of each pixel and assign it back to that pixel(in copied image)
#plt.imshow(gray_img) #Result - Grayscale image
https://i.stack.imgur.com/0F6KF.jpg
https://i.stack.imgur.com/Xy0hW.jpg
image=myCamera.getImage().crop(xx,xx,xx,xx).scale(xx,xx).greyscale()
You can use greyscale()
directly for the transformation.
Success story sharing
matplotlib
for some other reason, he should be able to use the builtincolorsys.rgb_to_yiq()
to transform plus a slice to get just the luma channel..convert('LA')
? why not.convert('gray')
? Seems needlessly cryptic. The PIL documentation doesn't mention anything about 'LA' for the convert function.cannot write mode LA as JPEG
, I needed to use L mode not LAimg = Image.open('image.png').convert('LA')
needs to beimg = Image.open('image.png').convert('L')
LA
mode has luminosity (brightness) and alpha. If you useLA
mode, thengreyscale.png
will be an RGBA image with the alpha channel ofimage.png
preserved. If you useL
mode, thengreyscale.png
will be an RGB image (with no alpha).