This may be simple, but I looked around and couldn't find an answer. What's the best way to reference a single item in a list from a Django template?
In other words, how do I do the equivalent of {{ data[0] }}
within the template language?
A better way: custom template filter: https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
such as get my_list[x] in templates:
in template
{% load index %}
{{ my_list|index:x }}
templatetags/index.py
from django import template
register = template.Library()
@register.filter
def index(indexable, i):
return indexable[i]
if my_list = [['a','b','c'], ['d','e','f']]
, you can use {{ my_list|index:x|index:y }}
in template to get my_list[x][y]
It works fine with "for"
{{ my_list|index:forloop.counter0 }}
Tested and works well ^_^
{{ data.0 }}
should work.
Let's say you wrote data.obj
django tries data.obj
and data.obj()
. If they don't work it tries data["obj"]
. In your case data[0]
can be written as {{ data.0 }}
. But I recommend you to pull data[0]
in the view and send it as separate variable.
@jennifer06262016, you can definitely add another filter to return the objects inside a django Queryset.
@register.filter
def get_item(Queryset):
return Queryset.your_item_key
In that case, you would type something like this {{ Queryset|index:x|get_item }} into your template to access some dictionary object. It works for me.
Success story sharing
{{ data.foo }}
, wherefoo
is a variable with an index value in it and not a property name.