I can set a radio button to checked fine, but what I want to do is setup a sort of 'listener' that activates when a certain radio button is checked.
Take, for example the following code:
$("#element").click(function()
{
$('#radio_button').attr("checked", "checked");
});
it adds a checked attribute and all is well, but how would I go about adding an alert. For example, that pops up when the radio button is checked without the help of the click function?
Monitoring when a radio button is unchecked
stackoverflow.com/questions/5824639/…
$('#element').click(function() {
if($('#radio_button').is(':checked')) { alert("it's checked"); }
});
If you have a group of radio buttons sharing the same name attribute and upon submit or some event you want to check if one of these radio buttons was checked, you can do this simply by the following code :
$(document).ready(function(){
$('#submit_button').click(function() {
if (!$("input[name='name']:checked").val()) {
alert('Nothing is checked!');
return false;
}
else {
alert('One of the radio buttons is checked!');
}
});
});
$('#myform').submit(function(event){ if (!$(this).find("input[name='name']:checked").val()) {
As Parag's solution threw an error for me, here's my solution (combining David Hedlund's and Parag's):
if (!$("input[name='name']").is(':checked')) {
alert('Nothing is checked!');
}
else {
alert('One of the radio buttons is checked!');
}
This worked fine for me!
You'd have to bind the click event of the checkbox, as the change event doesn't work in IE.
$('#radio_button').click(function(){
// if ($(this).is(':checked')) alert('is checked');
alert('check-checky-check was changed');
});
Now when you programmatically change the state, you have to trigger this event also:
$('#radio_button').attr("checked", "checked");
$('#radio_button').click();
//Check through class
if($("input:radio[class='className']").is(":checked")) {
//write your code
}
//Check through name
if($("input:radio[name='Name']").is(":checked")) {
//write your code
}
//Check through data
if($("input:radio[data-name='value']").is(":checked")) {
//write your code
}
Another way is to use prop
(jQuery >= 1.6):
$("input[type=radio]").click(function () {
if($(this).prop("checked")) { alert("checked!"); }
});
.prop()
is much faster, and simply easier to type.
The solution will be simple, As you just need 'listeners' when a certain radio button is checked. Do it :-
if($('#yourRadioButtonId').is(':checked')){
// Do your listener's stuff here.
}
Working with all types of Radio Buttons and Browsers
if($('#radio_button_id')[0].checked) {
alert("radiobutton checked")
}
else{
alert("not checked");
}
... Thanks guys... all I needed was the 'value' of the checked radio button where each radio button in the set had a different id...
var user_cat = $("input[name='user_cat']:checked").val();
works for me...
If you don't want a click function use Jquery change function
$('#radio_button :checked').live('change',function(){
alert('Something is checked.');
});
This should be the answer that you are looking for. if you are using Jquery version above 1.9.1 try to use on as live function had been deprecated.
dynamic generated Radio Button Check radio get value
$("input:radio[name=radiobuttonname:checked").val();
On change dynamic Radio button
$('input[name^="radioname"]').change(function () {if (this.value == 2) { }else{}});
$('.radio-button-class-name').is('checked') didn't work for me, but the next code worked well:
if(typeof $('.radio-button-class-name:checked').val() !== 'undefined'){
// radio button is checked
}
$('.radio-button-class-name').first().is(':checked')
should have worked.
try this
if($('input[name="radiobutton"]:checked').length == 0) {
alert("Radio buttons are not checked");
}
jQuery is still popular, but if you want to have no dependencies, see below. Short & clear function to find out if radio button is checked on ES-2015:
function getValueFromRadioButton( name ){ return [...document.getElementsByName(name)] .reduce( (rez, btn) => (btn.checked ? btn.value : rez), null) } console.log( getValueFromRadioButton('payment') );
ULTIMATE SOLUTION Detecting if a radio button has been checked using onChang method JQUERY > 3.6
$('input[type=radio][name=YourRadioName]').change(()=>{
alert("Hello"); });
Getting the value of the clicked radio button
var radioval=$('input[type=radio][name=YourRadioName]:checked').val();
Try this:
alert($('#radiobutton')[0].checked)
This will work in all versions of jquery.
//-- Check if there's no checked radio button
if ($('#radio_button').is(':checked') === false ) {
//-- if none, Do something here
}
To activate some function when a certain radio button is checked.
// get it from your form or parent id
if ($('#your_form').find('[name="radio_name"]').is(':checked') === false ) {
$('#your_form').find('[name="radio_name"]').filter('[value=' + checked_value + ']').prop('checked', true);
}
your html
$('document').ready(function() { var checked_value = 'checked'; if($("#your_form").find('[name="radio_name"]').is(":checked") === false) { $("#your_form") .find('[name="radio_name"]') .filter("[value=" + checked_value + "]") .prop("checked", true); } } )
$("#radio_1").prop("checked", true);
For versions of jQuery prior to 1.6, use:
$("#radio_1").attr('checked', 'checked');
checked
property, instead of querying it.
Success story sharing
('#radio_button').click
is withoutclick
?if ($('#radio_button').is(':checked'))) { alert("it's checked"); }
- you forgot the jQuery $ sign and then need to wrap it all in some more parenthesis.