What does Record<K, T>
mean in Typescript?
Typescript 2.1 introduced the Record
type, describing it in an example:
// For every properties K of type T, transform it to U
function mapObject
see Typescript 2.1
And the Advanced Types page mentions Record
under the Mapped Types heading alongside Readonly
, Partial
, and Pick
, in what appears to be its definition:
type Record
Readonly, Partial and Pick are homomorphic whereas Record is not. One clue that Record is not homomorphic is that it doesn’t take an input type to copy properties from: type ThreeStringProps = Record<'prop1' | 'prop2' | 'prop3', string>
And that's it. Besides the above quotes, there is no other mention of Record
on typescriptlang.org.
Questions
Can someone give a simple definition of what Record is? Is Record
Can someone give a simple definition of what Record is?
A Record<K, T>
is an object type whose property keys are K
and whose property values are T
. That is, keyof Record<K, T>
is equivalent to K
, and Record<K, T>[K]
is (basically) equivalent to T
.
Is Record
As you note, K
has a purpose... to limit the property keys to particular values. If you want to accept all possible string-valued keys, you could do something like Record<string, T>
, but the idiomatic way of doing that is to use an index signature like { [k: string]: T }
.
Does the K generic forbid additional keys on the object that are not K, or does it allow them and just indicate that their properties are not transformed to T?
It doesn't exactly "forbid" additional keys: after all, a value is generally allowed to have properties not explicitly mentioned in its type... but it wouldn't recognize that such properties exist:
declare const x: Record<"a", string>;
x.b; // error, Property 'b' does not exist on type 'Record<"a", string>'
and it would treat them as excess properties which are sometimes rejected:
declare function acceptR(x: Record<"a", string>): void;
acceptR({a: "hey", b: "you"}); // error, Object literal may only specify known properties
and sometimes accepted:
const y = {a: "hey", b: "you"};
acceptR(y); // okay
With the given example: type ThreeStringProps = Record<'prop1' | 'prop2' | 'prop3', string> Is it exactly the same as this?: type ThreeStringProps = {prop1: string, prop2: string, prop3: string}
Yes!
Hope that helps. Good luck!
A Record
lets you create a new type from a Union. The values in the Union are used as attributes of the new type.
For example, say I have a Union like this:
type CatNames = "miffy" | "boris" | "mordred";
Now I want to create an object that contains information about all the cats, I can create a new type using the values in the CatNames
union as keys.
type CatList = Record<CatNames, {age: number}>
If I want to satisfy this CatList
, I must create an object like this:
const cats: CatList = {
miffy: { age:99 },
boris: { age:16 },
mordred: { age:600 }
}
You get very strong type safety:
If I forget a cat, I get an error.
If I add a cat that's not allowed, I get an error.
If I later change CatNames, I get an error. This is especially useful because CatNames is likely imported from another file, and likely used in many places.
Real-world React example.
I used this recently to create a Status
component. The component would receive a status
prop, and then render an icon. I've simplified the code quite a lot here for illustrative purposes
I had a union like this:
type Statuses = "failed" | "complete";
I used this to create an object like this:
const icons: Record<
Statuses,
{ iconType: IconTypes; iconColor: IconColors }
> = {
failed: {
iconType: "warning",
iconColor: "red"
},
complete: {
iconType: "check",
iconColor: "green"
};
I could then render by destructuring an element from the object into props, like so:
const Status = ({status}) => <Icon {...icons[status]} />
If the Statuses
union is later extended or changed, I know my Status component will fail to compile and I'll get an error that I can fix immediately. This allows me to add additional error states to the app.
Note that the actual app had dozens of error states that were referenced in multiple places, so this type safety was extremely useful.
type Statuses
lives in typings NOT defined by you? Otherwise I can see something like an interface with an enum being a better fit right?
Dictionary<enum, additional_metadata>
. The Record type is a great way to represent that enum + metadata pattern.
const bla: CatNames = "miffy";
works. TS describes the |
as a union type, so only one is needed, but the record needs all. Very confusing. JS with TS is still a mess.
Success story sharing
Record<string, V>
to mean{[x: string]: V}
if you want; I've probably even done this myself. The index signature version is more direct: they are the same type, but the former is a type alias of a mapped type which evaluates to an index signature, while the latter is just the index signature directly. All else being equal, I'd recommend the latter. Similarly I wouldn't useRecord<"a", string>
in place of{a: string}
unless there were some other compelling contextual reason do to so.Record<string, V>
only makes sense if you already know how index signatures work in TypeScript. E.g., givenx: Record<string, string>
,x.foo
will apparently be astring
at compile time, but in actuality is likely to bestring | undefined
. This is a gap in how--strictNullChecks
works (see #13778). I'd rather have newcomers deal with{[x: string]: V}
directly instead of expecting them to follow the chain fromRecord<string, V>
through{[P in string]: V}
to the index signature behavior.