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Is it expensive to use try-catch blocks even if an exception is never thrown?

We know that it is expensive to catch exceptions. But, is it also expensive to use a try-catch block in Java even if an exception is never thrown?

I found the Stack Overflow question/answer Why are try blocks expensive?, but it is for .NET.

There really is no point to this question. Try..catch has a very specific purpose. If you need it, you need it. In any case, what point is a try without a catch?
try { /* do stuff */ } finally { /* make sure to release resources */ } is legal and useful
That cost has to be weighed against the benefits. It doesn't stand alone. In any case, expensive is relative, and until you know that you can't do it, it makes sense to use the most obvious method rather than not do something because it might save you a millisecond or two over the course of an hour of program execution.
I hope this isn't a lead to a "let's-reinvent-error-codes" type situation...
@SAFX: with Java7 you can even get rid of the finally block using a try-with-resources

P
Patashu

try has almost no expense at all. Instead of doing the work of setting up the try at runtime, the code's metadata is structured at compile time such that when an exception is thrown, it now does a relatively expensive operation of walking up the stack and seeing if any try blocks exist that would catch this exception. From a layman's perspective, try may as well be free. It's actually throwing the exception that costs you - but unless you're throwing hundreds or thousands of exceptions, you still won't notice the cost.

try has some minor costs associated with it. Java cannot do some optimizations on code in a try block that it would otherwise do. For example, Java will often re-arrange instructions in a method to make it run faster - but Java also needs to guarantee that if an exception is thrown, the method's execution is observed as though its statements, as written in the source code, executed in order up to some line.

Because in a try block an exception can be thrown (at any line in the try block! Some exceptions are thrown asynchronously, such as by calling stop on a Thread (which is deprecated), and even besides that OutOfMemoryError can happen almost anywhere) and yet it can be caught and code continue to execute afterwards in the same method, it is more difficult to reason about optimizations that can be made, so they are less likely to happen. (Someone would have to program the compiler to do them, reason about and guarantee correctness, etc. It'd be a big pain for something meant to be 'exceptional') But again, in practice you won't notice things like this.


Some exceptions are thrown asynchronously, they are not async but thrown in safe points. and this part try has some minor costs associated with it. Java cannot do some optimizations on code in a try block that it would otherwise do does need a serious reference. At some point the code is very likely to be within try/catch block. It might be true that try/catch block would be harder to be inlined and building proper lattice for the result but the part w/ the rearrange is ambiguous.
Does a try...finally block without catch also prevent some optimizations?
@Patashu "It's actually throwing the exception that costs you" Technically, throwing the exception is not expensive; instantiating the Exception object is what takes most of the time.
m
meriton

Let's measure it, shall we?

public abstract class Benchmark {

    final String name;

    public Benchmark(String name) {
        this.name = name;
    }

    abstract int run(int iterations) throws Throwable;

    private BigDecimal time() {
        try {
            int nextI = 1;
            int i;
            long duration;
            do {
                i = nextI;
                long start = System.nanoTime();
                run(i);
                duration = System.nanoTime() - start;
                nextI = (i << 1) | 1;
            } while (duration < 100000000 && nextI > 0);
            return new BigDecimal((duration) * 1000 / i).movePointLeft(3);
        } catch (Throwable e) {
            throw new RuntimeException(e);
        }
    }

    @Override
    public String toString() {
        return name + "\t" + time() + " ns";
    }

    public static void main(String[] args) throws Exception {
        Benchmark[] benchmarks = {
            new Benchmark("try") {
                @Override int run(int iterations) throws Throwable {
                    int x = 0;
                    for (int i = 0; i < iterations; i++) {
                        try {
                            x += i;
                        } catch (Exception e) {
                            e.printStackTrace();
                        }
                    }
                    return x;
                }
            }, new Benchmark("no try") {
                @Override int run(int iterations) throws Throwable {
                    int x = 0;
                    for (int i = 0; i < iterations; i++) {
                        x += i;
                    }
                    return x;
                }
            }
        };
        for (Benchmark bm : benchmarks) {
            System.out.println(bm);
        }
    }
}

On my computer, this prints something like:

try     0.598 ns
no try  0.601 ns

At least in this trivial example, the try statement had no measurable impact on performance. Feel free to measure more complex ones.

Generally speaking, I recommend not to worry about the performance cost of language constructs until you have evidence of an actual performance problem in your code. Or as Donald Knuth put it: "premature optimization is the root of all evil".


while try/no try is very likely to be the same on most JVM, the microbenchmark is terribly flawed.
quite a few levels: you mean the results are computed in under 1ns? Compiled code will remove both the try/catch AND the loop altogether (summing number from 1 to n is a trivial arithmetic progression sum). Even if the code contains try/finally the compiler can prove, there is nothing to be thrown in there. The abstract code has only 2 call sites and it will be clone and inlined. There are more cases, just look up some articles on microbenchmark and it you decide to write a microbenchmark always check the generated assembly.
The reported times are per iteration of the loop. As a measurement will only be used if it has a total elapsed time > 0.1 seconds (or 2 billion iterations, which wasn't the case here) I find your assertion that the loop has been removed in its entirety hard to believe - because if the loop was removed, what took 0.1 seconds to execute?
... and indeed, according to -XX:+UnlockDiagnosticVMOptions -XX:+PrintAssembly, both the loop and the addition therein are present in the generated native code. And no, the abstract methods are not inlined, because their caller is not just in time compiled (presumably, because it isn't invoked enough times).
How do I write a correct micro-benchmark in Java: stackoverflow.com/questions/504103/…
E
Evgeniy Dorofeev

try/catch may have some impact on performance. This is because it prevents JVM from doing some optimizations. Joshua Bloch, in "Effective Java," said the following:

• Placing code inside a try-catch block inhibits certain optimizations that modern JVM implementations might otherwise perform.


"it prevents JVM from doing some optimizations"...? Could you elaborate at all?
@The Kraken Code inside of try blocks (usually? always?) can't be re-ordered with code outside of try blocks, as one example.
Note that the question was whether "it's expensive", not whether "it has any impact on performance".
added an excerpt from Effective Java, and that's the bible of java, of course; unless there is a reference the excerpt doesn't tell anything. Practically any code in java is within try/finally at some level.
k
kevinarpe

Yep, as the others have said, a try block inhibits some optimizations across the {} characters surrounding it. In particular, the optimizer must assume that an exception could occur at any point within the block, so there's no assurance that statements get executed.

For example:

    try {
        int x = a + b * c * d;
        other stuff;
    }
    catch (something) {
        ....
    }
    int y = a + b * c * d;
    use y somehow;

Without the try, the value calculated to assign to x could be saved as a "common subexpression" and reused to assign to y. But because of the try there is no assurance that the first expression was ever evaluated, so the expression must be recomputed. This isn't usually a big deal in "straight-line" code, but can be significant in a loop.

It should be noted, however, that this applies ONLY to JITCed code. javac does only a piddling amount of optimization, and there is zero cost to the bytecode interpreter to enter/leave a try block. (There are no bytecodes generated to mark the block boundaries.)

And for bestsss:

public class TryFinally {
    public static void main(String[] argv) throws Throwable {
        try {
            throw new Throwable();
        }
        finally {
            System.out.println("Finally!");
        }
    }
}

Output:

C:\JavaTools>java TryFinally
Finally!
Exception in thread "main" java.lang.Throwable
        at TryFinally.main(TryFinally.java:4)

javap output:

C:\JavaTools>javap -c TryFinally.class
Compiled from "TryFinally.java"
public class TryFinally {
  public TryFinally();
    Code:
       0: aload_0
       1: invokespecial #1                  // Method java/lang/Object."<init>":()V
       4: return

  public static void main(java.lang.String[]) throws java.lang.Throwable;
    Code:
       0: new           #2                  // class java/lang/Throwable
       3: dup
       4: invokespecial #3                  // Method java/lang/Throwable."<init>":()V
       7: athrow
       8: astore_1
       9: getstatic     #4                  // Field java/lang/System.out:Ljava/io/PrintStream;
      12: ldc           #5                  // String Finally!
      14: invokevirtual #6                  // Method java/io/PrintStream.println:(Ljava/lang/String;)V
      17: aload_1
      18: athrow
    Exception table:
       from    to  target type
           0     9     8   any
}

No "GOTO".


There are no bytecodes generated to mark the block boundaries this is not necessarily -- it does require GOTO to leave the block, otherwise it will fall into the catch/finally frame.
@bestsss - Even if a GOTO is generated (which is not a given) the cost of that is miniscule, and it's far from being a "marker" for a block boundary -- GOTO can be generated for many constructs.
I never mentioned cost, however there are no bytecodes generated is a false statement. That's all. Actually, there are no blocks in bytecode, frames do not equal blocks.
There will not be a GOTO if the try falls directly into the finally, and there are other scenarios where there will be no GOTO. The point is that there is nothing on the order of "enter try"/"exit try" bytecodes.
There will not be a GOTO if the try falls directly into the finally - False! there is no finally in bytecode, it's try/catch(Throwable any){...; throw any;} And It does have catch statement w/ a frame and Throwable that MUST BE defined (non null) and so on. Why do you try to argue about the topic, you can check at least some bytecode? The current guideline for impl. of finally is copying the blocks and avoiding the goto section (previous impl) but the bytecodes have to be copied depending how many exit points there are.
A
Andrey Chaschev

Yet another microbenchmark (source).

I created a test in which I measure try-catch and no-try-catch code version based on an exception percentage. 10% percentage means that 10% of the test cases had division by zero cases. In one situation it is handled by a try-catch block, in the other by a conditional operator. Here is my results table:

OS: Windows 8 6.2 x64
JVM: Oracle Corporation Java HotSpot(TM) 64-Bit Server VM 23.25-b01
Percentage | Result (try/if, ns)   
    0%     |      88/90   
    1%     |      89/87    
    10%    |      86/97    
    90%    |      85/83

Which says that there is no significant difference between any of these cases.


t
technosaurus

To understand why the optimizations cannot be performed, It is useful to understand the underlying mechanisms. The most succinct example I could find was implemented in C macros at: http://www.di.unipi.it/~nids/docs/longjump_try_trow_catch.html

#include <stdio.h>
#include <setjmp.h>
#define TRY do{ jmp_buf ex_buf__; switch( setjmp(ex_buf__) ){ case 0: while(1){
#define CATCH(x) break; case x:
#define FINALLY break; } default:
#define ETRY } }while(0)
#define THROW(x) longjmp(ex_buf__, x)

Compilers often have difficulty determining if a jump can be localized to X, Y and Z so they skip optimizations that they can't guarantee to be safe, but the implementation itself is rather light.


These C macros you've found for try/catch are not equivalent to the Java or to the C# implementation, which emit 0 run time instructions.
The java implementation is too extensive to include in full, this is a simplified implementation for the purpose of understanding the basic idea of how exceptions can be implemented. Saying that it emits 0 run time instructions is misleading. For example a simple classcastexception extends runtimeexception which extends exception which extends throwable which involves: grepcode.com/file/repository.grepcode.com/java/root/jdk/openjdk/… ... That's like saying a switch-case in C is free if only 1 case is ever used, there is still a small startup overhead.
@Patashu All of those precompiled bits still have to be loaded at startup whether or not they are ever used. There is no way to know if there will be an out of memory exception during run time at compile time - that is why they are called run time exceptions - otherwise they would be compiler warnings/errors, so no it doesn't optimize everything away, all of the code to handle them is included in the compiled code and has a startup cost.
I can't speak about C. In C# and Java, try is implemented by adding metadata, not code. When a try block is entered, nothing is executed to indicate this - when an exception is thrown, the stack is unwinded and the metadata checked for handlers of that exception type (expensive).
Yep, I've actually implemented a Java interpreter & static bytecode compiler and worked on a subsequent JITC (for IBM iSeries) and I can tell you there's nothing that "marks" the entry/exit of the try range in the bytecodes, but rather the ranges are identified in a separate table. The interpreter does nothing special for a try range (until an exception is raised). A JITC (or static bytecode compiler) must be aware of the boundaries to suppress optimizations as previously stated.
M
Mateusz Kaflowski

I have found catching NullPointException quite expensive. For 1.2k operations the time was 200ms and 12ms when I handeled it the same way with if(object==null) which was pretty improvement for me.