I want to fill out a string with spaces. I know that the following works for zero's:
>>> print "'%06d'"%4
'000004'
But what should I do when I want this?:
'hi '
of course I can measure string length and do str+" "*leftover
, but I'd like the shortest way.
"%-6s" % s
for left-aligned and "%6s" % s
for right-aligned.
You can do this with str.ljust(width[, fillchar])
:
Return the string left justified in a string of length width. Padding is done using the specified fillchar (default is a space). The original string is returned if width is less than len(s).
>>> 'hi'.ljust(10)
'hi '
For a flexible method that works even when formatting complicated string, you probably should use the string-formatting mini-language,
using either f-strings
>>> f'{"Hi": <16} StackOverflow!' # Python >= 3.6
'Hi StackOverflow!'
or the str.format()
method
>>> '{0: <16} StackOverflow!'.format('Hi') # Python >=2.6
'Hi StackOverflow!'
'{message: <{fill}}'.format(message='Hi', fill='16')
str.format()
for templates with only a single {...}
and nothing else. Just use the format()
function and save yourself the parsing overhead: format('Hi', '<16')
.
The new(ish) string format method lets you do some fun stuff with nested keyword arguments. The simplest case:
>>> '{message: <16}'.format(message='Hi')
'Hi '
If you want to pass in 16
as a variable:
>>> '{message: <{width}}'.format(message='Hi', width=16)
'Hi '
If you want to pass in variables for the whole kit and kaboodle:
'{message:{fill}{align}{width}}'.format(
message='Hi',
fill=' ',
align='<',
width=16,
)
Which results in (you guessed it):
'Hi '
And for all these, you can use python 3.6+ f-strings:
message = 'Hi'
fill = ' '
align = '<'
width = 16
f'{message:{fill}{align}{width}}'
And of course the result:
'Hi '
You can try this:
print "'%-100s'" % 'hi'
"'%+100s'" % 'hi'
would work for putting spaces to the right of 'hi'
Correct way of doing this would be to use Python's format syntax as described in the official documentation
For this case it would simply be:
'{:10}'.format('hi')
which outputs:
'hi '
Explanation:
format_spec ::= [[fill]align][sign][#][0][width][,][.precision][type]
fill ::= <any character>
align ::= "<" | ">" | "=" | "^"
sign ::= "+" | "-" | " "
width ::= integer
precision ::= integer
type ::= "b" | "c" | "d" | "e" | "E" | "f" | "F" | "g" | "G" | "n" | "o" | "s" | "x" | "X" | "%"
Pretty much all you need to know is there ^.
Update: as of python 3.6 it's even more convenient with literal string interpolation!
foo = 'foobar'
print(f'{foo:10} is great!')
# foobar is great!
Use str.ljust()
:
>>> 'Hi'.ljust(6)
'Hi '
You should also consider string.zfill()
, str.ljust()
and str.center()
for string formatting. These can be chained and have the 'fill' character specified, thus:
>>> ('3'.zfill(8) + 'blind'.rjust(8) + 'mice'.ljust(8, '.')).center(40)
' 00000003 blindmice.... '
These string formatting operations have the advantage of working in Python v2 and v3.
Take a look at pydoc str
sometime: there's a wealth of good stuff in there.
str.center(n)
method. It was just what i was looking for and didn't even know its existance. :D
As of Python 3.6 you can just do
>>> strng = 'hi'
>>> f'{strng: <10}'
with literal string interpolation.
Or, if your padding size is in a variable, like this (thanks @Matt M.!):
>>> to_pad = 10
>>> f'{strng: <{to_pad}}'
f'{strng: >10}'
for filling string with leading whitespace to a length of 10. That is magic. And it is not well documented.
f'{strng:10}'
.
you can also center your string:
'{0: ^20}'.format('nice')
TL;DR
text = 'hi'
print(f'{text:10}') # 'hi '
Longer explanation
Since Python3.6
you can use f-strings literal interpolation.
Variable space:
value = 4
space = 10
# move value to left
print(f'foo {value:<{space}} bar') # foo 4 bar
# move value to right
print(f'foo {value:>{space}} bar') # foo 4 bar
# center value
print(f'foo {value:^{space}} bar') # foo 4 bar
Constant space:
value = 4
# move value to left
print(f'foo {value:<10} bar') # foo 4 bar
# move value to right
print(f'foo {value:>10} bar') # foo 4 bar
# center value
print(f'foo {value:^10} bar') # foo 4 bar
If you want to padd with some other char then space, specify it at the beginning:
value = 4
space = 10
padd = '_'
print(f'foo {value:{padd}^{space}} bar') # foo ____4_____ bar
print(f'foo {value:_^10} bar') # foo ____4_____ bar
Use Python 2.7's mini formatting for strings:
'{0: <8}'.format('123')
This left aligns, and pads to 8 characters with the ' ' character.
Just remove the 0 and it will add space instead:
>>> print "'%6d'"%4
Wouldn't it be more pythonic to use slicing?
For example, to pad a string with spaces on the right until it's 10 characters long:
>>> x = "string"
>>> (x + " " * 10)[:10]
'string '
To pad it with spaces on the left until it's 15 characters long:
>>> (" " * 15 + x)[-15:]
' string'
It requires knowing how long you want to pad to, of course, but it doesn't require measuring the length of the string you're starting with.
''.join(reversed(str))
is more pythonic than str[::-1]
, and we all know that's not true.
(x + " " * 10)[:10]
is in my opinion much more convoluted than using x.ljust(10)
.
A nice trick to use in place of the various print formats:
(1) Pad with spaces to the right:
('hi' + ' ')[:8]
(2) Pad with leading zeros on the left:
('0000' + str(2))[-4:]
min_len = 8
then ('hi' + ' '*min_len)[:min_len]
or ('0'*min_len + str(2))[-min_len]
('0'*min_len + str(2))[-min_len:]
rather, though this is only for fun, and I recommend the other answers.
You could do it using list comprehension, this'd give you an idea about the number of spaces too and would be a one liner.
"hello" + " ".join([" " for x in range(1,10)])
output --> 'hello '
s = "hi"
; s + (6-len(s)) * " "
instead (it is ok when the result is negative). However, answers which use whatever framework feature that addresses the exact issue will be easier to maintain (see other answers).
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