Can I invoke an instance method on a Ruby module without including it?

I think the shortest way to do just throw-away single call (without altering existing modules or creating new ones) would be as follows:

Class.new.extend(UsefulThings).get_file

---

If a method on a module is turned into a module function you can simply call it off of Mods as if it had been declared as

module Mods
  def self.foo
     puts "Mods.foo(self)"
  end
end

The module_function approach below will avoid breaking any classes which include all of Mods.

module Mods
  def foo
    puts "Mods.foo"
  end
end

class Includer
  include Mods
end

Includer.new.foo

Mods.module_eval do
  module_function(:foo)
  public :foo
end

Includer.new.foo # this would break without public :foo above

class Thing
  def bar
    Mods.foo
  end
end

Thing.new.bar  

However, I'm curious why a set of unrelated functions are all contained within the same module in the first place?

Edited to show that includes still work if public :foo is called after module_function :foo

---

Another way to do it if you "own" the module is to use module_function.

module UsefulThings
  def a
    puts "aaay"
  end
  module_function :a

  def b
    puts "beee"
  end
end

def test
  UsefulThings.a
  UsefulThings.b # Fails!  Not a module method
end

test

---

If you want to call these methods without including module in another class then you need to define them as module methods:

module UsefulThings
  def self.get_file; ...
  def self.delete_file; ...

  def self.format_text(x); ...
end

and then you can call them with

UsefulThings.format_text("xxx")

or

UsefulThings::format_text("xxx")

But anyway I would recommend that you put just related methods in one module or in one class. If you have problem that you want to include just one method from module then it sounds like a bad code smell and it is not good Ruby style to put unrelated methods together.

---

To invoke a module instance method without including the module (and without creating intermediary objects):

class UsefulWorker
  def do_work
    UsefulThings.instance_method(:format_text).bind(self).call("abc")
    ...
  end
end

---

Not sure if someone still needs it after 10 years but I solved it using eigenclass.

module UsefulThings
  def useful_thing_1
    "thing_1"
  end

  class << self
    include UsefulThings
  end
end

class A
  include UsefulThings
end

class B
  extend UsefulThings
end

UsefulThings.useful_thing_1 # => "thing_1"
A.new.useful_thing_1 # => "thing_1"
B.useful_thing_1 # => "thing_1"

---

Firstly, I'd recommend breaking the module up into the useful things you need. But you can always create a class extending that for your invocation:

module UsefulThings
  def a
    puts "aaay"
  end
  def b
    puts "beee"
  end
end

def test
  ob = Class.new.send(:include, UsefulThings).new
  ob.a
end

test

---

A. In case you, always want to call them in a "qualified", standalone way (UsefulThings.get_file), then just make them static as others pointed out,

module UsefulThings
  def self.get_file; ...
  def self.delete_file; ...

  def self.format_text(x); ...

  # Or.. make all of the "static"
  class << self
     def write_file; ...
     def commit_file; ...
  end

end

B. If you still want to keep the mixin approach in same cases, as well the one-off standalone invocation, you can have a one-liner module that extends itself with the mixin:

module UsefulThingsMixin
  def get_file; ...
  def delete_file; ...

  def format_text(x); ...
end

module UsefulThings
  extend UsefulThingsMixin
end

So both works then:

  UsefulThings.get_file()       # one off

   class MyUser
      include UsefulThingsMixin  
      def f
         format_text             # all useful things available directly
      end
   end 

IMHO it's cleaner than module_function for every single method - in case want all of them.

---

As I understand the question, you want to mix some of a module's instance methods into a class.

Let's begin by considering how Module#include works. Suppose we have a module UsefulThings that contains two instance methods:

module UsefulThings
  def add1
    self + 1
  end
  def add3
    self + 3
  end
end

UsefulThings.instance_methods
  #=> [:add1, :add3]

and Fixnum includes that module:

class Fixnum
  def add2
    puts "cat"
  end
  def add3
    puts "dog"
  end
  include UsefulThings
end

We see that:

Fixnum.instance_methods.select { |m| m.to_s.start_with? "add" }
  #=> [:add2, :add3, :add1] 
1.add1
2 
1.add2
cat
1.add3
dog

Were you expecting UsefulThings#add3 to override Fixnum#add3, so that 1.add3 would return 4? Consider this:

Fixnum.ancestors
  #=> [Fixnum, UsefulThings, Integer, Numeric, Comparable,
  #    Object, Kernel, BasicObject] 

When the class includes the module, the module becomes the class' superclass. So, because of how inheritance works, sending add3 to an instance of Fixnum will cause Fixnum#add3 to be invoked, returning dog.

Now let's add a method :add2 to UsefulThings:

module UsefulThings
  def add1
    self + 1
  end
  def add2
    self + 2
  end
  def add3
    self + 3
  end
end

We now wish Fixnum to include only the methods add1 and add3. Is so doing, we expect to get the same results as above.

Suppose, as above, we execute:

class Fixnum
  def add2
    puts "cat"
  end
  def add3
    puts "dog"
  end
  include UsefulThings
end

What is the result? The unwanted method :add2 is added to Fixnum, :add1 is added and, for reasons I explained above, :add3 is not added. So all we have to do is undef :add2. We can do that with a simple helper method:

module Helpers
  def self.include_some(mod, klass, *args)
    klass.send(:include, mod)
    (mod.instance_methods - args - klass.instance_methods).each do |m|
      klass.send(:undef_method, m)
    end
  end
end

which we invoke like this:

class Fixnum
  def add2
    puts "cat"
  end
  def add3
    puts "dog"
  end
  Helpers.include_some(UsefulThings, self, :add1, :add3)
end

Then:

Fixnum.instance_methods.select { |m| m.to_s.start_with? "add" }
  #=> [:add2, :add3, :add1] 
1.add1
2 
1.add2
cat
1.add3
dog

which is the result we want.

---

After almost 9 years here's a generic solution:

module CreateModuleFunctions
  def self.included(base)
    base.instance_methods.each do |method|
      base.module_eval do
        module_function(method)
        public(method)
      end
    end
  end
end

RSpec.describe CreateModuleFunctions do
  context "when included into a Module" do
    it "makes the Module's methods invokable via the Module" do
      module ModuleIncluded
        def instance_method_1;end
        def instance_method_2;end

        include CreateModuleFunctions
      end

      expect { ModuleIncluded.instance_method_1 }.to_not raise_error
    end
  end
end

The unfortunate trick you need to apply is to include the module after the methods have been defined. Alternatively you may also include it after the context is defined as ModuleIncluded.send(:include, CreateModuleFunctions).

Or you can use it via the reflection_utils gem.

spec.add_dependency "reflection_utils", ">= 0.3.0"

require 'reflection_utils'
include ReflectionUtils::CreateModuleFunctions

---