I often find Bash syntax very helpful, e.g. process substitution like in diff <(sort file1) <(sort file2)
.
Is it possible to use such Bash commands in a Makefile? I'm thinking of something like this:
file-differences:
diff <(sort file1) <(sort file2) > $@
In my GNU Make 3.80 this will give an error since it uses the shell
instead of bash
to execute the commands.
/bin/sh: -c: line 0: syntax error near unexpected token
('`
From the GNU Make documentation,
5.3.2 Choosing the Shell
------------------------
The program used as the shell is taken from the variable `SHELL'. If
this variable is not set in your makefile, the program `/bin/sh' is
used as the shell.
So put SHELL := /bin/bash
at the top of your makefile, and you should be good to go.
BTW: You can also do this for one target, at least for GNU Make. Each target can have its own variable assignments, like this:
all: a b
a:
@echo "a is $$0"
b: SHELL:=/bin/bash # HERE: this is setting the shell for b only
b:
@echo "b is $$0"
That'll print:
a is /bin/sh
b is /bin/bash
See "Target-specific Variable Values" in the documentation for more details. That line can go anywhere in the Makefile, it doesn't have to be immediately before the target.
You can call bash
directly, use the -c
flag:
bash -c "diff <(sort file1) <(sort file2) > $@"
Of course, you may not be able to redirect to the variable $@, but when I tried to do this, I got -bash: $@: ambiguous redirect
as an error message, so you may want to look into that before you get too into this (though I'm using bash 3.2.something, so maybe yours works differently).
One way that also works is putting it this way in the first line of the your target:
your-target: $(eval SHELL:=/bin/bash)
@echo "here shell is $$0"
If portability is important you may not want to depend on a specific shell in your Makefile. Not all environments have bash available.
You can call bash directly within your Makefile instead of using the default shell:
bash -c "ls -al"
instead of:
ls -al
make
ignores the value of the environment variable SHELL.
There is a way to do this without explicitly setting your SHELL variable to point to bash. This can be useful if you have many makefiles since SHELL isn't inherited by subsequent makefiles or taken from the environment. You also need to be sure that anyone who compiles your code configures their system this way.
If you run sudo dpkg-reconfigure dash
and answer 'no' to the prompt, your system will not use dash as the default shell. It will then point to bash (at least in Ubuntu). Note that using dash as your system shell is a bit more efficient though.
sh
, bash runs in compatibility mode (set -o posix
). The functionality the OP is trying to use, process substitution, is not available in this mode.
It's not a direct answer to the question, makeit is limited Makefile replacement with bash syntax and it can be useful in some cases (I'm the author)
rules can be defined as bash-functions
auto-completion feature
Basic idea is to have while
loop in the end of the script:
while [ $# != 0 ]; do
if [ "$(type -t $1)" == 'function' ]; then
$1
else
exit 1
fi
shift
done
https://asciinema.org/a/435159
https://asciinema.org/a/Nvx7QOvUyMnZc8MVfKk2xETnj.svg
Success story sharing
man
. Talk about timings. :Pinfo
, actually, but, I guess it really helped Andy. I know I've had days like that...SHELL=/bin/bash
as the first line of the Makefile (or right after the comment)./usr/bin/env bash
it uses thebash
in the PATH. But what if it was justSHELL := bash
?$(info $(SHELL))
from a makefile and see/bin/bash
: it means nothing! GNU Make inherits the variables from the environment, so theSHELL
variable comes from the environment, but it won't use it when$(origin SHELL)
isenvironment
(my guess).