How to add leading zeros?

The short version: use formatC or sprintf.

The longer version:

There are several functions available for formatting numbers, including adding leading zeroes. Which one is best depends upon what other formatting you want to do.

The example from the question is quite easy since all the values have the same number of digits to begin with, so let's try a harder example of making powers of 10 width 8 too.

anim <- 25499:25504
x <- 10 ^ (0:5)

paste (and it's variant paste0) are often the first string manipulation functions that you come across. They aren't really designed for manipulating numbers, but they can be used for that. In the simple case where we always have to prepend a single zero, paste0 is the best solution.

paste0("0", anim)
## [1] "025499" "025500" "025501" "025502" "025503" "025504"

For the case where there are a variable number of digits in the numbers, you have to manually calculate how many zeroes to prepend, which is horrible enough that you should only do it out of morbid curiosity.

str_pad from stringr works similarly to paste, making it more explicit that you want to pad things.

library(stringr)
str_pad(anim, 6, pad = "0")
## [1] "025499" "025500" "025501" "025502" "025503" "025504"

Again, it isn't really designed for use with numbers, so the harder case requires a little thinking about. We ought to just be able to say "pad with zeroes to width 8", but look at this output:

str_pad(x, 8, pad = "0")
## [1] "00000001" "00000010" "00000100" "00001000" "00010000" "0001e+05"

You need to set the scientific penalty option so that numbers are always formatted using fixed notation (rather than scientific notation).

library(withr)
with_options(
  c(scipen = 999), 
  str_pad(x, 8, pad = "0")
)
## [1] "00000001" "00000010" "00000100" "00001000" "00010000" "00100000"

stri_pad in stringi works exactly like str_pad from stringr.

formatC is an interface to the C function printf. Using it requires some knowledge of the arcana of that underlying function (see link). In this case, the important points are the width argument, format being "d" for "integer", and a "0" flag for prepending zeroes.

formatC(anim, width = 6, format = "d", flag = "0")
## [1] "025499" "025500" "025501" "025502" "025503" "025504"
formatC(x, width = 8, format = "d", flag = "0")
## [1] "00000001" "00000010" "00000100" "00001000" "00010000" "00100000"

This is my favourite solution, since it is easy to tinker with changing the width, and the function is powerful enough to make other formatting changes.

sprintf is an interface to the C function of the same name; like formatC but with a different syntax.

sprintf("%06d", anim)
## [1] "025499" "025500" "025501" "025502" "025503" "025504"
sprintf("%08d", x)
## [1] "00000001" "00000010" "00000100" "00001000" "00010000" "00100000"

The main advantage of sprintf is that you can embed formatted numbers inside longer bits of text.

sprintf(
  "Animal ID %06d was a %s.", 
  anim, 
  sample(c("lion", "tiger"), length(anim), replace = TRUE)
)
## [1] "Animal ID 025499 was a tiger." "Animal ID 025500 was a tiger."
## [3] "Animal ID 025501 was a lion."  "Animal ID 025502 was a tiger."
## [5] "Animal ID 025503 was a tiger." "Animal ID 025504 was a lion." 

See also goodside's answer.

For completeness it is worth mentioning the other formatting functions that are occasionally useful, but have no method of prepending zeroes.

format, a generic function for formatting any kind of object, with a method for numbers. It works a little bit like formatC, but with yet another interface.

prettyNum is yet another formatting function, mostly for creating manual axis tick labels. It works particularly well for wide ranges of numbers.

The scales package has several functions such as percent, date_format and dollar for specialist format types.

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For a general solution that works regardless of how many digits are in data$anim, use the sprintf function. It works like this:

sprintf("%04d", 1)
# [1] "0001"
sprintf("%04d", 104)
# [1] "0104"
sprintf("%010d", 104)
# [1] "0000000104"

In your case, you probably want: data$anim <- sprintf("%06d", data$anim)

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Expanding on @goodside's repsonse:

In some cases you may want to pad a string with zeros (e.g. fips codes or other numeric-like factors). In OSX/Linux:

> sprintf("%05s", "104")
[1] "00104"

But because sprintf() calls the OS's C sprintf() command, discussed here, in Windows 7 you get a different result:

> sprintf("%05s", "104")
[1] "  104"

So on Windows machines the work around is:

> sprintf("%05d", as.numeric("104"))
[1] "00104"

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str_pad from the stringr package is an alternative.

anim = 25499:25504
str_pad(anim, width=6, pad="0")

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Here's a generalizable base R function:

pad_left <- function(x, len = 1 + max(nchar(x)), char = '0'){

    unlist(lapply(x, function(x) {
        paste0(
            paste(rep(char, len - nchar(x)), collapse = ''),
            x
        )
    }))
}

pad_left(1:100)

I like sprintf but it comes with caveats like:

however the actual implementation will follow the C99 standard and fine details (especially the behaviour under user error) may depend on the platform

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Here is another alternative for adding leading to 0s to strings such as CUSIPs which can sometimes look like a number and which many applications such as Excel will corrupt and remove the leading 0s or convert them to scientific notation.

When I tried the answer provided by @metasequoia the vector returned had leading spaces and not 0s. This was the same problem mentioned by @user1816679 -- and removing the quotes around the 0 or changing from %d to %s did not make a difference either. FYI, I am using RStudio Server running on an Ubuntu Server. This little two-step solution worked for me:

gsub(pattern = " ", replacement = "0", x = sprintf(fmt = "%09s", ids[,CUSIP]))

using the %>% pipe function from the magrittr package it could look like this:

sprintf(fmt = "%09s", ids[,CUSIP]) %>% gsub(pattern = " ", replacement = "0", x = .)

I'd prefer a one-function solution, but it works.

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data$anim <- sapply(0, paste0,data$anim)

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For other circumstances in which you want the number string to be consistent, I made a function.

Someone may find this useful:

idnamer<-function(x,y){#Alphabetical designation and number of integers required
    id<-c(1:y)
    for (i in 1:length(id)){
         if(nchar(id[i])<2){
            id[i]<-paste("0",id[i],sep="")
         }
    }
    id<-paste(x,id,sep="")
    return(id)
}
idnamer("EF",28)

Sorry about the formatting.

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