How to identify on which OS Python is running on?

>>> import os
>>> os.name
'posix'
>>> import platform
>>> platform.system()
'Linux'
>>> platform.release()
'2.6.22-15-generic'

The output of platform.system() is as follows:

Linux: Linux

Mac: Darwin

Windows: Windows

See: platform — Access to underlying platform’s identifying data

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Dang -- Louis Brandy beat me to the punch, but that doesn't mean I can't provide you with the system results for Vista!

>>> import os
>>> os.name
'nt'
>>> import platform
>>> platform.system()
'Windows'
>>> platform.release()
'Vista'

...and I can’t believe no one’s posted one for Windows 10 yet:

>>> import os
>>> os.name
'nt'
>>> import platform
>>> platform.system()
'Windows'
>>> platform.release()
'10'

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For the record here's the results on Mac:

>>> import os
>>> os.name
'posix'
>>> import platform
>>> platform.system()
'Darwin'
>>> platform.release()
'8.11.1'

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Sample code to differentiate operating systems using Python:

import sys

if sys.platform.startswith("linux"):  # could be "linux", "linux2", "linux3", ...
    # linux
elif sys.platform == "darwin":
    # MAC OS X
elif sys.platform == "win32":
    # Windows (either 32-bit or 64-bit)

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Short Story

Use platform.system(). It returns Windows, Linux or Darwin (for OSX).

Long Story

There are 3 ways to get OS in Python, each with its own pro and cons:

Method 1

>>> import sys
>>> sys.platform
'win32'  # could be 'linux', 'linux2, 'darwin', 'freebsd8' etc

How this works (source): Internally it calls OS APIs to get name of the OS as defined by OS. See here for various OS-specific values.

Pro: No magic, low level.

Con: OS version dependent, so best not to use directly.

Method 2

>>> import os
>>> os.name
'nt'  # for Linux and Mac it prints 'posix'

How this works (source): Internally it checks if python has OS-specific modules called posix or nt.

Pro: Simple to check if posix OS

Con: no differentiation between Linux or OSX.

Method 3

>>> import platform
>>> platform.system()
'Windows' # for Linux it prints 'Linux', Mac it prints `'Darwin'

How this works (source): Internally it will eventually call internal OS APIs, get OS version-specific name like 'win32' or 'win16' or 'linux1' and then normalize to more generic names like 'Windows' or 'Linux' or 'Darwin' by applying several heuristics.

Pro: Best portable way for Windows, OSX and Linux.

Con: Python folks must keep normalization heuristic up to date.

Summary

If you want to check if OS is Windows or Linux or OSX then the most reliable way is platform.system().

If you want to make OS-specific calls but via built-in Python modules posix or nt then use os.name.

If you want to get raw OS name as supplied by OS itself then use sys.platform.

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You can also use sys.platform if you already have imported sys and you don't want to import another module

>>> import sys
>>> sys.platform
'linux2'

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I started a bit more systematic listing of what values you can expect using the various modules (feel free to edit and add your system):

Linux (64bit) + WSL

                            x86_64            aarch64
                            ------            -------
os.name                     posix             posix
sys.platform                linux             linux
platform.system()           Linux             Linux
sysconfig.get_platform()    linux-x86_64      linux-aarch64
platform.machine()          x86_64            aarch64
platform.architecture()     ('64bit', '')     ('64bit', 'ELF')

tried with archlinux and mint, got same results

on python2 sys.platform is suffixed by kernel version, e.g. linux2, everything else stays identical

same output on Windows Subsystem for Linux (tried with ubuntu 18.04 LTS), except platform.architecture() = ('64bit', 'ELF')

WINDOWS (64bit)

(with 32bit column running in the 32bit subsystem)

official python installer   64bit                     32bit
-------------------------   -----                     -----
os.name                     nt                        nt
sys.platform                win32                     win32
platform.system()           Windows                   Windows
sysconfig.get_platform()    win-amd64                 win32
platform.machine()          AMD64                     AMD64
platform.architecture()     ('64bit', 'WindowsPE')    ('64bit', 'WindowsPE')

msys2                       64bit                     32bit
-----                       -----                     -----
os.name                     posix                     posix
sys.platform                msys                      msys
platform.system()           MSYS_NT-10.0              MSYS_NT-10.0-WOW
sysconfig.get_platform()    msys-2.11.2-x86_64        msys-2.11.2-i686
platform.machine()          x86_64                    i686
platform.architecture()     ('64bit', 'WindowsPE')    ('32bit', 'WindowsPE')

msys2                       mingw-w64-x86_64-python3  mingw-w64-i686-python3
-----                       ------------------------  ----------------------
os.name                     nt                        nt
sys.platform                win32                     win32
platform.system()           Windows                   Windows
sysconfig.get_platform()    mingw                     mingw
platform.machine()          AMD64                     AMD64
platform.architecture()     ('64bit', 'WindowsPE')    ('32bit', 'WindowsPE')

cygwin                      64bit                     32bit
------                      -----                     -----
os.name                     posix                     posix
sys.platform                cygwin                    cygwin
platform.system()           CYGWIN_NT-10.0            CYGWIN_NT-10.0-WOW
sysconfig.get_platform()    cygwin-3.0.1-x86_64       cygwin-3.0.1-i686
platform.machine()          x86_64                    i686
platform.architecture()     ('64bit', 'WindowsPE')    ('32bit', 'WindowsPE')

Some remarks:

there is also distutils.util.get_platform() which is identical to `sysconfig.get_platform

anaconda on windows is same as official python windows installer

I don't have a Mac nor a true 32bit system and was not motivated to do it online

To compare with your system, simply run this script (and please append results here if missing :)

from __future__ import print_function
import os
import sys
import platform
import sysconfig

print("os.name                      ",  os.name)
print("sys.platform                 ",  sys.platform)
print("platform.system()            ",  platform.system())
print("sysconfig.get_platform()     ",  sysconfig.get_platform())
print("platform.machine()           ",  platform.machine())
print("platform.architecture()      ",  platform.architecture())

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If you want user readable data but still detailed, you can use platform.platform()

>>> import platform
>>> platform.platform()
'Linux-3.3.0-8.fc16.x86_64-x86_64-with-fedora-16-Verne'

Here's a few different possible calls you can make to identify where you are, linux_distribution and dist are removed in recent python versions.

import platform
import sys

def linux_distribution():
  try:
    return platform.linux_distribution()
  except:
    return "N/A"

def dist():
  try:
    return platform.dist()
  except:
    return "N/A"

print("""Python version: %s
dist: %s
linux_distribution: %s
system: %s
machine: %s
platform: %s
uname: %s
version: %s
mac_ver: %s
""" % (
sys.version.split('\n'),
str(dist()),
linux_distribution(),
platform.system(),
platform.machine(),
platform.platform(),
platform.uname(),
platform.version(),
platform.mac_ver(),
))

The outputs of this script ran on a few different systems (Linux, Windows, Solaris, MacOS) and architectures (x86, x64, Itanium, power pc, sparc) is available here: https://github.com/hpcugent/easybuild/wiki/OS_flavor_name_version

Ubuntu 12.04 server for example gives:

Python version: ['2.6.5 (r265:79063, Oct  1 2012, 22:04:36) ', '[GCC 4.4.3]']
dist: ('Ubuntu', '10.04', 'lucid')
linux_distribution: ('Ubuntu', '10.04', 'lucid')
system: Linux
machine: x86_64
platform: Linux-2.6.32-32-server-x86_64-with-Ubuntu-10.04-lucid
uname: ('Linux', 'xxx', '2.6.32-32-server', '#62-Ubuntu SMP Wed Apr 20 22:07:43 UTC 2011', 'x86_64', '')
version: #62-Ubuntu SMP Wed Apr 20 22:07:43 UTC 2011
mac_ver: ('', ('', '', ''), '')

---

How about a new answer:

import psutil
psutil.MACOS   #True (OSX is deprecated)
psutil.WINDOWS #False
psutil.LINUX   #False 

This would be the output if I was using MACOS

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Use platform.system()

Returns the system/OS name, such as 'Linux', 'Darwin', 'Java', 'Windows'. An empty string is returned if the value cannot be determined.

import platform
system = platform.system().lower()

is_windows = system == 'windows'
is_linux = system == 'linux'
is_mac = system == 'darwin'

---

I am using the WLST tool that comes with weblogic, and it doesn't implement the platform package.

wls:/offline> import os
wls:/offline> print os.name
java 
wls:/offline> import sys
wls:/offline> print sys.platform
'java1.5.0_11'

Apart from patching the system javaos.py (issue with os.system() on windows 2003 with jdk1.5) (which I can't do, I have to use weblogic out of the box), this is what I use:

def iswindows():
  os = java.lang.System.getProperty( "os.name" )
  return "win" in os.lower()

---

/usr/bin/python3.2

def cls():
    from subprocess import call
    from platform import system

    os = system()
    if os == 'Linux':
        call('clear', shell = True)
    elif os == 'Windows':
        call('cls', shell = True)

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For Jython the only way to get os name I found is to check os.name Java property (tried with sys, os and platform modules for Jython 2.5.3 on WinXP):

def get_os_platform():
    """return platform name, but for Jython it uses os.name Java property"""
    ver = sys.platform.lower()
    if ver.startswith('java'):
        import java.lang
        ver = java.lang.System.getProperty("os.name").lower()
    print('platform: %s' % (ver))
    return ver

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Interesting results on windows 8:

>>> import os
>>> os.name
'nt'
>>> import platform
>>> platform.system()
'Windows'
>>> platform.release()
'post2008Server'

Edit: That's a bug

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Watch out if you're on Windows with Cygwin where os.name is posix.

>>> import os, platform
>>> print os.name
posix
>>> print platform.system()
CYGWIN_NT-6.3-WOW

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I know this is an old question but I believe that my answer is one that might be helpful to some people who are looking for an easy, simple to understand pythonic way to detect OS in their code. Tested on python3.7

from sys import platform


class UnsupportedPlatform(Exception):
    pass


if "linux" in platform:
    print("linux")
elif "darwin" in platform:
    print("mac")
elif "win" in platform:
    print("windows")
else:
    raise UnsupportedPlatform

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If you not looking for the kernel version etc, but looking for the linux distribution you may want to use the following

in python2.6+

>>> import platform
>>> print platform.linux_distribution()
('CentOS Linux', '6.0', 'Final')
>>> print platform.linux_distribution()[0]
CentOS Linux
>>> print platform.linux_distribution()[1]
6.0

in python2.4

>>> import platform
>>> print platform.dist()
('centos', '6.0', 'Final')
>>> print platform.dist()[0]
centos
>>> print platform.dist()[1]
6.0

Obviously, this will work only if you are running this on linux. If you want to have more generic script across platforms, you can mix this with code samples given in other answers.

---

try this:

import os

os.uname()

and you can make it :

info=os.uname()
info[0]
info[1]

---

You can also use only platform module without importing os module to get all the information.

>>> import platform
>>> platform.os.name
'posix'
>>> platform.uname()
('Darwin', 'mainframe.local', '15.3.0', 'Darwin Kernel Version 15.3.0: Thu Dec 10 18:40:58 PST 2015; root:xnu-3248.30.4~1/RELEASE_X86_64', 'x86_64', 'i386')

A nice and tidy layout for reporting purpose can be achieved using this line:

for i in zip(['system','node','release','version','machine','processor'],platform.uname()):print i[0],':',i[1]

That gives this output:

system : Darwin
node : mainframe.local
release : 15.3.0
version : Darwin Kernel Version 15.3.0: Thu Dec 10 18:40:58 PST 2015; root:xnu-3248.30.4~1/RELEASE_X86_64
machine : x86_64
processor : i386

What is missing usually is the operating system version but you should know if you are running windows, linux or mac a platform indipendent way is to use this test:

In []: for i in [platform.linux_distribution(),platform.mac_ver(),platform.win32_ver()]:
   ....:     if i[0]:
   ....:         print 'Version: ',i[0]

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in the same vein....

import platform
is_windows=(platform.system().lower().find("win") > -1)

if(is_windows): lv_dll=LV_dll("my_so_dll.dll")
else:           lv_dll=LV_dll("./my_so_dll.so")

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Check the available tests with module platform and print the answer out for your system:

import platform

print dir(platform)

for x in dir(platform):
    if x[0].isalnum():
        try:
            result = getattr(platform, x)()
            print "platform."+x+": "+result
        except TypeError:
            continue

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If you are running macOS X and run platform.system() you get darwin because macOS X is built on Apple's Darwin OS. Darwin is the kernel of macOS X and is essentially macOS X without the GUI.

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This solution works for both python and jython.

module os_identify.py:

import platform
import os

# This module contains functions to determine the basic type of
# OS we are running on.
# Contrary to the functions in the `os` and `platform` modules,
# these allow to identify the actual basic OS,
# no matter whether running on the `python` or `jython` interpreter.

def is_linux():
    try:
        platform.linux_distribution()
        return True
    except:
        return False

def is_windows():
    try:
        platform.win32_ver()
        return True
    except:
        return False

def is_mac():
    try:
        platform.mac_ver()
        return True
    except:
        return False

def name():
    if is_linux():
        return "Linux"
    elif is_windows():
        return "Windows"
    elif is_mac():
        return "Mac"
    else:
        return "<unknown>" 

Use like this:

import os_identify

print "My OS: " + os_identify.name()

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How about a simple Enum implementation like the following? No need for external libs!

import platform
from enum import Enum
class OS(Enum):
    def checkPlatform(osName):
        return osName.lower()== platform.system().lower()

    MAC = checkPlatform("darwin")
    LINUX = checkPlatform("linux")
    WINDOWS = checkPlatform("windows")  #I haven't test this one

Simply you can access with Enum value

if OS.LINUX.value:
    print("Cool it is Linux")

P.S It is python3

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You can look at the code in pyOSinfo which is part of the pip-date package, to get the most relevant OS information, as seen from your Python distribution.

One of the most common reasons people want to check their OS is for terminal compatibility and if certain system commands are available. Unfortunately, the success of this checking is somewhat dependent on your python installation and OS. For example, uname is not available on most Windows python packages. The above python program will show you the output of the most commonly used built-in functions, already provided by os, sys, platform, site.

https://i.stack.imgur.com/3PfPS.png

So the best way to get only the essential code is looking at that as an example. (I guess I could have just pasted it here, but that would not have been politically correct.)

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I am late to the game but, just in case anybody needs it, this a function I use to make adjustments on my code so it runs on Windows, Linux and MacOs:

import sys
def get_os(osoptions={'linux':'linux','Windows':'win','macos':'darwin'}):
    '''
    get OS to allow code specifics
    '''   
    opsys = [k for k in osoptions.keys() if sys.platform.lower().find(osoptions[k].lower()) != -1]
    try:
        return opsys[0]
    except:
        return 'unknown_OS'

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