To combine stderr
and stdout
into the stdout
stream, we append this to a command:
2>&1
e.g. to see the first few errors from compiling g++ main.cpp
:
g++ main.cpp 2>&1 | head
What does 2>&1
mean, in detail?
2>&1
than 2>/dev/null ;-)
|&
is shorthand for 2>&1 |
if you're using zsh. I can't speak to whether that applies to other bourne-like shells or if it's a zsh only feature.
File descriptor 1 is the standard output (stdout
).
File descriptor 2 is the standard error (stderr
).
At first, 2>1
may look like a good way to redirect stderr
to stdout
. However, it will actually be interpreted as "redirect stderr
to a file named 1
".
&
indicates that what follows and precedes is a file descriptor, and not a filename. Thus, we use 2>&1
. Consider >&
to be a redirect merger operator.
To redirect stdout to file.txt
:
echo test > file.txt
This is equivalent to:
echo test 1> file.txt
To redirect stderr to file.txt
:
echo test 2> file.txt
So >&
is the syntax to redirect a stream to another file descriptor:
0 is stdin
1 is stdout
2 is stderr
To redirect stdout to stderr:
echo test 1>&2 # equivalently, echo test >&2
To redirect stderr to stdout:
echo test 2>&1
Thus, in 2>&1
:
2> redirects stderr to an (unspecified) file.
&1 redirects stderr to stdout.
java ... 2&1 >> data.log
, I saw one of my colleague did this?
cmd 2>&1 >> somefile.log
will append stdout/stderr to a file - it's basically the same as above, with >> file
to append
cmd 2>&1 >>file
does not redirect stderr to the file, but cmd >> file 2>&1
does. Order matters. In the first case, stderr is redirected to the stdout of the shell (possibly a tty if the command is entered interactively), and then stdout is directed to the file. In the second case, stdout is directed to the file, and then stderr is directed to the same place.
0(or 1,2)>&0(or 1,2)
like an option to control the output? Is echo test >test.log 2>&1
same as echo test 2>&1 >test.log
?
Some tricks about redirection
Some syntax particularity about this may have important behaviours. There is some little samples about redirections, STDERR
, STDOUT
, and arguments ordering.
1 - Overwriting or appending?
Symbol >
means redirection.
> means send to as a whole completed file, overwriting target if exist (see noclobber bash feature at #3 later).
>> means send in addition to would append to target if exist.
In any case, the file would be created if they not exist.
2 - The shell command line is order dependent!!
For testing this, we need a simple command which will send something on both outputs:
$ ls -ld /tmp /tnt
ls: cannot access /tnt: No such file or directory
drwxrwxrwt 118 root root 196608 Jan 7 11:49 /tmp
$ ls -ld /tmp /tnt >/dev/null
ls: cannot access /tnt: No such file or directory
$ ls -ld /tmp /tnt 2>/dev/null
drwxrwxrwt 118 root root 196608 Jan 7 11:49 /tmp
(Expecting you don't have a directory named /tnt
, of course ;). Well, we have it!!
So, let's see:
$ ls -ld /tmp /tnt >/dev/null
ls: cannot access /tnt: No such file or directory
$ ls -ld /tmp /tnt >/dev/null 2>&1
$ ls -ld /tmp /tnt 2>&1 >/dev/null
ls: cannot access /tnt: No such file or directory
The last command line dumps STDERR
to the console, and it seem not to be the expected behaviour... But...
If you want to make some post filtering about standard output, error output or both:
$ ls -ld /tmp /tnt | sed 's/^.*$/<-- & --->/'
ls: cannot access /tnt: No such file or directory
<-- drwxrwxrwt 118 root root 196608 Jan 7 12:02 /tmp --->
$ ls -ld /tmp /tnt 2>&1 | sed 's/^.*$/<-- & --->/'
<-- ls: cannot access /tnt: No such file or directory --->
<-- drwxrwxrwt 118 root root 196608 Jan 7 12:02 /tmp --->
$ ls -ld /tmp /tnt >/dev/null | sed 's/^.*$/<-- & --->/'
ls: cannot access /tnt: No such file or directory
$ ls -ld /tmp /tnt >/dev/null 2>&1 | sed 's/^.*$/<-- & --->/'
$ ls -ld /tmp /tnt 2>&1 >/dev/null | sed 's/^.*$/<-- & --->/'
<-- ls: cannot access /tnt: No such file or directory --->
Notice that the last command line in this paragraph is exactly same as in previous paragraph, where I wrote seem not to be the expected behaviour (so, this could even be an expected behaviour).
Well, there is a little tricks about redirections, for doing different operation on both outputs:
$ ( ls -ld /tmp /tnt | sed 's/^/O: /' >&9 ) 9>&2 2>&1 | sed 's/^/E: /'
O: drwxrwxrwt 118 root root 196608 Jan 7 12:13 /tmp
E: ls: cannot access /tnt: No such file or directory
Note: &9
descriptor would occur spontaneously because of ) 9>&2
.
Addendum: nota! With the new version of bash (>4.0
) there is a new feature and more sexy syntax for doing this kind of things:
$ ls -ld /tmp /tnt 2> >(sed 's/^/E: /') > >(sed 's/^/O: /')
O: drwxrwxrwt 17 root root 28672 Nov 5 23:00 /tmp
E: ls: cannot access /tnt: No such file or directory
And finally for such a cascading output formatting:
$ ((ls -ld /tmp /tnt |sed 's/^/O: /' >&9 ) 2>&1 |sed 's/^/E: /') 9>&1| cat -n
1 O: drwxrwxrwt 118 root root 196608 Jan 7 12:29 /tmp
2 E: ls: cannot access /tnt: No such file or directory
Addendum: nota! Same new syntax, in both ways:
$ cat -n <(ls -ld /tmp /tnt 2> >(sed 's/^/E: /') > >(sed 's/^/O: /'))
1 O: drwxrwxrwt 17 root root 28672 Nov 5 23:00 /tmp
2 E: ls: cannot access /tnt: No such file or directory
Where STDOUT
go through a specific filter, STDERR
to another and finally both outputs merged go through a third command filter.
2b - Using |& instead
Syntax command |& ...
could be used as an alias for command 2>&1 | ...
. Same rules about command line order applies. More details at What is the meaning of operator |& in bash?
3 - A word about noclobber option and >| syntax
That's about overwriting:
While set -o noclobber
instruct bash to not overwrite any existing file, the >|
syntax let you pass through this limitation:
$ testfile=$(mktemp /tmp/testNoClobberDate-XXXXXX)
$ date > $testfile ; cat $testfile
Mon Jan 7 13:18:15 CET 2013
$ date > $testfile ; cat $testfile
Mon Jan 7 13:18:19 CET 2013
$ date > $testfile ; cat $testfile
Mon Jan 7 13:18:21 CET 2013
The file is overwritten each time, well now:
$ set -o noclobber
$ date > $testfile ; cat $testfile
bash: /tmp/testNoClobberDate-WW1xi9: cannot overwrite existing file
Mon Jan 7 13:18:21 CET 2013
$ date > $testfile ; cat $testfile
bash: /tmp/testNoClobberDate-WW1xi9: cannot overwrite existing file
Mon Jan 7 13:18:21 CET 2013
Pass through with >|
:
$ date >| $testfile ; cat $testfile
Mon Jan 7 13:18:58 CET 2013
$ date >| $testfile ; cat $testfile
Mon Jan 7 13:19:01 CET 2013
Unsetting this option and/or inquiring if already set.
$ set -o | grep noclobber
noclobber on
$ set +o noclobber
$ set -o | grep noclobber
noclobber off
$ date > $testfile ; cat $testfile
Mon Jan 7 13:24:27 CET 2013
$ rm $testfile
4 - Last trick and more...
For redirecting both output from a given command, we see that a right syntax could be:
$ ls -ld /tmp /tnt >/dev/null 2>&1
for this special case, there is a shortcut syntax: &>
... or >&
$ ls -ld /tmp /tnt &>/dev/null
$ ls -ld /tmp /tnt >&/dev/null
Nota: if 2>&1
exist, 1>&2
is a correct syntax too:
$ ls -ld /tmp /tnt 2>/dev/null 1>&2
4b- Now, I will let you think about:
$ ls -ld /tmp /tnt 2>&1 1>&2 | sed -e s/^/++/
++/bin/ls: cannot access /tnt: No such file or directory
++drwxrwxrwt 193 root root 196608 Feb 9 11:08 /tmp/
$ ls -ld /tmp /tnt 1>&2 2>&1 | sed -e s/^/++/
/bin/ls: cannot access /tnt: No such file or directory
drwxrwxrwt 193 root root 196608 Feb 9 11:08 /tmp/
4c- If you're interested in more information
You could read the fine manual by hitting:
man -Len -Pless\ +/^REDIRECTION bash
in a bash console ;-)
I found this brilliant post on redirection: All about redirections
Redirect both standard output and standard error to a file
$ command &>file
This one-liner uses the &>
operator to redirect both output streams - stdout and stderr - from command to file. This is Bash's shortcut for quickly redirecting both streams to the same destination.
Here is how the file descriptor table looks like after Bash has redirected both streams:
https://i.stack.imgur.com/huKF2.png
As you can see, both stdout and stderr now point to file
. So anything written to stdout and stderr gets written to file
.
There are several ways to redirect both streams to the same destination. You can redirect each stream one after another:
$ command >file 2>&1
This is a much more common way to redirect both streams to a file. First stdout is redirected to file, and then stderr is duplicated to be the same as stdout. So both streams end up pointing to file
.
When Bash sees several redirections it processes them from left to right. Let's go through the steps and see how that happens. Before running any commands, Bash's file descriptor table looks like this:
https://i.stack.imgur.com/1gsdY.png
Now Bash processes the first redirection >file. We've seen this before and it makes stdout point to file:
https://i.stack.imgur.com/Ls39g.png
Next Bash sees the second redirection 2>&1. We haven't seen this redirection before. This one duplicates file descriptor 2 to be a copy of file descriptor 1 and we get:
https://i.stack.imgur.com/KnuSt.png
Both streams have been redirected to file.
However be careful here! Writing
command >file 2>&1
is not the same as writing:
$ command 2>&1 >file
The order of redirects matters in Bash! This command redirects only the standard output to the file. The stderr will still print to the terminal. To understand why that happens, let's go through the steps again. So before running the command, the file descriptor table looks like this:
https://i.stack.imgur.com/OYgDd.png
Now Bash processes redirections left to right. It first sees 2>&1 so it duplicates stderr to stdout. The file descriptor table becomes:
https://i.stack.imgur.com/Jef1c.png
Now Bash sees the second redirect, >file
, and it redirects stdout to file:
https://i.stack.imgur.com/LR04L.png
Do you see what happens here? Stdout now points to file, but the stderr still points to the terminal! Everything that gets written to stderr still gets printed out to the screen! So be very, very careful with the order of redirects!
Also note that in Bash, writing
$ command &>file
is exactly the same as:
$ command >&file
>&
/dev/tty0
?
The numbers refer to the file descriptors (fd).
Zero is stdin
One is stdout
Two is stderr
2>&1
redirects fd 2 to 1.
This works for any number of file descriptors if the program uses them.
You can look at /usr/include/unistd.h
if you forget them:
/* Standard file descriptors. */
#define STDIN_FILENO 0 /* Standard input. */
#define STDOUT_FILENO 1 /* Standard output. */
#define STDERR_FILENO 2 /* Standard error output. */
That said I have written C tools that use non-standard file descriptors for custom logging so you don't see it unless you redirect it to a file or something.
That construct sends the standard error stream (stderr
) to the current location of standard output (stdout
) - this currency issue appears to have been neglected by the other answers.
You can redirect any output handle to another by using this method but it's most often used to channel stdout
and stderr
streams into a single stream for processing.
Some examples are:
# Look for ERROR string in both stdout and stderr.
foo 2>&1 | grep ERROR
# Run the less pager without stderr screwing up the output.
foo 2>&1 | less
# Send stdout/err to file (with append) and terminal.
foo 2>&1 |tee /dev/tty >>outfile
# Send stderr to normal location and stdout to file.
foo >outfile1 2>&1 >outfile2
Note that that last one will not direct stderr
to outfile2
- it redirects it to what stdout
was when the argument was encountered (outfile1
) and then redirects stdout
to outfile2
.
This allows some pretty sophisticated trickery.
some_program 2>&1 > /dev/null
does not work like this: some_program > /dev/null 2>&1
.
I found this very helpful if you are a beginner read this
Update:
In Linux or Unix System there are two places programs send output to: Standard output (stdout) and Standard Error (stderr).You can redirect these output to any file.
Like if you do this ls -a > output.txt
Nothing will be printed in console all output (stdout) is redirected to output file.
And if you try print the content of any file that does not exits means output will be an error like if you print test.txt that not present in current directory
cat test.txt > error.txt
Output will be
cat: test.txt :No such file or directory
But error.txt file will be empty because we redirecting the stdout to a file not stderr.
so we need file descriptor( A file descriptor is nothing more than a positive integer that represents an open file. You can say descriptor is unique id of file) to tell shell which type of output we are sending to file .In Unix /Linux system 1 is for stdout and 2 for stderr.
so now if you do this
ls -a 1> output.txt
means you are sending Standard output (stdout) to output.txt.
and if you do this cat test.txt 2> error.txt
means you are sending Standard Error (stderr) to error.txt .
&1
is used to reference the value of the file descriptor 1 (stdout).
Now to the point 2>&1
means “Redirect the stderr to the same place we are redirecting the stdout”
Now you can do this
<br
cat maybefile.txt > output.txt 2>&1
both Standard output (stdout) and Standard Error (stderr) will redirected to output.txt.
Thanks to Ondrej K. for pointing out
2>1
2>&1
is a POSIX shell construct. Here is a breakdown, token by token:
2
: "Standard error" output file descriptor.
>&
: Duplicate an Output File Descriptor operator (a variant of Output Redirection operator >
). Given [x]>&[y]
, the file descriptor denoted by x
is made to be a copy of the output file descriptor y
.
1
"Standard output" output file descriptor.
The expression 2>&1
copies file descriptor 1
to location 2
, so any output written to 2
("standard error") in the execution environment goes to the same file originally described by 1
("standard output").
Further explanation:
File Descriptor: "A per-process unique, non-negative integer used to identify an open file for the purpose of file access."
Standard output/error: Refer to the following note in the Redirection section of the shell documentation:
Open files are represented by decimal numbers starting with zero. The largest possible value is implementation-defined; however, all implementations shall support at least 0 to 9, inclusive, for use by the application. These numbers are called "file descriptors". The values 0, 1, and 2 have special meaning and conventional uses and are implied by certain redirection operations; they are referred to as standard input, standard output, and standard error, respectively. Programs usually take their input from standard input, and write output on standard output. Error messages are usually written on standard error. The redirection operators can be preceded by one or more digits (with no intervening characters allowed) to designate the file descriptor number.
2 is the console standard error.
1 is the console standard output.
This is the standard Unix, and Windows also follows the POSIX.
E.g. when you run
perl test.pl 2>&1
the standard error is redirected to standard output, so you can see both outputs together:
perl test.pl > debug.log 2>&1
After execution, you can see all the output, including errors, in the debug.log.
perl test.pl 1>out.log 2>err.log
Then standard output goes to out.log, and standard error to err.log.
I suggest you to try to understand these.
perl test.pl > debug.log 2>&1
To answer your question: It takes any error output (normally sent to stderr) and writes it to standard output (stdout).
This is helpful with, for example 'more' when you need paging for all output. Some programs like printing usage information into stderr.
To help you remember
1 = standard output (where programs print normal output)
2 = standard error (where programs print errors)
"2>&1" simply points everything sent to stderr, to stdout instead.
I also recommend reading this post on error redirecting where this subject is covered in full detail.
From a programmer's point of view, it means precisely this:
dup2(1, 2);
See the man page.
Understanding that 2>&1
is a copy also explains why ...
command >file 2>&1
... is not the same as ...
command 2>&1 >file
The first will send both streams to file
, whereas the second will send errors to stdout
, and ordinary output into file
.
People, always remember paxdiablo's hint about the current location of the redirection target... It is important.
My personal mnemonic for the 2>&1
operator is this:
Think of & as meaning 'and' or 'add' (the character is an ampers-and, isn't it?)
So it becomes: 'redirect 2 (stderr) to where 1 (stdout) already/currently is and add both streams'.
The same mnemonic works for the other frequently used redirection too, 1>&2
:
Think of & meaning and or add... (you get the idea about the ampersand, yes?)
So it becomes: 'redirect 1 (stdout) to where 2 (stderr) already/currently is and add both streams'.
And always remember: you have to read chains of redirections 'from the end', from right to left (not from left to right).
Redirecting Input Redirection of input causes the file whose name results from the expansion of word to be opened for reading on file descriptor n, or the standard input (file descriptor 0) if n is not specified. The general format for redirecting input is: [n]
Ref:
man bash
Type /^REDIRECT
to locate to the redirection
section, and learn more...
An online version is here: 3.6 Redirections
PS:
Lots of the time, man
was the powerful tool to learn Linux.
Provided that /foo
does not exist on your system and /tmp
does…
$ ls -l /tmp /foo
will print the contents of /tmp
and print an error message for /foo
$ ls -l /tmp /foo > /dev/null
will send the contents of /tmp
to /dev/null
and print an error message for /foo
$ ls -l /tmp /foo 1> /dev/null
will do exactly the same (note the 1)
$ ls -l /tmp /foo 2> /dev/null
will print the contents of /tmp
and send the error message to /dev/null
$ ls -l /tmp /foo 1> /dev/null 2> /dev/null
will send both the listing as well as the error message to /dev/null
$ ls -l /tmp /foo > /dev/null 2> &1
is shorthand
unix_commands 2>&1
This is used to print errors to the terminal.
When errors are produced, they are written to the "standard error" buffer at memory address &2, and 2 references and streams from that buffer.
When outputs are produced, they are written to the "standard output" buffer at memory address &1, and 1 references and streams from that buffer.
So going back to the command. Anytime the program unix_commands
produces an error, it writes that into the errors buffer. So we create a pointer to that buffer 2
, and redirect >
the errors into the outputs buffer &1
. At this point we're done, because anything in the outputs buffer is read and printed by the terminal.
This is just like passing the error to the stdout or the terminal.
That is, cmd
is not a command:
$cmd 2>filename
cat filename
command not found
The error is sent to the file like this:
2>&1
Standard error is sent to the terminal.
0 for input, 1 for stdout and 2 for stderr.
One Tip: somecmd >1.txt 2>&1
is correct, while somecmd 2>&1 >1.txt
is totally wrong with no effect!
You need to understand this in terms of pipe.
$ (whoami;ZZZ) 2>&1 | cat
logan
ZZZ: command not found
As you can see both stdout and stderr of LHS of pipe is fed into the RHS (of pipe).
This is the same as
$ (whoami;ZZZ) |& cat
logan
ZZZ: command not found
Note that 1>&2
cannot be used interchangeably with 2>&1
.
Imagine your command depends on piping, for example:
docker logs 1b3e97c49e39 2>&1 | grep "some log"
grepping will happen across both stderr
and stdout
since stderr
is basically merged into stdout
.
However, if you try:
docker logs 1b3e97c49e39 1>&2 | grep "some log"
,
grepping will not really search anywhere at all because Unix pipe is connecting processes via connecting stdout | stdin
, and stdout
in the second case was redirected to stderr
in which Unix pipe has no interest.
Success story sharing
&2>&1
?&
is only interpreted to mean "file descriptor" in the context of redirections. Writingcommand &2>&
is parsed ascommand &
and2>&1
, i.e. "runcommand
in the background, then run the command2
and redirect its stdout into its stdout".2>'&1'