Copy array by value

Use this:

let oldArray = [1, 2, 3, 4, 5]; let newArray = oldArray.slice(); console.log({newArray});

Basically, the slice() operation clones the array and returns a reference to a new array.

Also note that:

For references, strings and numbers (and not the actual object), slice() copies object references into the new array. Both the original and new array refer to the same object. If a referenced object changes, the changes are visible to both the new and original arrays.

Primitives such as strings and numbers are immutable, so changes to the string or number are impossible.

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In Javascript, deep-copy techniques depend on the elements in an array. Let's start there.

Three types of elements

Elements can be: literal values, literal structures, or prototypes.

// Literal values (type1)
const booleanLiteral = true;
const numberLiteral = 1;
const stringLiteral = 'true';

// Literal structures (type2)
const arrayLiteral = [];
const objectLiteral = {};

// Prototypes (type3)
const booleanPrototype = new Bool(true);
const numberPrototype = new Number(1);
const stringPrototype = new String('true');
const arrayPrototype = new Array();
const objectPrototype = new Object(); // or `new function () {}

From these elements we can create three types of arrays.

// 1) Array of literal-values (boolean, number, string) 
const type1 = [ true, 1, "true" ];

// 2) Array of literal-structures (array, object)
const type2 = [ [], {} ];

// 3) Array of prototype-objects (function)
const type3 = [ function () {}, function () {} ];

Deep copy techniques depend on the three array types

Based on the types of elements in the array, we can use various techniques to deep copy.

Deep copy techniques

https://i.stack.imgur.com/UL33O.png

Benchmarks

https://www.measurethat.net/Benchmarks/Show/17502/0/deep-copy-comparison

Array of literal-values (type1) The [ ...myArray ], myArray.splice(0), myArray.slice(), and myArray.concat() techniques can be used to deep copy arrays with literal values (boolean, number, and string) only; where slice() has the highest performance in Chrome, and spread ... has the highest performance in Firefox.

Array of literal-values (type1) and literal-structures (type2) The JSON.parse(JSON.stringify(myArray)) technique can be used to deep copy literal values (boolean, number, string) and literal structures (array, object), but not prototype objects.

All arrays (type1, type2, type3) The Lo-dash cloneDeep(myArray) or jQuery extend(true, [], myArray) techniques can be used to deep-copy all array-types. Where the Lodash cloneDeep() technique has the highest performance. And for those who avoid third-party libraries, the custom function below will deep-copy all array-types, with lower performance than cloneDeep() and higher performance than extend(true).

The Lo-dash cloneDeep(myArray) or jQuery extend(true, [], myArray) techniques can be used to deep-copy all array-types. Where the Lodash cloneDeep() technique has the highest performance.

And for those who avoid third-party libraries, the custom function below will deep-copy all array-types, with lower performance than cloneDeep() and higher performance than extend(true).

function copy(aObject) {
  // Prevent undefined objects
  // if (!aObject) return aObject;

  let bObject = Array.isArray(aObject) ? [] : {};

  let value;
  for (const key in aObject) {

    // Prevent self-references to parent object
    // if (Object.is(aObject[key], aObject)) continue;
    
    value = aObject[key];

    bObject[key] = (typeof value === "object") ? copy(value) : value;
  }

  return bObject;
}

So to answer the question...

Question

var arr1 = ['a','b','c'];
var arr2 = arr1;

I realized that arr2 refers to the same array as arr1, rather than a new, independent array. How can I copy the array to get two independent arrays?

Answer

Because arr1 is an array of literal values (boolean, number, or string), you can use any deep copy technique discussed above, where slice() and spread ... have the highest performance.

arr2 = arr1.slice();
arr2 = [...arr1];
arr2 = arr1.splice(0);
arr2 = arr1.concat();
arr2 = JSON.parse(JSON.stringify(arr1));
arr2 = copy(arr1); // Custom function needed, and provided above
arr2 = _.cloneDeep(arr1); // Lo-dash.js needed
arr2 = jQuery.extend(true, [], arr1); // jQuery.js needed

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You can use array spreads ... to copy arrays.

const itemsCopy = [...items];

Also if want to create a new array with the existing one being part of it:

var parts = ['shoulders', 'knees'];
var lyrics = ['head', ...parts, 'and', 'toes'];

Array spreads are now supported in all major browsers but if you need older support use typescript or babel and compile to ES5.

More info on spreads

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No jQuery needed... Working Example

var arr2 = arr1.slice()

This copys the array from the starting position 0 through the end of the array.

It is important to note that it will work as expected for primitive types (string, number, etc.), and to also explain the expected behavior for reference types...

If you have an array of Reference types, say of type Object. The array will be copied, but both of the arrays will contain references to the same Object's. So in this case it would seem like the array is copied by reference even though the array is actually copied.

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This is how I've done it after trying many approaches:

var newArray = JSON.parse(JSON.stringify(orgArray));

This will create a new deep copy not related to the first one (not a shallow copy).

Also this obviously will not clone events and functions, but the good thing you can do it in one line, and it can be used for any kind of object (arrays, strings, numbers, objects ...)

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An alternative to slice is concat, which can be used in 2 ways. The first of these is perhaps more readable as the intended behaviour is very clear:

var array2 = [].concat(array1);

The second method is:

var array2 = array1.concat();

Cohen (in the comments) pointed out that this latter method has better performance.

The way this works is that the concat method creates a new array consisting of the elements in the object on which it is called followed by the elements of any arrays passed to it as arguments. So when no arguments are passed, it simply copies the array.

Lee Penkman, also in the comments, points out that if there's a chance array1 is undefined, you can return an empty array as follows:

var array2 = [].concat(array1 || []);

Or, for the second method:

var array2 = (array1 || []).concat();

Note that you can also do this with slice: var array2 = (array1 || []).slice();.

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Important!

Most of answers here works for particular cases.

If you don't care about deep/nested objects and props use (ES6):

let clonedArray = [...array]

but if you want to do deep clone use this instead:

let cloneArray = JSON.parse(JSON.stringify(array))*

*functions won't be preserved (serialized) while using stringify, you will get result without them.

For lodash users:

let clonedArray = _.clone(array) documentation

and

let clonedArray = _.cloneDeep(array) documentation

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I personally think Array.from is a more readable solution. By the way, just beware of its browser support.

// clone let x = [1, 2, 3]; let y = Array.from(x); console.log({y}); // deep clone let clone = arr => Array.from(arr, item => Array.isArray(item) ? clone(item) : item); x = [1, [], [[]]]; y = clone(x); console.log({y});

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Some of mentioned methods work well when working with simple data types like number or string, but when the array contains other objects these methods fail. When we try to pass any object from one array to another it is passed as a reference, not the object.

Add the following code in your JavaScript file:

Object.prototype.clone = function() {
    var newObj = (this instanceof Array) ? [] : {};
    for (i in this) {
        if (i == 'clone') 
            continue;
        if (this[i] && typeof this[i] == "object") {
            newObj[i] = this[i].clone();
        } 
        else 
            newObj[i] = this[i]
    } return newObj;
};

And simply use

var arr1 = ['val_1','val_2','val_3'];
var arr2 = arr1.clone()

It will work.

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From ES2015,

var arr2 = [...arr1];

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If you are in an environment of ECMAScript 6, using the Spread Operator you could do it this way:

var arr1 = ['a','b','c']; var arr2 = [...arr1]; //copy arr1 arr2.push('d'); console.log(arr1) console.log(arr2)

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Primitive values are always pass by its value (copied). Compound values however are passed by reference.

So how do we copy this arr?

let arr = [1,2,3,4,5];

Copy an Array in ES6

let arrCopy = [...arr]; 

Copy n Array in ES5

let arrCopy = arr.slice(); 
let arrCopy = [].concat(arr);

Why `let arrCopy = arr` is not passing by value?

Passing one varible to another on Compound values such as Object/Array behave difrently. Using asign operator on copand values we pass reference to an object. This is why the value of both arrays are changing when removing/adding arr elements.

Exceptions:

arrCopy[1] = 'adding new value this way will unreference';

When you assign a new value to the variable, you are changing the reference itself and it doesn’t affect the original Object/Array.

read more

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Adding to the solution of array.slice(); be aware that if you have multidimensional array sub-arrays will be copied by references. What you can do is to loop and slice() each sub-array individually

var arr = [[1,1,1],[2,2,2],[3,3,3]];
var arr2 = arr.slice();

arr2[0][1] = 55;
console.log(arr2[0][1]);
console.log(arr[0][1]);

function arrCpy(arrSrc, arrDis){
 for(elm in arrSrc){
  arrDis.push(arrSrc[elm].slice());
}
}

var arr3=[];
arrCpy(arr,arr3);

arr3[1][1] = 77;

console.log(arr3[1][1]);
console.log(arr[1][1]);

same things goes to array of objects, they will be copied by reference, you have to copy them manually

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let a = [1,2,3];

Now you can do any one of the following to make a copy of an array.

let b = Array.from(a); 

OR

let b = [...a];

OR

let b = new Array(...a); 

OR

let b = a.slice(); 

OR

let b = a.map(e => e);

Now, if i change a,

a.push(5); 

Then, a is [1,2,3,5] but b is still [1,2,3] as it has different reference.

But i think, in all the methods above Array.from is better and made mainly to copy an array.

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I would personally prefer this way:

JSON.parse(JSON.stringify( originalObject ));

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You must use best practice for this question when there are a lot of answers.

I recommend to you use array spreads … to copy arrays.

var arr1 = ['a','b','c'];

var arr2 = […arr1];

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As we know in Javascript arrays and objects are by reference, but what ways we can do copy the array without changing the original array later one?

Here are few ways to do it:

Imagine we have this array in your code:

var arr = [1, 2, 3, 4, 5];

1) Looping through the array in a function and return a new array, like this:

 function newArr(arr) {
      var i=0, res = [];
      while(i<arr.length){
       res.push(arr[i]);
        i++;
       }
   return res;
 }

2) Using slice method, slice is for slicing part of the array, it will slice some part of your array without touching the original, in the slice, if don't specify the start and end of the array, it will slice the whole array and basically make a full copy of the array, so we can easily say:

var arr2 = arr.slice(); // make a copy of the original array

3) Also contact method, this is for merging two array, but we can just specify one of arrays and then this basically make a copy of the values in the new contacted array:

var arr2 = arr.concat();

4) Also stringify and parse method, it's not recommended, but can be an easy way to copy Array and Objects:

var arr2 = JSON.parse(JSON.stringify(arr));

5) Array.from method, this is not widely supported, before use check the support in different browsers:

const arr2 = Array.from(arr);

6) ECMA6 way, also not fully supported, but babelJs can help you if you want to transpile:

const arr2 = [...arr];

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Dan, no need to use fancy tricks. All you need to do is make copy of arr1 by doing this.

var arr1 = ['a','b','c']; var arr2 = []; var arr2 = new Array(arr1); arr2.push('d'); // Now, arr2 = [['a','b','c'],'d'] console.log('arr1:'); console.log(arr1); console.log('arr2:'); console.log(arr2); // Following did the trick: var arr3 = [...arr1]; arr3.push('d'); // Now, arr3 = ['a','b','c','d']; console.log('arr3:'); console.log(arr3);

Now arr1 and arr2 are two different array variables stored in separate stacks. Check this out on jsfiddle.

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In my particular case I needed to ensure the array remained intact so this worked for me:

// Empty array
arr1.length = 0;
// Add items from source array to target array
for (var i = 0; i < arr2.length; i++) {
    arr1.push(arr2[i]);
}

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Make copy of multidimensional array/object:

function deepCopy(obj) {
   if (Object.prototype.toString.call(obj) === '[object Array]') {
      var out = [], i = 0, len = obj.length;
      for ( ; i < len; i++ ) {
         out[i] = arguments.callee(obj[i]);
      }
      return out;
   }
   if (typeof obj === 'object') {
      var out = {}, i;
      for ( i in obj ) {
         out[i] = arguments.callee(obj[i]);
      }
      return out;
   }
   return obj;
}

Thanks to James Padolsey for this function.

Source: Here

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If your array contains elements of the primitive data type such as int, char, or string etc then you can user one of those methods which returns a copy of the original array such as .slice() or .map() or spread operator(thanks to ES6).

new_array = old_array.slice()

or

new_array = old_array.map((elem) => elem)

or

const new_array = new Array(...old_array);

BUT if your array contains complex elements such as objects(or arrays) or more nested objects, then, you will have to make sure that you are making a copy of all the elements from the top level to the last level else reference of the inner objects will be used and that means changing values in object_elements in new_array will still affect the old_array. You can call this method of copying at each level as making a DEEP COPY of the old_array.

For deep copying, you can use the above-mentioned methods for primitive data types at each level depending upon the type of data or you can use this costly method(mentioned below) for making a deep copy without doing much work.

var new_array = JSON.parse(JSON.stringify(old_array));

There are a lot of other methods out there which you can use depending on your requirements. I have mentioned only some of those for giving a general idea of what happens when we try to copy an array into the other by value.

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If you want to make a new copy of an object or array, you must explicitly copy the properties of the object or the elements of the array, for example:

var arr1 = ['a','b','c'];
var arr2 = [];

for (var i=0; i < arr1.length; i++) {
   arr2[i] = arr1[i];
}

You can search for more information on Google about immutable primitive values and mutable object references.

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You could use ES6 with spread Opeartor, its simpler.

arr2 = [...arr1];

There are limitations..check docs Spread syntax @ mozilla

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When we want to copy an array using the assignment operator ( = ) it doesn't create a copy it merely copies the pointer/reference to the array. For example:

const oldArr = [1,2,3]; const newArr = oldArr; // now oldArr points to the same place in memory console.log(oldArr === newArr); // Points to the same place in memory thus is true const copy = [1,2,3]; console.log(copy === newArr); // Doesn't point to the same place in memory and thus is false

Often when we transform data we want to keep our initial datastructure (e.g. Array) intact. We do this by making a exact copy of our array so this one can be transformed while the initial one stays intact.

Ways of copying an array:

const oldArr = [1,2,3]; // Uses the spread operator to spread out old values into the new array literal const newArr1 = [...oldArr]; // Slice with no arguments returns the newly copied Array const newArr2 = oldArr.slice(); // Map applies the callback to every element in the array and returns a new array const newArr3 = oldArr.map((el) => el); // Concat is used to merge arrays and returns a new array. Concat with no args copies an array const newArr4 = oldArr.concat(); // Object.assign can be used to transfer all the properties into a new array literal const newArr5 = Object.assign([], oldArr); // Creating via the Array constructor using the new keyword const newArr6 = new Array(...oldArr); // For loop function clone(base) { const newArray = []; for(let i= 0; i < base.length; i++) { newArray[i] = base[i]; } return newArray; } const newArr7 = clone(oldArr); console.log(newArr1, newArr2, newArr3, newArr4, newArr5, newArr6, newArr7);

Be careful when arrays or objects are nested!:

When arrays are nested the values are copied by reference. Here is an example of how this could lead to issues:

let arr1 = [1,2,[1,2,3]] let arr2 = [...arr1]; arr2[2][0] = 5; // we change arr2 console.log(arr1); // arr1 is also changed because the array inside arr1 was copied by reference

So don't use these methods when there are objects or arrays inside your array you want to copy. i.e. Use these methods on arrays of primitives only.

If you do want to deepclone a javascript array use JSON.parse in conjunction with JSON.stringify, like this:

let arr1 = [1,2,[1,2,3]] let arr2 = JSON.parse(JSON.stringify(arr1)) ; arr2[2][0] = 5; console.log(arr1); // now I'm not modified because I'm a deep clone

Performance of copying:

So which one do we choose for optimal performance. It turns out that the most verbose method, the for loop has the highest performance. Use the for loop for really CPU intensive copying (large/many arrays).

After that the .slice() method also has decent performance and is also less verbose and easier for the programmer to implement. I suggest to use .slice() for your everyday copying of arrays which aren't very CPU intensive. Also avoid using the JSON.parse(JSON.stringify(arr)) (lots of overhead) if no deep clone is required and performance is an issue.

Source performance test

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var arr2 = arr1.slice(0);

This way just work for simple Arrays.

If you have Complex Array like array of Objects then you must use another solutions like:

const arr2 = JSON.parse(JSON.stringify(arr1)); 

For example, we have an array of objects that each cell have another array field in its object ... in this situation if we use slice method then the array fields will copy by Ref and that's mean these fields updates will affect on orginal array same element and fields.

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Using jQuery deep copy could be made as following:

var arr2 = $.extend(true, [], arr1);

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You can also use ES6 spread operator to copy Array

var arr=[2,3,4,5];
var copyArr=[...arr];

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Here are few more way to copy:

const array = [1,2,3,4]; const arrayCopy1 = Object.values(array); const arrayCopy2 = Object.assign([], array); const arrayCopy3 = array.map(i => i); const arrayCopy4 = Array.of(...array );

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For ES6 array containing objects

cloneArray(arr) {
    return arr.map(x => ({ ...x }));
}

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Quick Examples:

If elements in the array are primitive types (string, number, etc.)

var arr1 = ['a','b','c']; // arr1 and arr2 are independent and primitive elements are stored in // different places in the memory var arr2 = arr1.slice(); arr2.push('d'); console.log(arr1); // [ 'a', 'b', 'c' ] console.log(arr2); // [ 'a', 'b', 'c', 'd' ]

If elements in the array are object literals, another array ({}, [])

var arr1 = [{ x: 'a', y: 'b'}, [1, 2], [3, 4]]; // arr1 and arr2 are independent and reference's/addresses are stored in different // places in the memory. But those reference's/addresses points to some common place // in the memory. var arr2 = arr1.slice(); arr2.pop(); // OK - don't affect arr1 bcos only the address in the arr2 is // deleted not the data pointed by that address arr2[0].x = 'z'; // not OK - affect arr1 bcos changes made in the common area // pointed by the addresses in both arr1 and arr2 arr2[1][0] = 9; // not OK - same above reason console.log(arr1); // [ { x: 'z', y: 'b' }, [ 9, 2 ], [ 3, 4 ] ] console.log(arr2); // [ { x: 'z', y: 'b' }, [ 9, 2 ] ]

Solution for 2: Deep Copy by element by element

var arr1 = [{ x: 'a', y: 'b'}, [1, 2], [3, 4]]; arr2 = JSON.parse(JSON.stringify(arr1)); arr2.pop(); // OK - don't affect arr1 arr2[0].x = 'z'; // OK - don't affect arr1 arr2[1][0] = 9; // OK - don't affect arr1 console.log(arr1); // [ { x: 'a', y: 'b' }, [ 1, 2 ], [ 3, 4 ] ] console.log(arr2); // [ { x: 'z', y: 'b' }, [ 9, 2 ] ]

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